Number of metal-metal bond in [Re2Cl4(PPhMe2)4] is?Correct answer is '...
Explanation:
The given compound is [Re2Cl4(PPhMe2)4], which contains two rhenium atoms, four chloride ions, and eight phosphine ligands. The metal-metal bond refers to the bond between the two rhenium atoms.
1. Determining the oxidation state of rhenium
Each chloride ion has a -1 charge, and each phosphine ligand has a neutral charge. Let x be the oxidation state of rhenium. Then:
2(-1) + 4(0) + 4(0) + 2x = 0
-2 + 2x = 0
2x = 2
x = +1
Therefore, each rhenium atom has a +1 oxidation state.
2. Determining the electronic configuration of rhenium
The electronic configuration of rhenium in the +1 oxidation state is [Xe] 4f14 5d5. Each rhenium atom has one unpaired electron in the 5d orbital.
3. Determining the bonding in [Re2Cl4(PPhMe2)4]
The compound has a dimeric structure, with each rhenium atom bonded to four phosphine ligands and two chloride ions. The chloride ions bridge the two rhenium atoms, forming a Re-Cl-Re bridge. The phosphine ligands are coordinated to each rhenium atom, forming a tetrahedral geometry.
The metal-metal bond arises from the overlap of the 5d orbitals on the two rhenium atoms. The two unpaired electrons in the 5d orbital of each rhenium atom can form a bond, resulting in a quadruple bond between the two rhenium atoms.
Therefore, there are three metal-metal bonds in [Re2Cl4(PPhMe2)4].
Number of metal-metal bond in [Re2Cl4(PPhMe2)4] is?Correct answer is '...
Total valence electrons= 7×2+1×4+2×4
14+4+8
26 electrons
number of metal metal bond=. n×18- total valence electrons divided by 2. where n is the number of metal present.
2×18-26/2
=36-26/2
=10/2
=5 metal metal bond