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Calculate the resistivity of n-type semiconductor from the following data, Density of holes = 5 x 1012 cm-3. Density of electrons = 8 x 1013 cm-3, mobility of conduction electron = 2.3 x 104 cm2/ V-sec and mobility of holes = 100 cm2/V-sec.
  • a)
    0.43 Ω-m
  • b)
    0.34 Ω-m
  • c)
    0.42 Ω-m
  • d)
    0.24 Ω-m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Calculate the resistivity of n-type semiconductor from the following d...
Resistivity(
r
) = .
σ = e(neue + nnun).
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Most Upvoted Answer
Calculate the resistivity of n-type semiconductor from the following d...
To calculate the resistivity of an n-type semiconductor, we can use the formula:

ρ = 1 / (q * (μn * p + μp * n))

Where:
ρ is the resistivity
q is the charge of an electron (1.6 x 10^-19 C)
μn is the mobility of conduction electrons
μp is the mobility of holes
n is the density of electrons
p is the density of holes

Given data:
Density of holes (p) = 5 x 10^12 cm^-3
Density of electrons (n) = 8 x 10^13 cm^-3
Mobility of conduction electron (μn) = 2.3 x 10^4 cm^2/V-sec
Mobility of holes (μp) = 100 cm^2/V-sec

1. Calculate the value of ρ using the given formula:

ρ = 1 / (q * (μn * p + μp * n))
= 1 / (1.6 x 10^-19 C * ((2.3 x 10^4 cm^2/V-sec * 5 x 10^12 cm^-3) + (100 cm^2/V-sec * 8 x 10^13 cm^-3)))

2. Simplify the expression inside the parentheses:

(2.3 x 10^4 cm^2/V-sec * 5 x 10^12 cm^-3) + (100 cm^2/V-sec * 8 x 10^13 cm^-3)
= (1.15 x 10^17 cm^-1/sec) + (8 x 10^15 cm^-1/sec)
= 1.23 x 10^17 cm^-1/sec

3. Substitute this value back into the formula:

ρ = 1 / (1.6 x 10^-19 C * 1.23 x 10^17 cm^-1/sec)

4. Calculate the value of ρ:

ρ = 1 / (1.6 x 10^-19 C * 1.23 x 10^17 cm^-1/sec)
≈ 0.34 Ω-m

Therefore, the resistivity of the n-type semiconductor is approximately 0.34 Ω-m.
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Calculate the resistivity of n-type semiconductor from the following data, Density of holes = 5 x 1012 cm-3. Density of electrons = 8 x 1013 cm-3, mobility of conduction electron = 2.3 x 104 cm2/ V-sec and mobility of holes = 100 cm2/V-sec.a)0.43 Ω-mb)0.34 Ω-mc)0.42 Ω-md)0.24 Ω-mCorrect answer is option 'B'. Can you explain this answer?
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