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If one zero of (a^2 9)x 13x 6a is the reciprocal of other then find a?
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If one zero of (a^2 9)x 13x 6a is the reciprocal of other then find a...
We have,
F(x) =( a^2 9) x 13 x 6a =0
Let one zero be @ and other be 1/@

:. Product of zeroes = 1/@ *@= 1
=>constant term/coefficient of x ^2 =1
=> 6a/ a^2 9 =1
=>6a= a^2 9
=>a^2 - 6a + 9 =0
=>a^2 - 3a - 3a + 9 =0
=>a(a - 3) - 3( a- 3) =0
=> a-3 =0 a - 3 =0
=>a= 3 or a= 3

Hence the value of a is 3..
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If one zero of (a^2 9)x 13x 6a is the reciprocal of other then find a?
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