A sum amounts to Rs. 9680 in 2 years and to Rs. 10648 in 3 years respe...
Amount = P[ (1+r)^n ]
9680 = P [ (1+r)^2 ] -(eq 1)
10648 = P [ (1+r)^3 ] -(eq 2)
On dividing eq 1 by eq 2 , we get
1210/1331 = 1/(1+r)
1210+1210r = 1331
r = 121/1210
r = 1/10. (means rate = 10%)
Putting value of r in any of the eqns ,we get
P = 8000
For , 1 2/5 yrs or 7/5 yrs -
A = 8000 [ (1+1/10) ^ (7/5) ]
A = 8000 [ (1.1) ^ (1.4) ]
A = 8000*1.14274
A = 9141.9
So , A = Rs. 9142 (approx.)
I didn't got the exact ans but its closest to option b).
A sum amounts to Rs. 9680 in 2 years and to Rs. 10648 in 3 years respe...
To solve this problem, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the final amount (the sum after interest)
P = the principal amount (the initial sum)
r = the annual interest rate (as a decimal)
n = the number of times that interest is compounded per year
t = the number of years
Let's solve this problem step by step:
1. Find the principal amount:
From the given information, we know that the sum amounts to Rs. 9680 in 2 years and Rs. 10648 in 3 years.
Using the compound interest formula, we can set up the following equations:
9680 = P(1 + r/n)^(2n)
10648 = P(1 + r/n)^(3n)
2. Solve for P:
We have two equations and two unknowns (P and r/n). We can solve these equations simultaneously to find the value of P.
Dividing the second equation by the first equation, we get:
10648/9680 = (P(1 + r/n)^(3n))/(P(1 + r/n)^(2n))
1.09917 = (1 + r/n)^n
Now, let's make some simplifications:
Let's assume n = 1 (compounded annually) for simplicity.
1.09917 = (1 + r)^1
Simplifying further:
1.09917 = 1 + r
r = 0.09917
Now, substitute the value of r into either of the equations to solve for P. Let's use the first equation:
9680 = P(1 + 0.09917/1)^(1*2)
Simplifying further:
9680 = P(1.09917)^2
9680 = P(1.20825)
P = 9680/1.20825
P ≈ 8006.31
So, the principal amount is approximately Rs. 8006.31.
3. Calculate the amount for 1 2/5 years:
Now, we need to find the amount if the same sum is invested for 1 2/5 years at the same rate of compound interest.
Using the compound interest formula:
A = P(1 + r/n)^(nt)
A = 8006.31(1 + 0.09917/1)^(1*7/5) (as 1 2/5 years is equivalent to 7/5 years)
Simplifying further:
A = 8006.31(1.09917)^(7/5)
A ≈ 8006.31(1.09917)^1.4
A ≈ 8006.31(1.2178)
A ≈ 9761.22
Therefore, the amount if the same sum is invested for 1 2/5 years at the same rate of compound interest will be approximately Rs. 9761.22.
Therefore, the correct answer is option B: Rs. 9150.