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Page 1 1. (b) According to spectrochemical series . 2. (b) CN – is coordinated to cobalt as the ligand and coordinated compounds have different properties than the individual species. 3. (d) [Ni X 4 ] 2– , the electronic configuration of Ni 2+ is It contains two unpaired electrons and the hybridisation is sp 3 (tetrahedral). 4. (b) The crystal field splitting in tetrahedral complexes is lower than that in octahedral complexes, and 5. (c) [Mn(CN) 6 ] 3– and [Fe(CN) 6 ] 3– are inner orbital complexes and paramagnetic while [Co(C 2 O 4 ) 3 ] 3– is diamagnetic in nature. 6. (a) Ti(C 2 H 4 ) 4 is an organometallic compound due to Ti directly attached to C- atom 7. (d) Tetraethyl lead Pb(C 2 H 5 ) 4 is not p bonded complex. It is s bonded organometallic compound 8. (a) Number of moles of the complex = = 0.01 moles Number of moles of AgCl obtained Page 2 1. (b) According to spectrochemical series . 2. (b) CN – is coordinated to cobalt as the ligand and coordinated compounds have different properties than the individual species. 3. (d) [Ni X 4 ] 2– , the electronic configuration of Ni 2+ is It contains two unpaired electrons and the hybridisation is sp 3 (tetrahedral). 4. (b) The crystal field splitting in tetrahedral complexes is lower than that in octahedral complexes, and 5. (c) [Mn(CN) 6 ] 3– and [Fe(CN) 6 ] 3– are inner orbital complexes and paramagnetic while [Co(C 2 O 4 ) 3 ] 3– is diamagnetic in nature. 6. (a) Ti(C 2 H 4 ) 4 is an organometallic compound due to Ti directly attached to C- atom 7. (d) Tetraethyl lead Pb(C 2 H 5 ) 4 is not p bonded complex. It is s bonded organometallic compound 8. (a) Number of moles of the complex = = 0.01 moles Number of moles of AgCl obtained = moles ? No. of moles of AgCl obtained = 3 × No. of moles of complex ? n = 9. (b) The chemical formula of Pentaminenitrochromium (III) chloride is It can exist in following two structures and Therefore the type of isomerism found in this compound is linkage isomerism as nitro group is linked through N as –NO 2 or through O as – ONO. 10. (c) Nickel ions are frequently detected by the formation of red precipitate of the complex of nickel dimethylglyoxime, when heated with dimethylglyoxime. Page 3 1. (b) According to spectrochemical series . 2. (b) CN – is coordinated to cobalt as the ligand and coordinated compounds have different properties than the individual species. 3. (d) [Ni X 4 ] 2– , the electronic configuration of Ni 2+ is It contains two unpaired electrons and the hybridisation is sp 3 (tetrahedral). 4. (b) The crystal field splitting in tetrahedral complexes is lower than that in octahedral complexes, and 5. (c) [Mn(CN) 6 ] 3– and [Fe(CN) 6 ] 3– are inner orbital complexes and paramagnetic while [Co(C 2 O 4 ) 3 ] 3– is diamagnetic in nature. 6. (a) Ti(C 2 H 4 ) 4 is an organometallic compound due to Ti directly attached to C- atom 7. (d) Tetraethyl lead Pb(C 2 H 5 ) 4 is not p bonded complex. It is s bonded organometallic compound 8. (a) Number of moles of the complex = = 0.01 moles Number of moles of AgCl obtained = moles ? No. of moles of AgCl obtained = 3 × No. of moles of complex ? n = 9. (b) The chemical formula of Pentaminenitrochromium (III) chloride is It can exist in following two structures and Therefore the type of isomerism found in this compound is linkage isomerism as nitro group is linked through N as –NO 2 or through O as – ONO. 10. (c) Nickel ions are frequently detected by the formation of red precipitate of the complex of nickel dimethylglyoxime, when heated with dimethylglyoxime. 11. (d) Isomers of given complexes are as follows Thus [Co(en) 2 Cl 2 ] + has large number of isomers. 12. (d) Due to some backbonding by sidewise overlapping between d- orbitals of metal and p-orbital of carbon, the F–C bond has both s and p characters. 13. (a) [PdCl 4 ] 2– is dsp 2 hybridized and square planar in shape. 14. (b) For a given metal ion, weak field ligands create a complex with smaller ?, which will absorbs light of longer ? and thus lower frequency. Conservely, stronger field ligands create a larger ?, absorb light of shorter ? and thus higher v i.e. higher energy. So order of ligand strength is L 1 < L 3 < L 2 < L 4 15. (d) 16. (c) In both states (paramagnetic and diamagnetic) of the given complex, Ni exists as Ni 2+ whose electronic configuration is [Ar] 3d 8 4s 0 . Page 4 1. (b) According to spectrochemical series . 2. (b) CN – is coordinated to cobalt as the ligand and coordinated compounds have different properties than the individual species. 3. (d) [Ni X 4 ] 2– , the electronic configuration of Ni 2+ is It contains two unpaired electrons and the hybridisation is sp 3 (tetrahedral). 4. (b) The crystal field splitting in tetrahedral complexes is lower than that in octahedral complexes, and 5. (c) [Mn(CN) 6 ] 3– and [Fe(CN) 6 ] 3– are inner orbital complexes and paramagnetic while [Co(C 2 O 4 ) 3 ] 3– is diamagnetic in nature. 6. (a) Ti(C 2 H 4 ) 4 is an organometallic compound due to Ti directly attached to C- atom 7. (d) Tetraethyl lead Pb(C 2 H 5 ) 4 is not p bonded complex. It is s bonded organometallic compound 8. (a) Number of moles of the complex = = 0.01 moles Number of moles of AgCl obtained = moles ? No. of moles of AgCl obtained = 3 × No. of moles of complex ? n = 9. (b) The chemical formula of Pentaminenitrochromium (III) chloride is It can exist in following two structures and Therefore the type of isomerism found in this compound is linkage isomerism as nitro group is linked through N as –NO 2 or through O as – ONO. 10. (c) Nickel ions are frequently detected by the formation of red precipitate of the complex of nickel dimethylglyoxime, when heated with dimethylglyoxime. 11. (d) Isomers of given complexes are as follows Thus [Co(en) 2 Cl 2 ] + has large number of isomers. 12. (d) Due to some backbonding by sidewise overlapping between d- orbitals of metal and p-orbital of carbon, the F–C bond has both s and p characters. 13. (a) [PdCl 4 ] 2– is dsp 2 hybridized and square planar in shape. 14. (b) For a given metal ion, weak field ligands create a complex with smaller ?, which will absorbs light of longer ? and thus lower frequency. Conservely, stronger field ligands create a larger ?, absorb light of shorter ? and thus higher v i.e. higher energy. So order of ligand strength is L 1 < L 3 < L 2 < L 4 15. (d) 16. (c) In both states (paramagnetic and diamagnetic) of the given complex, Ni exists as Ni 2+ whose electronic configuration is [Ar] 3d 8 4s 0 . Ni 2+ : In the above paramagnetic state the geometry of the complex is sp 3 giving tetrahedral geometry. The diamagnetic state is achieved by pairing of electrons in 3d orbital. Thus the geometry of the complex will be dsp 2 giving square planar geometry. 17. (b) (ppt) 18. (b) The correct IUPAC Name of [Mn(CN) 5 ] 2– . Pentacyanomangnate (III). 19. (c) EAN of a central metal ion = (atomic no. of central atom) – oxidation state + no. of ligands × 2 = 26 – 3 + (6× 2) = 23 + 12 = 35 20. (c) In [Co(CO) 5 NH 3 ] 2+ CO is bonded to cobalt through s and p bonding. 21. (15) [Co(NH 3 ) 5 CO 3 ]ClO 4. Six monodentate ligands are attached to Co hence C. N. of Co = 6; O. N. = x + 5 × (0) + 1 × (–2) + 1× (–1) = 0 ? x = + 3 ; electronic configuration of Co 3+ [Ar] 3d 6 4s 0 hence number of d electrons is 6. All d electrons are paired due to strong ligand hence unpaired electron is zero. The sum of C.N, O. N. No of d electron and number of uppaired d electron = 6 + 3 + 6 + 0 = 15 Page 5 1. (b) According to spectrochemical series . 2. (b) CN – is coordinated to cobalt as the ligand and coordinated compounds have different properties than the individual species. 3. (d) [Ni X 4 ] 2– , the electronic configuration of Ni 2+ is It contains two unpaired electrons and the hybridisation is sp 3 (tetrahedral). 4. (b) The crystal field splitting in tetrahedral complexes is lower than that in octahedral complexes, and 5. (c) [Mn(CN) 6 ] 3– and [Fe(CN) 6 ] 3– are inner orbital complexes and paramagnetic while [Co(C 2 O 4 ) 3 ] 3– is diamagnetic in nature. 6. (a) Ti(C 2 H 4 ) 4 is an organometallic compound due to Ti directly attached to C- atom 7. (d) Tetraethyl lead Pb(C 2 H 5 ) 4 is not p bonded complex. It is s bonded organometallic compound 8. (a) Number of moles of the complex = = 0.01 moles Number of moles of AgCl obtained = moles ? No. of moles of AgCl obtained = 3 × No. of moles of complex ? n = 9. (b) The chemical formula of Pentaminenitrochromium (III) chloride is It can exist in following two structures and Therefore the type of isomerism found in this compound is linkage isomerism as nitro group is linked through N as –NO 2 or through O as – ONO. 10. (c) Nickel ions are frequently detected by the formation of red precipitate of the complex of nickel dimethylglyoxime, when heated with dimethylglyoxime. 11. (d) Isomers of given complexes are as follows Thus [Co(en) 2 Cl 2 ] + has large number of isomers. 12. (d) Due to some backbonding by sidewise overlapping between d- orbitals of metal and p-orbital of carbon, the F–C bond has both s and p characters. 13. (a) [PdCl 4 ] 2– is dsp 2 hybridized and square planar in shape. 14. (b) For a given metal ion, weak field ligands create a complex with smaller ?, which will absorbs light of longer ? and thus lower frequency. Conservely, stronger field ligands create a larger ?, absorb light of shorter ? and thus higher v i.e. higher energy. So order of ligand strength is L 1 < L 3 < L 2 < L 4 15. (d) 16. (c) In both states (paramagnetic and diamagnetic) of the given complex, Ni exists as Ni 2+ whose electronic configuration is [Ar] 3d 8 4s 0 . Ni 2+ : In the above paramagnetic state the geometry of the complex is sp 3 giving tetrahedral geometry. The diamagnetic state is achieved by pairing of electrons in 3d orbital. Thus the geometry of the complex will be dsp 2 giving square planar geometry. 17. (b) (ppt) 18. (b) The correct IUPAC Name of [Mn(CN) 5 ] 2– . Pentacyanomangnate (III). 19. (c) EAN of a central metal ion = (atomic no. of central atom) – oxidation state + no. of ligands × 2 = 26 – 3 + (6× 2) = 23 + 12 = 35 20. (c) In [Co(CO) 5 NH 3 ] 2+ CO is bonded to cobalt through s and p bonding. 21. (15) [Co(NH 3 ) 5 CO 3 ]ClO 4. Six monodentate ligands are attached to Co hence C. N. of Co = 6; O. N. = x + 5 × (0) + 1 × (–2) + 1× (–1) = 0 ? x = + 3 ; electronic configuration of Co 3+ [Ar] 3d 6 4s 0 hence number of d electrons is 6. All d electrons are paired due to strong ligand hence unpaired electron is zero. The sum of C.N, O. N. No of d electron and number of uppaired d electron = 6 + 3 + 6 + 0 = 15 22. (1.0)EDTA has hexadentate four donor O atoms and 2 donor N atoms and for the formation of octahedral complex one molecule is required. 23. (3) [MA 6 ] No. of geometrical isomers [MA 5 B] No. of geometrical isomers Thus, 3 complexes will show geometrical isomerism. 24. (7.93) Gd (64) = [Xe] 4f 7 5d 1 6s 2 Gd 3+ = [Xe] 4f 7 5d 0 6s 0 i.e. no. of unpaired electrons = 7 = 7.93 BM 25. (3) The number of geometrical isomers is 3.Read More
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