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What is the increase of volume per unit volume of thin-walled steel cylinder closed at both ends and subjected to a uniform internal pressure of 0.5 MPa. The wall thickness is 1.5 mm, the radius 350 mm and Poisson’s ratio are 0.33. Consider Young’s Modulus of elasticity as 200 GPa.a)1.07 × 10-3b)1.07 × 10-2c)0.54 × 10-3d)0.54 × 10-2Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared
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the Mechanical Engineering exam syllabus. Information about What is the increase of volume per unit volume of thin-walled steel cylinder closed at both ends and subjected to a uniform internal pressure of 0.5 MPa. The wall thickness is 1.5 mm, the radius 350 mm and Poisson’s ratio are 0.33. Consider Young’s Modulus of elasticity as 200 GPa.a)1.07 × 10-3b)1.07 × 10-2c)0.54 × 10-3d)0.54 × 10-2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam.
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What is the increase of volume per unit volume of thin-walled steel cylinder closed at both ends and subjected to a uniform internal pressure of 0.5 MPa. The wall thickness is 1.5 mm, the radius 350 mm and Poisson’s ratio are 0.33. Consider Young’s Modulus of elasticity as 200 GPa.a)1.07 × 10-3b)1.07 × 10-2c)0.54 × 10-3d)0.54 × 10-2Correct answer is option 'A'. Can you explain this answer?, a detailed solution for What is the increase of volume per unit volume of thin-walled steel cylinder closed at both ends and subjected to a uniform internal pressure of 0.5 MPa. The wall thickness is 1.5 mm, the radius 350 mm and Poisson’s ratio are 0.33. Consider Young’s Modulus of elasticity as 200 GPa.a)1.07 × 10-3b)1.07 × 10-2c)0.54 × 10-3d)0.54 × 10-2Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of What is the increase of volume per unit volume of thin-walled steel cylinder closed at both ends and subjected to a uniform internal pressure of 0.5 MPa. The wall thickness is 1.5 mm, the radius 350 mm and Poisson’s ratio are 0.33. Consider Young’s Modulus of elasticity as 200 GPa.a)1.07 × 10-3b)1.07 × 10-2c)0.54 × 10-3d)0.54 × 10-2Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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