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There are certain 2-digit numbers. The difference between the number and the one obtained on reversing it is always 27. How many such maximum 2-digit numbers are there?
  • a)
    3
  • b)
    4
  • c)
    5
  • d)
    None of the above
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
There are certain 2-digit numbers. The difference between the number a...
Required numbers = (14, 41), (25, 52), (36, 63), (47, 74), (58, 85), (69, 96) 
OR, 
Let number = 10x + y 
Obtain number after reversing = 10y + x 
Now, 
(10x + y) – (10y + x) = 27 
⇒ 9x – 9y = 27 
⇒ x – y = 3 
Now we can put, y = 1, 2, 3, 4, 5 
and 6 and x = 4, 5, 6, 7, 8 and 9 
On doing this, we got more than five numbers. Hence, the correct option is (d).
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Most Upvoted Answer
There are certain 2-digit numbers. The difference between the number a...
Solution:

Let the number be xy, where x and y are digits.

The number can be written as 10x+y, and the reversed number can be written as 10y+x.

The difference between the two numbers is:

(10x+y)-(10y+x) = 9x-9y = 9(x-y)

Given that the difference is 27, we have:

9(x-y) = 27

Simplifying, we get:

x-y = 3

This means that the digits differ by 3.

We need to find maximum 2-digit numbers that satisfy this condition.

Let us list all such numbers:

- 12 (21)
- 23 (32)
- 34 (43)
- 45 (54)
- 56 (65)
- 67 (76)
- 78 (87)
- 89 (98)

Thus, there are no such maximum 2-digit numbers that satisfy the condition. Hence, the correct answer is option D.
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There are certain 2-digit numbers. The difference between the number and the one obtained on reversing it is always 27. How many such maximum 2-digit numbers are there?a)3b)4c)5d)None of the aboveCorrect answer is option 'D'. Can you explain this answer?
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