Born Haber Cycle Class 11 Notes | EduRev

Chemistry for JEE

Class 11 : Born Haber Cycle Class 11 Notes | EduRev

The document Born Haber Cycle Class 11 Notes | EduRev is a part of the Class 11 Course Chemistry for JEE.
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BORN HABER CYCLE
Ionisation Energy: The minimum amount of energy required to remove one electron form the outermost shell of an isolated gaseous atom is called ionization energy of the element.

Electron affinity: Amount of energy released when an extra electron is added to an isolated gaseous atom.

Lattice Energy: Amount of energy released when 1 mole of gaseous cation and 1 mole gaseous anion combine to each other and form 1 mole of ionic compound is called lattice energy.
Na (g) + Cl-(g) → NaCl(s) + heat
                             (Lattice energy)

Born Haber Cycle Class 11 Notes | EduRev

Example: Calculate the standard enthalpy change for a reaction CO2(g) + H2(g) → CO(g) +H2O (g) given that ΔHf0 for CO2(g), CO(g) and H2O(g) as -393.5, -110.5 and -241.8 KJ/mol respectively.
(a) -31.2 KJ 
(b) - 21.2 KJ 
(c) -11.2 KJ 
(d) 41.2KJ
Ans. (d)
Solution.
ΔHº= SΔHfº(products) - SΔHfº(Reactants)

Born Haber Cycle Class 11 Notes | EduRev
ΔHº = [-241.8 - 110.5] - [-393.5 0]
= - 352.3 393.5 = 41.2 KJ

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