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Page 1
PHYSICS
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant.
Calculate the magnitude of the force experienced by the electron at that instant.
(1) 4× 10
-20
N
(2) 8?? × 10
-20
N
(3) 4?? × 10
-20
N
(4) 8× 10
-20
N
Correct Answer: (4)
Q.1. Solution:
M.F due to long current carrying wire at 20 cm ,
?? =
?? 0
?? 2????
?? =
2× 10
-7
× 5
20× 10
-2
?? = 0.5 × 10
-5
T
Now,
Force experienced by electron = ?? V??
?? ?? = ??????
Page 2
PHYSICS
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant.
Calculate the magnitude of the force experienced by the electron at that instant.
(1) 4× 10
-20
N
(2) 8?? × 10
-20
N
(3) 4?? × 10
-20
N
(4) 8× 10
-20
N
Correct Answer: (4)
Q.1. Solution:
M.F due to long current carrying wire at 20 cm ,
?? =
?? 0
?? 2????
?? =
2× 10
-7
× 5
20× 10
-2
?? = 0.5 × 10
-5
T
Now,
Force experienced by electron = ?? V??
?? ?? = ??????
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
= 8 × 10
-20
N
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:
(1) n
(2) 2??
(3) 3n
(4) 4n
Correct Answer: (2)
Q.2. Solution:
Given,
frequency of SIHM = ??
as we know,
? In one time period ???? become maximum & minimum two time
So,
It means frequency of ???? is 2?? .
3. A radioactive nucleus
?? A
X undergoes spontaneous decay in the sequence
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where
Z is the atomic number of element X. The possible decay particles in the sequence are:
(1) ?? ,?? -
,?? +
(2) ?? ,?? +
,?? -
(3) ?? +
,?? ,?? -
(4) ?? -
,?? ,?? +
Correct Answer: (3)
Q.3. Solution:
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay
mass number remains unchange and atomic number increases by 1.
Due to ?? +
decay mass number remains unchange but atomic number decreares by 1.
Page 3
PHYSICS
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant.
Calculate the magnitude of the force experienced by the electron at that instant.
(1) 4× 10
-20
N
(2) 8?? × 10
-20
N
(3) 4?? × 10
-20
N
(4) 8× 10
-20
N
Correct Answer: (4)
Q.1. Solution:
M.F due to long current carrying wire at 20 cm ,
?? =
?? 0
?? 2????
?? =
2× 10
-7
× 5
20× 10
-2
?? = 0.5 × 10
-5
T
Now,
Force experienced by electron = ?? V??
?? ?? = ??????
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
= 8 × 10
-20
N
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:
(1) n
(2) 2??
(3) 3n
(4) 4n
Correct Answer: (2)
Q.2. Solution:
Given,
frequency of SIHM = ??
as we know,
? In one time period ???? become maximum & minimum two time
So,
It means frequency of ???? is 2?? .
3. A radioactive nucleus
?? A
X undergoes spontaneous decay in the sequence
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where
Z is the atomic number of element X. The possible decay particles in the sequence are:
(1) ?? ,?? -
,?? +
(2) ?? ,?? +
,?? -
(3) ?? +
,?? ,?? -
(4) ?? -
,?? ,?? +
Correct Answer: (3)
Q.3. Solution:
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay
mass number remains unchange and atomic number increases by 1.
Due to ?? +
decay mass number remains unchange but atomic number decreares by 1.
So, option (3) is correct option.
4. The escape velocity from the Earth's surface is ?? . The escape velocity from the surface of another planet having a
radius, four times that of Earth and same mass density is :
(1) ??
(2) 2??
(3) 3??
(4) 4??
Correct Answer: (4)
Q.4. Solution:
As we know escape velocity is given by,
?? ?? = v2???? =
v
2???? 4
3
?? ?? 3
4
3
?? ?? 2
=
v
2???? ?? 4
3
?? ?? 2
?? ?? ?
v
?? 2
? ??
Escape velocity from Earth’s surface = ??
Escape velocity from surface of another planet =?
?? ???????????? = 4?? ???????? h
?? ???????????? = ?? ???????? h
So we can write ,
(?? ?? )
earth
(?? ?? ) planet
=
?? ???????? h
?? ???????????? =
?? 4?? =
1
4
It means,
(?? ?? )
earth
= (?? ?? )
Planet
(?? ?? )
Planet
= 4??
Page 4
PHYSICS
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant.
Calculate the magnitude of the force experienced by the electron at that instant.
(1) 4× 10
-20
N
(2) 8?? × 10
-20
N
(3) 4?? × 10
-20
N
(4) 8× 10
-20
N
Correct Answer: (4)
Q.1. Solution:
M.F due to long current carrying wire at 20 cm ,
?? =
?? 0
?? 2????
?? =
2× 10
-7
× 5
20× 10
-2
?? = 0.5 × 10
-5
T
Now,
Force experienced by electron = ?? V??
?? ?? = ??????
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
= 8 × 10
-20
N
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:
(1) n
(2) 2??
(3) 3n
(4) 4n
Correct Answer: (2)
Q.2. Solution:
Given,
frequency of SIHM = ??
as we know,
? In one time period ???? become maximum & minimum two time
So,
It means frequency of ???? is 2?? .
3. A radioactive nucleus
?? A
X undergoes spontaneous decay in the sequence
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where
Z is the atomic number of element X. The possible decay particles in the sequence are:
(1) ?? ,?? -
,?? +
(2) ?? ,?? +
,?? -
(3) ?? +
,?? ,?? -
(4) ?? -
,?? ,?? +
Correct Answer: (3)
Q.3. Solution:
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay
mass number remains unchange and atomic number increases by 1.
Due to ?? +
decay mass number remains unchange but atomic number decreares by 1.
So, option (3) is correct option.
4. The escape velocity from the Earth's surface is ?? . The escape velocity from the surface of another planet having a
radius, four times that of Earth and same mass density is :
(1) ??
(2) 2??
(3) 3??
(4) 4??
Correct Answer: (4)
Q.4. Solution:
As we know escape velocity is given by,
?? ?? = v2???? =
v
2???? 4
3
?? ?? 3
4
3
?? ?? 2
=
v
2???? ?? 4
3
?? ?? 2
?? ?? ?
v
?? 2
? ??
Escape velocity from Earth’s surface = ??
Escape velocity from surface of another planet =?
?? ???????????? = 4?? ???????? h
?? ???????????? = ?? ???????? h
So we can write ,
(?? ?? )
earth
(?? ?? ) planet
=
?? ???????? h
?? ???????????? =
?? 4?? =
1
4
It means,
(?? ?? )
earth
= (?? ?? )
Planet
(?? ?? )
Planet
= 4??
5. The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours
would be :
(1) 1/2
(2)
1
2v2
(3)
2
3
(4)
2
3v2
Correct Answer: (2)
Q.5. Solution:
Given,
?? 1
2
= 100 hours
?? = 150 hours
? no. of nuclide remain after ?? half life, ?? =
?? 0
2
??
? 100 hours = 1 half life
150 hours =
1
100
× 150
=
3
2
half life
So, Fraction Remain after
3
2
half life
?? ?? 0
= (
1
2
)
3/2
=
1
2v2
6. A convex lens 'A' of focal length 20cm and a concave lens ' ?? ' of focal length 5cm are kept along the same axis with a
distance 'd' between them. If a parallel beam of light falling on 'A' leaves 'B' as a parallel beam, then the distance 'd' in cm
will be :
(1) 25
(2) 15
(3) 50
(4) 30
Page 5
PHYSICS
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant.
Calculate the magnitude of the force experienced by the electron at that instant.
(1) 4× 10
-20
N
(2) 8?? × 10
-20
N
(3) 4?? × 10
-20
N
(4) 8× 10
-20
N
Correct Answer: (4)
Q.1. Solution:
M.F due to long current carrying wire at 20 cm ,
?? =
?? 0
?? 2????
?? =
2× 10
-7
× 5
20× 10
-2
?? = 0.5 × 10
-5
T
Now,
Force experienced by electron = ?? V??
?? ?? = ??????
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
= 8 × 10
-20
N
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:
(1) n
(2) 2??
(3) 3n
(4) 4n
Correct Answer: (2)
Q.2. Solution:
Given,
frequency of SIHM = ??
as we know,
? In one time period ???? become maximum & minimum two time
So,
It means frequency of ???? is 2?? .
3. A radioactive nucleus
?? A
X undergoes spontaneous decay in the sequence
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where
Z is the atomic number of element X. The possible decay particles in the sequence are:
(1) ?? ,?? -
,?? +
(2) ?? ,?? +
,?? -
(3) ?? +
,?? ,?? -
(4) ?? -
,?? ,?? +
Correct Answer: (3)
Q.3. Solution:
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay
mass number remains unchange and atomic number increases by 1.
Due to ?? +
decay mass number remains unchange but atomic number decreares by 1.
So, option (3) is correct option.
4. The escape velocity from the Earth's surface is ?? . The escape velocity from the surface of another planet having a
radius, four times that of Earth and same mass density is :
(1) ??
(2) 2??
(3) 3??
(4) 4??
Correct Answer: (4)
Q.4. Solution:
As we know escape velocity is given by,
?? ?? = v2???? =
v
2???? 4
3
?? ?? 3
4
3
?? ?? 2
=
v
2???? ?? 4
3
?? ?? 2
?? ?? ?
v
?? 2
? ??
Escape velocity from Earth’s surface = ??
Escape velocity from surface of another planet =?
?? ???????????? = 4?? ???????? h
?? ???????????? = ?? ???????? h
So we can write ,
(?? ?? )
earth
(?? ?? ) planet
=
?? ???????? h
?? ???????????? =
?? 4?? =
1
4
It means,
(?? ?? )
earth
= (?? ?? )
Planet
(?? ?? )
Planet
= 4??
5. The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours
would be :
(1) 1/2
(2)
1
2v2
(3)
2
3
(4)
2
3v2
Correct Answer: (2)
Q.5. Solution:
Given,
?? 1
2
= 100 hours
?? = 150 hours
? no. of nuclide remain after ?? half life, ?? =
?? 0
2
??
? 100 hours = 1 half life
150 hours =
1
100
× 150
=
3
2
half life
So, Fraction Remain after
3
2
half life
?? ?? 0
= (
1
2
)
3/2
=
1
2v2
6. A convex lens 'A' of focal length 20cm and a concave lens ' ?? ' of focal length 5cm are kept along the same axis with a
distance 'd' between them. If a parallel beam of light falling on 'A' leaves 'B' as a parallel beam, then the distance 'd' in cm
will be :
(1) 25
(2) 15
(3) 50
(4) 30
Correct Answer: (1)
Q.6. Solution:
Total distance = ?? 1
+ ?? 2
= 25 ????
7. A capacitor of capacitance '?? ', is connected across an ac source of voltage ?? , given by V = V
0
sin ?? t The displacement
current between the plates of the capacitor, would then be given by:
(1) I
d
= V
0
?? Ccos?? t
(2) I
d
=
V
0
?? C
cos ?? t
(3) ?? ?? =
?? 0
????
sin ????
(4) I
d
= V
0
?? Csin ?? t
Correct Answer: (1)
Q.7. Solution:
? ?? = ????
And ?? = ?? 0
sin????
?? ?? =?
As we know,
? ?? ?? = ?? 0
?? Ø
????
= ?? 0
??????
????
(? ?? =
?? ?? )
=
?? 0
?? ????
?? ????
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Ans.NEET, or the National Eligibility cum Entrance Test, is a standardized entrance exam in India for students aspiring to pursue undergraduate medical courses. It is crucial because it serves as a common gateway for admission into medical and dental colleges, ensuring that students are assessed on a uniform basis, which enhances the selection process for quality education in the medical field.
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