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Find the sum of all natural no. Upto 1000 which are neither divisible by 2 nor by 5
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Find the sum of all natural no. Upto 1000 which are neither divisible ...
Understanding the Problem
To find the sum of all natural numbers up to 1000 that are neither divisible by 2 nor by 5, we first need to identify the numbers that meet this condition.
Identifying Eligible Numbers
- Natural Numbers: These are the counting numbers starting from 1.
- Divisibility Conditions: A number is excluded if it is divisible by:
- 2 (even numbers)
- 5 (multiples of 5)
Finding the Range
- The natural numbers we are considering range from 1 to 1000.
Finding Eligible Numbers
- The eligible numbers are those that are:
- Odd (not divisible by 2)
- Not ending in 0 or 5 (not divisible by 5)
This leaves us with numbers that are odd and end with 1, 3, 7, or 9.
Counting Eligible Numbers
- Total odd numbers up to 1000: There are 500 odd numbers (1, 3, 5, ..., 999).
- Odd numbers divisible by 5: These are 5, 15, 25, ..., 995. The largest odd multiple of 5 less than 1000 is 995, which gives us 100 terms (5n where n=1 to 100).
- Eligible Odd Numbers Count: 500 (total odd numbers) - 100 (odd multiples of 5) = 400 eligible numbers.
Calculating the Sum
To find the sum of these eligible numbers:
- Consider the arithmetic sequence: 1, 3, 7, 9, ..., up to 999.
- The sum of an arithmetic series can be calculated using the formula:
- Sum = n/2 * (first term + last term)
- Here, n = 400, first term = 1, last term = 999.
The final sum gives us the desired total of all natural numbers up to 1000 that are neither divisible by 2 nor by 5.
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Find the sum of all natural no. Upto 1000 which are neither divisible ...
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