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JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced PDF Download

DIRECTIONS (Q. 1 and 2) : Each question contains statements given in two columns, which have to be matched. The statements in Column-I are labelled A, B, C and D, while the statements in ColumnII are labelled p, q, r, s and t. Any given statement in Column-I can have correct matching with ONE OR MORE statement(s) in Column-II. The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example : If the correct matches are A-p, s and t; B-q and r; C-p and q; and D-s then the correct darkening of bubbles will look like the given.

JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

Q. 1. z ≠ 0 is a complex number (1992 -  2 Marks)

Column I                               Column II
 (A) Rez = 0                         (p) Rez2 = 0
 (B) Argz = JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced                      (q) Imz2 = 0
                                              (r) Rez 2 = Imz2

Ans. z ≠ 0 Let z = a + ib Re (z) = 0 ⇒ z = ib
⇒ z2 = – b2
∴ Im (z)2 = 0
∴ (A) corresponds to (q)

Arg JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced = ⇒ a = b ⇒ z = a + ia

z= a2 – a2 + 2ia2 ; z= 2ia⇒ Re (z)= 0
∴ (B) corresponds to (p).

 

Q. 2. Match the statements in Column I with those in Column II.  (2010) [Note : Here z takes values in the complex plane and Im z and Re z denote , respectively, the imaginary part and the real part of z.] 

Column  I 
Column  II
The set of points z satisfying
|z – i| z | | = |z + i | z || is contained in or equal to
(p) an ellipse with eccentricity JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced
(B) The set of points z satisfying
|z + 4 | + |z – 4 | = 10 is contained in or equal to
(q) the set of points z satisfying Im z = 0
(C) If | w | = 2, then the set of points
z = w –JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced  is contained in or equal to
(r) the set of points z satisfying |Im z | ≤ 1
(D) If | w | = 1, then the set of points
z = w +  JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced  is contained in or equal to
(s) the set of points z satisfying | Re z | < 2

(t) the set of points z satisfying | z | ≤ 3


Ans.   JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

⇒ z is equidistant from two points ( 0, |z|) and (0,– |z|) which lie on imaginary axis.

∴ z  must lie on real axis ⇒ Im ( z )=0 also |Im(z)| ≤1

(B) → p

Sum of distances of z from two fined points (–4, 0) and (4, 0) is 10 which is greater than 8.
∴ z traces an ellipse with 2a = 10 and 2ae =8

⇒ e= 4/5

(C) → (p, s, t)

Let ω = 2(cosθ + i sinθ)

then z = ω - JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced  (cosθ + i sinθ) - JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced(cosθ + i sinθ)

⇒ x + iy JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

Here JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced  JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

Also x = JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & AdvancedJEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

Which is an ellipse with e =JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

(D) → (q,r, s,t)
Let ω = cosθ + i sinq then z = 2 cosθ ⇒ Imz=0

Also z ≤ 3 and  | Im( z) |≤ 1, | Re (z) |≤ 2

 

DIRECTIONS (Q. 3) : Following question has matching lists. The codes for the list have choices (a), (b), (c) and (d) out of which ONLY ONE is correct.

Q. 3. Let zk = JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced + sin JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced: k=1,2,......,9.                            (JEE Adv. 2014)

List-I   
List-II 
P. For each zk there exists as zj such that zk. z= 1
1. True 
Q. There exists a k ∈ {1, 2,...,9} such that z1.z = zk
has no solution z in the set of complex numbers 
 2. False
R. JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced equals 
3. 1
S. JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced equals   
4. 2


      P    Q    R    S                                       P    Q    R    S
 (a) 1      2     4    3                             (b) 2      1     3    4 

(c) 1      2     3    4                              (d) 2      1     4    3


Ans. (c)

 (P)  (1) :JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced, k = 1 to 9

JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

Now zk.z= 1 ⇒ JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced =JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

We know if zis 10th root of unity so will beJEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

∴ For every zk, there exist zi = JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

Such that zk . z j = zk.JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced= 1

Hence the statement is true.

(Q) → (2) z=z k ⇒ JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced   for z1 ≠ 0

∴ We can always find a solution to z1.z =z

Hence the statement is false.

(R) → (3) : We know z10 - 1 = ( z - 1)( z - z1 ) .... ( z-z9 )

⇒ ( z - z1)( z - z2) .... ( z-z9) JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

= 1 + z + z+ ... z9

For z = 1 we get

(1 - z1) (1 - z2) ..... (1 -z9)= 10

JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

(S) → (4) : 1, Z1, Z2, ... Z9 are 10th roots of unity.      

∴ Z10 – 1 = 0

From equation 1 + Z1 + Z+ .... + Z= 0

Re (1) + Re (Z1) + Re (Z2) + .... + Re(Z9) = 0

⇒ Re (Z1) + Re (Z2) + ..... Re(Z9) = – 1

JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & AdvancedJEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced

Hence (c) is the correct option.

The document JEE Advanced (Matrix Match): Complex Numbers | Chapter-wise Tests for JEE Main & Advanced is a part of the JEE Course Chapter-wise Tests for JEE Main & Advanced.
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