Introductory Exercise 4.2
Ques 1: A particle is projected along an inclined plane as shown in figure. What is the speed of the particle when it collides at point A? (g = 10 m/s^{2})
Ans:
Sol: Time of flight
Using, v = u + at
v_{x} = u_{x} = u cos 60°
Ques 2: In the above problem what is the component of its velocity perpendicular to the plane when it strikes at A?
Ans: 5 m/s
Sol: Component of velocity perpendicular to plane
Ques 3: Two particles A and B are projected simultaneously from the two towers of height 10 m and 20 m respectively. Particle A is projected with an initial speed of 10√2 m/s at an angle of 45° with horizontal, while particle B is projected horizontally with speed 10 m/s. If they collide in air, what is the distance d between the towers?
Ans: 20 m
Sol: Let the particle collide at time t.
x_{1} = (u cos θ) t
and x_{2} = vt
∴ d = x_{2}  x_{1}
= (v + u cos θ) t
For vertical motion of particle 1:
i.e., …(i)
or
For the vertical motion of particle 2:
i.e., …(ii)
Comparing Eqs. (i) and (ii),
⇒ t = 1 s
∴ d = 20 m
Ques 4: Two particles A and B are projected from ground towards each other with speeds 10 m/s and 5√2 m/s at angles 30° and 45° with horizontal from two points separated by a distance of 15 m. Will they collide or not?
Ans: No
Sol: u = 10 m/s
v = 5√2 m/s
θ = 30°
φ = 45°
d = 15 m
Let the particles meet (or are in the same vertical time t).
∴ d = (u cos θ) t + (v cos φ) t
⇒ 15 = (10 cos 30° + 5√2 cos 45°) t
or
or
= 1.009 s
Now, let us find time of flight of A and B
= 1 s
As T_{A} < t, particle A will touch ground before the expected time t of collision.
∴ Ans: NO.
Ques 5: A particle is projected from the bottom of an inclined plane of inclination 30°. At what angle α (from the horizontal) should the particle be projected to get the maximum range on the inclined plane.
Ans: 60°
Sol: For range to be maximum
Ques 6: A particle is projected from the bottom of an inclined plane of inclination 30° with velocity of 40 m/s at an angle of 60° with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane. Take g = 10 m/s^{2}.
Ans:
Sol: At point A velocity of the particle will be parallel to the inclined plane.
∴ φ = β
v_{x} = u_{x} = u cos α
v_{x} = v cos φ = v cos β
or u cos α = v cos β
⇒
Ques 7: Two particles A and B are projected simultaneously in the directions shown in figure with velocities v_{A} = 20 m/s and v_{B} = 10 m/s respectively. They collide in air after 1/2 s.
Find:
(a) the angle θ
(b) the distance x.
Ans: (a) 30°
Sol: (a) At time t, vertical displacement of A
= Vertical displacement of B
i.e., v_{A} sin θ = v_{B}
∴ θ = 30°
(b) x = (v_{A} cos θ) t
Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 