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The voltage across the secondary of the transformer in a half wave rectifier with a shunt capacitor filter is 50 volts. The maximum voltage that will occur on the reverse biased diode will be
- a)100 V
- b)88 V
- c)50 V
- d)25 V
Correct answer is option 'A'. Can you explain this answer?
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The voltage across the secondary of the transformer in a half wave rec...
Explanation:
In a half wave rectifier with a shunt capacitor filter, the capacitor is connected in parallel with the load resistor. The capacitor gets charged during the positive half cycle of the input AC voltage and discharges during the negative half cycle. This helps in smoothing out the output voltage.
Maximum Voltage across Capacitor:
During the positive half cycle of the input AC voltage, the diode conducts and the voltage across the secondary of the transformer appears across the load resistor and capacitor. Therefore, the voltage across the capacitor will be equal to the peak voltage of the secondary of the transformer, which is given as 50 V.
Minimum Voltage across Capacitor:
During the negative half cycle of the input AC voltage, the diode is reverse biased and does not conduct. The capacitor discharges through the load resistor during this time. The minimum voltage across the capacitor will be equal to the voltage obtained by subtracting the forward voltage drop of the diode from the peak voltage of the secondary of the transformer. This is given as:
Vmin = Vp - Vf
where,
Vp = Peak voltage of secondary of transformer (50 V)
Vf = Forward voltage drop of diode (0.7 V)
Vmin = 50 - 0.7 = 49.3 V
Maximum Voltage across Diode:
During the negative half cycle of the input AC voltage, the diode is reverse biased and does not conduct. The maximum voltage that will occur on the reverse biased diode will be equal to the maximum voltage across the capacitor, which is 50 V.
Therefore, the correct option is A) 100 V, which is twice the maximum voltage across the capacitor.
In a half wave rectifier with a shunt capacitor filter, the capacitor is connected in parallel with the load resistor. The capacitor gets charged during the positive half cycle of the input AC voltage and discharges during the negative half cycle. This helps in smoothing out the output voltage.
Maximum Voltage across Capacitor:
During the positive half cycle of the input AC voltage, the diode conducts and the voltage across the secondary of the transformer appears across the load resistor and capacitor. Therefore, the voltage across the capacitor will be equal to the peak voltage of the secondary of the transformer, which is given as 50 V.
Minimum Voltage across Capacitor:
During the negative half cycle of the input AC voltage, the diode is reverse biased and does not conduct. The capacitor discharges through the load resistor during this time. The minimum voltage across the capacitor will be equal to the voltage obtained by subtracting the forward voltage drop of the diode from the peak voltage of the secondary of the transformer. This is given as:
Vmin = Vp - Vf
where,
Vp = Peak voltage of secondary of transformer (50 V)
Vf = Forward voltage drop of diode (0.7 V)
Vmin = 50 - 0.7 = 49.3 V
Maximum Voltage across Diode:
During the negative half cycle of the input AC voltage, the diode is reverse biased and does not conduct. The maximum voltage that will occur on the reverse biased diode will be equal to the maximum voltage across the capacitor, which is 50 V.
Therefore, the correct option is A) 100 V, which is twice the maximum voltage across the capacitor.
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The voltage across the secondary of the transformer in a half wave rec...
Capacitor charges to 2*Vs
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