Overview: Squares and Square Roots | CSAT Preparation - UPSC PDF Download

Square Numbers

When a number or integer (not a fraction) is multiplied by itself, the resultant is called a ‘Square Number’. 

• Any natural number ‘p’ which can be represented as y², where y is a natural number, then ‘p’ is called a Square Number.

  Example

  4 = 2²

  9 = 3²

  16 = 4²

  Where 2, 3, 4 are the natural numbers and 4, 9, 16 are the respective square numbers.

  Such types of numbers are also known as Perfect Squares.

• For example, 3 multiplied by 3 is equal to 3-squared or 3 x 3 = 3². So, basically, the exponential form of multiplication of a number or integer by itself is called a square number. 
• Square numbers are always positive. If the negative sign is multiplied by itself, it results in a positive sign (+). For example, (-4)² = 16. So, we can say here 16 is a positive square number, whose square root is an integer again, i.e.√16 = 4.
• Numbers such as 1, 4, 9, 16, 25, 36, 49, 64, etc. are special numbers as these are the product of a number by itself.
• If we express a number (x) in terms of the square of any natural number such as a², then x is a square number. 
• For example, 100 can be expressed as 10 × 10 = 10², where 10 is a natural number, therefore 100 is a square number. 
• Whereas, the number 45 cannot be called a square number because it is the product of numbers 9 and 5. The number is not multiplied by itself. Square numbers can also be called perfect square numbers.

List of Square Numbers 

Odd and Even Square Numbers

• Squares of even numbers are even, i.e, (2n)² = 4n².
• Squares of odd numbers are odd, i.e, (2n + 1) = 4(n² + n) + 1.
• Since every odd square is of the form 4n + 1, the odd numbers that are of the form 4n+3 are not square numbers.

Properties of Square Numbers

The following are the properties of the square numbers:

•  A number with 2, 3, 7 or 8 at the unit’s place should never be a perfect square. In other words, none of the square numbers ends in 2, 3, 7 or 8.
• Any number having 1 or 9 in its one’s place will always have a square ending with 1.
  
• Any number which has 4 or 6 in its unit’s place, its square will always end with 6.
  
• Any number which has 0 in its unit’s place, its square will always have an even number of zeros at the end.
  
• If the number of zeros at the end is even, then the number is a perfect square number. Otherwise, we can say that a number ending in an odd number of zeros is never a perfect square
• If the even numbers are squared, it always gives even numbers. Also, if the odd numbers are squared, it always gives odd numbers.
• If the natural numbers other than one are squared, it should be either a multiple of 3 or exceeds a multiple of 3 by 1.
• If the natural numbers other than one is squared, it should be either a multiple of 4 or exceeds a multiple of 4 by 1.
• It is noted that the unit’s digit of the square of a natural number is equal to the unit’s digit of the square of the digit at unit’s place of the given natural number.
• There are n natural numbers, say p and q such that p ² = 2q ²
• For every natural number n, we can write it as: (n + 1)² – n ² = ( n + 1) + n..
• If a number n is squared, it equals the sum of the first n odd natural numbers.
• For any natural number, say”n” which is greater than 1, we can say that (2n, n ² – 1, n ² + 1) should be a Pythagorean triplet.

Finding the Square of a Number

Example: Find the square of 53.

Solution: Divide the number in two parts.

53 = 50 + 3

53² = (50 + 3)²

= (50 + 3) (50 + 3)

= 50(50 + 3) +3(50 + 3)

= 2500 + 150 + 150 + 9

= 2809

1. Other pattern for the number ending with 5

For numbers ending with 5 we can use the pattern

(a5)² = a × (a + 1)100 + 25

Example

25²= 625 = (2 × 3) 100 + 25

45² = 2025 = (4 × 5) 100 + 25

95² = 9025 = (9 × 10) 100 + 25

125² = 15625 = (12 × 13) 100 + 25

2. Pythagorean TripletsIf the sum of two square numbers is also a square number, then these three numbers form a Pythagorean triplet.For any natural number p >1, we have (2p) ² + (p² -1)² = (p² + 1)². So, 2p, p²-1 and p²+1 forms a Pythagorean triplet.

Example: Write a Pythagorean triplet having 22 as one its members.

Solution:

Let 2p = 6

P = 3

p² + 1 = 10

p² - 1 = 8.

Thus, the Pythagorean triplet is 6, 8 and 10.

6² + 8² = 10²

36 + 64 = 100

Square Root

The square root is the inverse operation of squaring. To find the number with the given square is called the Square Root.

• When you square a number, you are multiplying it by itself, e.g. 6*6 = 36.  
• When you take the square-root of a number, you are undoing the square, going backwards from the result of squaring to the input that was originally squared: √ 36 = 6.  Similarly, 8*8 = 64, so √ 64 = 8.  
• As long as all the numbers are positive, everything is straightforward.
• The square root of a number is denoted by the symbol called the radical sign(√ ).
  2² = 4, so the square root of 4 is 2
  10² = 100, therefore square root of 100 is 10
• There are two square roots of any number. One is positive and the other is negative. The square root of 100 could be 10 or -10.

Symbol of Positive Square Root

How to Find the Square Root of an Integer?

(i) By the method of Prime Factors: 

When a given number is a perfect square, we resolve it into prime factors and take the product of prime factors, choosing one out of every two.
To find the square root of a perfect square by using the prime factorization method when a given number is a perfect square:

• Step I: Resolve the given number into prime factors.
• Step II: Make pairs of similar factors.
• Step III: Take the product of prime factors, choosing one factor out of every pair.

Example 1: Find the square root of 484 by prime factorization method.

Solution:
Resolving 484 as the product of primes, we get

484 = 2 × 2 × 11 × 11 
√484 = √(2 × 2 × 11 × 11) 
= 2 × 11 
Therefore, √484 = 22

Example 2: Find the square root of 324.

Solution: The square root of 324 by prime factorization, we get 

324 = 2 × 2 × 3 × 3 × 3 × 3
√324 = √(2 × 2 × 3 × 3 × 3 × 3) 
= 2 × 3 × 3 
Therefore, √324 = 18 

(ii) By the method of Long Division: 

This method can be used when the number is large and the factors cannot be determined easily. This method can also be used when we want to add a least number or to subtract a least number from a given number so that the resulting number may give a perfect square of some number.
Steps of Long Division Method for Finding Square Roots:

• Step I: Group the digits in pairs, starting with the digit in the units place. Each pair and the remaining digit (if any) is called a period.
• Step II: Think of the largest number whose square is equal to or just less than the first period. Take this number as the divisor and also as the quotient.
• Step III: Subtract the product of the divisor and the quotient from the first period and bring down the next period to the right of the remainder. This becomes the new dividend.
• Step IV: Now, the new divisor is obtained by taking two times the quotient and annexing with it a suitable digit which is also taken as the next digit of the quotient, chosen in such a way that the product of the new divisor and this digit is equal to or just less than the new dividend.
• Step V: Repeat steps (2), (3) and (4) till all the periods have been taken up. Now, the quotient so obtained is the required square root of the given number.

Example 1: Find the square root of 784 by the long-division method.

Solution:
Marking periods and using the long-division method,

Therefore, √784 = 28

Example 2: Evaluate √5329 using the long-division method.

Solution: Marking periods and using the long-division method,

Therefore, √5329 =73

Square Roots of Decimals

To find the square root of a decimal number we have to put bars on the primary part of the number in the same manner as we did above. And for the digits on the right of the decimal we have to put bars starting from the first decimal place.

Rest of the method is same as above. We just need to put the decimal in between when the decimal will come in the division.

Example: Find √7.29 using the division method.

Solution:

Thus, √7.29 = 2.7

Remark: To put the bar on a number like 174.241, we will put a bar on 74 and a bar on 1 as it is a single digit left. And in the numbers after decimal, we will put a bar on 24 and put zero after 1 to make it double-digit.

174. 24 10

Solution:

We know that, 300 comes between 100 and 400 i.e. 100 < 300 < 400.
Now, √100 = 10 and √400 = 20.

 So, we can say that

10 < √300 < 20.

We can further estimate the numbers as we know that 17² = 289 and 18² = 324.
Thus, we can say that the square root of √300 = 17 as 289 is much closer to 300 than 324.

Important Points to Remember

1.

2.
3. Number ending in 8 can never be a perfect square.
4. Remember the squares and cubes of 2 to 10. This will help in easily solving the problems.

Solved Questions on Squaring and Square Roots

Q1: Simplify the following expression.

Solution: 

Q2: Simplify the following expression.

Solution:  

Q3: Assume x to be positive. Multiply the eighth power of the fourth root of x by the fourth power of the eighth root of x. What is the product?

Solution: