Chapter 40 : Electromagnetic Waves - HC Verma Solution, Physics Class 11 Notes | EduRev

Physics Class 11

JEE : Chapter 40 : Electromagnetic Waves - HC Verma Solution, Physics Class 11 Notes | EduRev

 Page 1


40.1
ELECTROMAGNETIC WAVES
CHAPTER - 40
1.
0 E 0
2
0
d EA
dt dt 4 r
? ? ?
?
? ?
= 
1 3 4 2 1 1 2
1 3 2 2
M L T A A T L
T M L A L
? ?
? ?
? ? = A
1
= (Current) (proved).
2. E = 
2
Kq
x
, [from coulomb’s law]
?
E
= EA = 
2
KqA
x
I
d
= 
2
0 0 0
2
d E d kqA d
KqA x
dt dt dt x
?
?
? ?? ?? ?
= 
3
0
3
0
1 dx qAv
q A 2 x
4 dt 2 x
?
? ? ? ? ? ? ? ? ?
? ? ?
. ?
3. E = 
0
Q
A ?
(Electric field)
? = E.A. = 
0 0
Q A Q
A 2 2
?
? ?
i
0
= 
E
0 0
0
d d Q 1 dQ
dt dt 2 2 dt
? ? ? ? ?
? ?? ?
? ?
? ?
? ? ?
? ?
? ??
0
td
RE t /RC t /RC
1 d 1 1 E
(ECe ) EC e e
2 dt 2 RC 2R
?
? ? ?
?
? ? ? ?
4. E = 
0
Q
A ?
(Electric field)
? = E.A. = 
0 0
Q A Q
A 2 2
?
? ?
i
0
= 
E
0 0
0
d d Q 1 dQ
dt dt 2 2 dt
? ? ? ? ?
? ?? ?
? ?
? ?
? ? ?
? ?
5. B = ?
0
H
? H = 
0
B
?
0 0 0 0
0 0 0 0
E B /( C) 1
H B / C
? ?
? ?
? ?
= 
12 8
1
8.85 10 3 10
?
? ? ?
= 376.6 ??= 377 ?.
Dimension 
1 1 3 4 2 1 2 3 2
0
1 1 1
C [LT ][M L T A ] M L T A
? ? ? ? ?
? ?
?
= M
1
L
2
T
–3
A
–2
= [R].
6. E
0
= 810 V/m, B
0
= ?
We know, B
0
= ?
0
?
0
C E
0
Putting the values,
B
0
= 4 ? ? 10
–7
? 8.85 ? 10
–12
? 3 ? 10
8
? 810
= 27010.9 ? 10
–10
= 2.7 ? 10
–6
T = 2.7 ?T. ?
Page 2


40.1
ELECTROMAGNETIC WAVES
CHAPTER - 40
1.
0 E 0
2
0
d EA
dt dt 4 r
? ? ?
?
? ?
= 
1 3 4 2 1 1 2
1 3 2 2
M L T A A T L
T M L A L
? ?
? ?
? ? = A
1
= (Current) (proved).
2. E = 
2
Kq
x
, [from coulomb’s law]
?
E
= EA = 
2
KqA
x
I
d
= 
2
0 0 0
2
d E d kqA d
KqA x
dt dt dt x
?
?
? ?? ?? ?
= 
3
0
3
0
1 dx qAv
q A 2 x
4 dt 2 x
?
? ? ? ? ? ? ? ? ?
? ? ?
. ?
3. E = 
0
Q
A ?
(Electric field)
? = E.A. = 
0 0
Q A Q
A 2 2
?
? ?
i
0
= 
E
0 0
0
d d Q 1 dQ
dt dt 2 2 dt
? ? ? ? ?
? ?? ?
? ?
? ?
? ? ?
? ?
? ??
0
td
RE t /RC t /RC
1 d 1 1 E
(ECe ) EC e e
2 dt 2 RC 2R
?
? ? ?
?
? ? ? ?
4. E = 
0
Q
A ?
(Electric field)
? = E.A. = 
0 0
Q A Q
A 2 2
?
? ?
i
0
= 
E
0 0
0
d d Q 1 dQ
dt dt 2 2 dt
? ? ? ? ?
? ?? ?
? ?
? ?
? ? ?
? ?
5. B = ?
0
H
? H = 
0
B
?
0 0 0 0
0 0 0 0
E B /( C) 1
H B / C
? ?
? ?
? ?
= 
12 8
1
8.85 10 3 10
?
? ? ?
= 376.6 ??= 377 ?.
Dimension 
1 1 3 4 2 1 2 3 2
0
1 1 1
C [LT ][M L T A ] M L T A
? ? ? ? ?
? ?
?
= M
1
L
2
T
–3
A
–2
= [R].
6. E
0
= 810 V/m, B
0
= ?
We know, B
0
= ?
0
?
0
C E
0
Putting the values,
B
0
= 4 ? ? 10
–7
? 8.85 ? 10
–12
? 3 ? 10
8
? 810
= 27010.9 ? 10
–10
= 2.7 ? 10
–6
T = 2.7 ?T. ?
Electromagnetic Waves
40.2
7. B = (200 ?T) Sin [(4 ? 10
15
5
–1
) (t – x/C)]
a) B
0
= 200 ?T
E
0
= C ? B
0
= 200 ? 10
–6
? 3 ? 10
8
= 6 ? 10
4
b) Average energy density = 
6 2
2
0
7
0
1 (200 10 )
B
2 2 4 10
?
?
?
?
? ? ? ?
= 
8
7
4 10 1
20 8 10
?
?
?
?
? ? ?
= 0.0159 = 0.016. ?
8. I = 2.5 ? 10
14
W/m
2
We know, I = 
2
0 0
1
E C
2
?
?
2
0
E = 
I
0
2
C ?
or E
0
= 
I
0
2
C ?
E
0
= 
14
12 8
2 2.5 10
8.85 10 3 10
?
? ?
? ? ?
= 0.4339 ? 10
9
= 4.33 ? 10
8
N/c.
B
0
= ?
0
?
0
C E
0
= 4 ? 3.14 ? 10
–7
? 8.854 ? 10
–12
? 3 ? 10
8
? 4.33 ? 10
8
= 1.44 T. 
9. Intensity of wave = 
2
0 0
1
E C
2
?
?
0
= 8.85 ? 10
–12
; E
0
= ? ; C = 3 ? 10
8
, I = 1380 W/m
2
1380 = 1/2 ? 8.85 ? 10
–12
?
2
0
E ? 3 ? 10
8
?
2
0
E = 
4
2 1380
8.85 3 10
?
?
? ?
= 103.95 ? 10
4
? E
0
= 10.195 ? 10
2
= 1.02 ? 10
3
E
0
= B
0
C
? B
0
= E
0
/C = 
3
8
1.02 10
3 10
?
?
= 3.398 ? 10
–5
= 3.4 ? 10
–5
T.
? ? ?
Read More
Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Complete Syllabus of JEE

JEE

Dynamic Test

Content Category

Related Searches

Important questions

,

Physics Class 11 Notes | EduRev

,

Semester Notes

,

pdf

,

Extra Questions

,

Objective type Questions

,

Physics Class 11 Notes | EduRev

,

Previous Year Questions with Solutions

,

ppt

,

Physics Class 11 Notes | EduRev

,

past year papers

,

MCQs

,

Viva Questions

,

Chapter 40 : Electromagnetic Waves - HC Verma Solution

,

video lectures

,

Chapter 40 : Electromagnetic Waves - HC Verma Solution

,

practice quizzes

,

shortcuts and tricks

,

Summary

,

Sample Paper

,

mock tests for examination

,

Chapter 40 : Electromagnetic Waves - HC Verma Solution

,

Exam

,

study material

,

Free

;