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1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed?
Verified Answer
?1. You are given that the diameter of the eyeball is about 2.3 cm and...
Given:
When object is at infinity:u=-∞
V=2.3cm( given)
By lens formula:1/f=1/v-1/u
1/fmax=1/2.3+1/∞
=1/2.3 +0
=1/2.3
fmax=2.3cm
Therefore when object is at Infinity , the parallel rays from object makes the ciliary muscles relaxed and focal length has its maximum value which is equal to its distance from retina=2.3cm
When an eye is focussed on a closer object, the ciliary muscles are strained and focal length of eye lens decreases.
here u=-25cm
v=2.3cm
f=?
1\f=1/v-1/u
1/fmin=1/2.3+1/25
=10/23 +1/25
=250+23/23x25
=273/575
fmin=575/273=2.1
If the position of an object is between Infinity and the point of least distance of distinct vision then eye lens adjust's its focal length in between 2.3cm to 2.1cm
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?1. You are given that the diameter of the eyeball is about 2.3 cm and...
Eye Lens Power when Ciliary Muscles are Fully Relaxed:
The power of the eye lens can be determined using the lens formula:
1/f = 1/v - 1/u
Where:
- f is the focal length of the lens
- v is the image distance (distance of the image formed by the lens from the lens itself)
- u is the object distance (distance of the object from the lens)
In the case of a normal eye, the ciliary muscles are relaxed, and the eye lens is in its least convex state. This means that the focal length of the eye lens is at its maximum value.
Focal Length:
The focal length of a lens can be determined using the lens-maker's formula:
1/f = (n - 1) * [(1/R1) - (1/R2)]
Where:
- n is the refractive index of the lens material
- R1 and R2 are the radii of curvature of the lens surfaces
In the case of the eye lens, the refractive index of the lens material is constant and the radii of curvature of the lens surfaces do not change significantly when the ciliary muscles are relaxed.
Power of the Eye Lens:
The power of a lens is given by the reciprocal of its focal length:
Power (P) = 1/f
Calculation:
Given that the diameter of the eyeball is about 2.3 cm, we can assume the radius of curvature of the lens surfaces to be approximately half of the diameter (1.15 cm).
Using the lens-maker's formula and the given values, we can calculate the focal length of the eye lens when the ciliary muscles are fully relaxed.
Substituting the values into the lens-maker's formula:
1/f = (n - 1) * [(1/R1) - (1/R2)]
1/f = (n - 1) * [(1/1.15) - (1/1.15)]
1/f = 0
This implies that the focal length of the eye lens is infinity when the ciliary muscles are fully relaxed.
Therefore, the power of the eye lens when the ciliary muscles are fully relaxed is 0 diopters (D).
Explanation:
When the ciliary muscles are fully relaxed, the eye lens is in its least convex state, resulting in an infinite focal length. This means that the eye can focus on objects situated at infinity with the help of the relaxed eye lens. The power of the eye lens in this state is 0 D, indicating that no additional focusing power is required to see objects at different distances.
The power of the eye lens can be determined using the lens formula:
1/f = 1/v - 1/u
Where:
- f is the focal length of the lens
- v is the image distance (distance of the image formed by the lens from the lens itself)
- u is the object distance (distance of the object from the lens)
In the case of a normal eye, the ciliary muscles are relaxed, and the eye lens is in its least convex state. This means that the focal length of the eye lens is at its maximum value.
Focal Length:
The focal length of a lens can be determined using the lens-maker's formula:
1/f = (n - 1) * [(1/R1) - (1/R2)]
Where:
- n is the refractive index of the lens material
- R1 and R2 are the radii of curvature of the lens surfaces
In the case of the eye lens, the refractive index of the lens material is constant and the radii of curvature of the lens surfaces do not change significantly when the ciliary muscles are relaxed.
Power of the Eye Lens:
The power of a lens is given by the reciprocal of its focal length:
Power (P) = 1/f
Calculation:
Given that the diameter of the eyeball is about 2.3 cm, we can assume the radius of curvature of the lens surfaces to be approximately half of the diameter (1.15 cm).
Using the lens-maker's formula and the given values, we can calculate the focal length of the eye lens when the ciliary muscles are fully relaxed.
Substituting the values into the lens-maker's formula:
1/f = (n - 1) * [(1/R1) - (1/R2)]
1/f = (n - 1) * [(1/1.15) - (1/1.15)]
1/f = 0
This implies that the focal length of the eye lens is infinity when the ciliary muscles are fully relaxed.
Therefore, the power of the eye lens when the ciliary muscles are fully relaxed is 0 diopters (D).
Explanation:
When the ciliary muscles are fully relaxed, the eye lens is in its least convex state, resulting in an infinite focal length. This means that the eye can focus on objects situated at infinity with the help of the relaxed eye lens. The power of the eye lens in this state is 0 D, indicating that no additional focusing power is required to see objects at different distances.
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?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed?
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?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about ?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed?.
?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about ?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed?.
Solutions for ?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed? in English & in Hindi are available as part of our courses for Class 10.
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?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed?, a detailed solution for ?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed? has been provided alongside types of ?1. You are given that the diameter of the eyeball is about 2.3 cm and a normal eye can adjust the focal length of its eye lens to see objects situated anywhere from 25 cm to an infinite distance away from it. (a) What is the power of the (normal) eye lens, when ciliary muscles are fully relaxed? theory, EduRev gives you an
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