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Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?
Correct answer is between '2.9,3.1'. Can you explain this answer?
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Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.0...
∆Tf= i × Kf × m
0.02046 = i × 1.86 × 0.01
i = 1.1
CH3COOH = CH3COO- + H+
i= 1+ alpha
1.1 = 1+ alpha
alpha = .1
[H+] = C alpha
[H+] = 0.01 × .1
[H+] = 0.001
pH = - log[H+]
pH = - log [ 0.001]
pH = 3
0.02046 = i × 1.86 × 0.01
i = 1.1
CH3COOH = CH3COO- + H+
i= 1+ alpha
1.1 = 1+ alpha
alpha = .1
[H+] = C alpha
[H+] = 0.01 × .1
[H+] = 0.001
pH = - log[H+]
pH = - log [ 0.001]
pH = 3
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Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.0...
The depression of freezing point is given by the formula:
ΔTf = Kf × molality
where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent (water), and molality is the molality of the solute (CH3COOH) in the solution.
We are given that the depression of freezing point is 0.02046, and we can assume that the freezing point depression constant for water is 1.86 °C/m. Therefore, we can rearrange the formula to solve for the molality:
molality = ΔTf / Kf
molality = 0.02046 / 1.86
molality = 0.011
Therefore, the molality of the CH3COOH solution is 0.011 mol/kg.
ΔTf = Kf × molality
where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent (water), and molality is the molality of the solute (CH3COOH) in the solution.
We are given that the depression of freezing point is 0.02046, and we can assume that the freezing point depression constant for water is 1.86 °C/m. Therefore, we can rearrange the formula to solve for the molality:
molality = ΔTf / Kf
molality = 0.02046 / 1.86
molality = 0.011
Therefore, the molality of the CH3COOH solution is 0.011 mol/kg.
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Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer?
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Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer?.
Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer?.
Solutions for Depression of freezing point of 0.01 molal aq. CH3COOH solution is 0.02046°. 1 molal urea solution freezes at – 1.86°C. Assuming molality equal to molarity, pH (rounded up to first decimal place) of CH3COOH solution is?Correct answer is between '2.9,3.1'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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