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The angle of elevation from a point 30 metre from the base of tree as level ground to the top of the tree is 60°. The height of the tree is : 
  • a)
    60√3 m
  • b)
    30√3 m
  • c)
    30 m
  • d)
    30/√3 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The angle of elevation from a point 30 metre from the base of tree as ...
Angle of elevation is 60
Base = 30m
Height of the tree = Perpendicular
So in the right triangle
Where base is given and we have to find perpendicular we have only tan θ
So, Tan θ = P/B
Tan 60 = P/30
√30 = P/30
P = 30√30
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Community Answer
The angle of elevation from a point 30 metre from the base of tree as ...
Angle of elevation is 60
Base = 30m
Height of the tree = Perpendicular
So in the right triangle
Where base is given and we have to find perpendicular we have only tan θ
So, Tan θ = P/B
Tan 60 = P/30
√30 = P/30
P = 30√30
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The angle of elevation from a point 30 metre from the base of tree as level ground to the top of the tree is 60°. The height of the tree is :a)60√3mb)30√3mc)30 md)30/√3mCorrect answer is option 'B'. Can you explain this answer?
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