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Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:
- a)124 × 10–4 S m2 mol–1
- b)1240 × 10–4 S m2 mol–1
- c)1.24 × 10–4 S m2 mol–1
- d)12.4 × 10–4 S m2 mol–1
Correct answer is option 'A'. Can you explain this answer?
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Resistance of a conductivity cell filled with a solution of an electro...
Solution:
Given, the resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm and the conductivity of this solution is 1.29 S m-1.
Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm.
The molar conductivity of 0.02 M solution of electrolyte would be:
We know that the resistance of a conductivity cell is given by the equation:
R = (1/k) x [(l/A)]
where, R = Resistance of the conductivity cell, k = Conductivity of the solution, l = Distance between the electrodes, and A = Area of cross-section of the electrodes.
Let's assume that the distance between the electrodes and the area of cross-section of the electrodes are constant in both cases.
So, we can write:
R1/R2 = k2/k1
where, R1 = Resistance of the conductivity cell filled with 0.1 M solution of electrolyte and R2 = Resistance of the same cell filled with 0.02 M solution of electrolyte.
Substituting the given values, we get:
100/520 = k2/1.29
k2 = (100/520) x 1.29
k2 = 0.24867 S m-1
Now, we can use the equation for molar conductivity:
Λm = k x (1/c)
where, Λm = Molar conductivity, k = Conductivity of the solution, and c = Concentration of the solution.
Substituting the values, we get:
Λm = 0.24867 x (1/0.02)
Λm = 12.4335 S m2 mol-1
Rounding off to two significant figures, we get:
Λm = 12.4 x 104 S m2 mol-1
Therefore, the correct option is A) 124 x 104 S m2 mol-1.
Given, the resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm and the conductivity of this solution is 1.29 S m-1.
Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm.
The molar conductivity of 0.02 M solution of electrolyte would be:
We know that the resistance of a conductivity cell is given by the equation:
R = (1/k) x [(l/A)]
where, R = Resistance of the conductivity cell, k = Conductivity of the solution, l = Distance between the electrodes, and A = Area of cross-section of the electrodes.
Let's assume that the distance between the electrodes and the area of cross-section of the electrodes are constant in both cases.
So, we can write:
R1/R2 = k2/k1
where, R1 = Resistance of the conductivity cell filled with 0.1 M solution of electrolyte and R2 = Resistance of the same cell filled with 0.02 M solution of electrolyte.
Substituting the given values, we get:
100/520 = k2/1.29
k2 = (100/520) x 1.29
k2 = 0.24867 S m-1
Now, we can use the equation for molar conductivity:
Λm = k x (1/c)
where, Λm = Molar conductivity, k = Conductivity of the solution, and c = Concentration of the solution.
Substituting the values, we get:
Λm = 0.24867 x (1/0.02)
Λm = 12.4335 S m2 mol-1
Rounding off to two significant figures, we get:
Λm = 12.4 x 104 S m2 mol-1
Therefore, the correct option is A) 124 x 104 S m2 mol-1.
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Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer?
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Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer?.
Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer?.
Solutions for Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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ample number of questions to practice Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S m–1. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:a)124 × 10–4 S m2 mol–1b)1240 × 10–4 S m2 mol–1c)1.24 × 10–4 S m2 mol–1d)12.4 × 10–4 S m2 mol–1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Chemistry tests.
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