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The coordination number and the oxidation state of element E in the complex [E(en)2(C2O4)]NO2
are,respectively
  • a)
    6 and 3
  • b)
    6 and 2
  • c)
    4 and 2
  • d)
    4 and 3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The coordination number and the oxidation state of element E in the co...
In the given complex [E(en)2(C2O4)]+NO2- ethylene diamine is a bidentate ligand and (C2O42–) oxalate ion is also bidentate ligand.

Therefore, cooordination number of the complex is 6 i.e., it is an octahedral complex.

Oxidation number of E in the given complex is

x + 2 x 0 + 1 x (–2) = +1

x = 3

The correct option is A.
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The coordination number and the oxidation state of element E in the complex [E(en)2(C2O4)]NO2are,respectivelya)6 and 3b)6 and 2c)4 and 2d)4 and 3Correct answer is option 'A'. Can you explain this answer?
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