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# Solved Examples for JEE: Mole Concept & Molar Mass- 1 Video Lecture - Chemistry for JEE Main & Advanced

## Chemistry for JEE Main & Advanced

320 videos|585 docs|368 tests

## FAQs on Solved Examples for JEE: Mole Concept & Molar Mass- 1 Video Lecture - Chemistry for JEE Main & Advanced

 1. What is the mole concept? Ans. The mole concept is a fundamental concept in chemistry that allows us to measure and count atoms, molecules, or ions. It is based on the Avogadro's number, which is approximately 6.022 x 10^23. One mole of any substance contains Avogadro's number of particles.
 2. How do you calculate the molar mass of a compound? Ans. The molar mass of a compound is calculated by summing up the atomic masses of all the elements present in the compound. The atomic masses can be found on the periodic table. The molar mass is expressed in grams per mole (g/mol).
 3. How can the mole concept be applied in stoichiometry? Ans. The mole concept is essential in stoichiometry, which deals with the quantitative relationships between reactants and products in chemical reactions. By using the mole concept, we can determine the ratios of different substances involved in a reaction, calculate the mass of reactants needed or products produced, and predict the limiting reactant.
 4. What is the difference between molar mass and molecular mass? Ans. Molar mass refers to the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by summing up the atomic masses of all the atoms in a compound. On the other hand, molecular mass refers to the sum of the atomic masses of the atoms in a molecule and is expressed in atomic mass units (amu).
 5. How can the mole concept be used to convert between mass and moles? Ans. The mole concept allows us to convert between mass and moles using the molar mass of a substance. To convert from moles to mass, we multiply the number of moles by the molar mass. To convert from mass to moles, we divide the mass by the molar mass. This conversion is useful in various calculations, such as determining the amount of reactants needed or products produced in a chemical reaction.

## Chemistry for JEE Main & Advanced

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