Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

Science Class 10

Class 10 : Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

The document Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev is a part of the Class 10 Course Science Class 10.
All you need of Class 10 at this link: Class 10

Chemical Change

Whenever a chemical change occurs, we say that a chemical reaction has taken place. For example, cooking of food, respiration, digestion of food, exposure of iron to the humid atmosphere. Chemical change involves the change of state, change of colour, the evolution of gas, or change of temperature. Cooking of food, fermentation of sugar, and respiration are some examples of chemical change.

Activity 1Aim:

Perform an activity to show that a chemical reaction has taken place (change in state and change in colour).

Materials required:

A conical flask, 5% lead nitrate solution, 5% potassium iodide solution, test tubes.

Procedure:
(i) Take a clean 100 mL flask.

(ii) Take about 10 mL (half a test tube) of lead nitrate solution in a test tube and transfer it to the flask.

(iii) Then take about 10 mL of potassium iodide solution in a test tube and add it to the same flask.

(iv) Shake the flask and observe what happens. 

We observe that a yellow precipitate of lead iodide is formed.


Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRevLead Nitrate reacts with Potassium Iodide to form Lead Iodide  

Lead nitrate + Potassium iodide → Lead iodide + Potassium nitrate

Result:

This activity shows that a chemical reaction has taken place. Before mixing, the two solutions were colourless. But after mixing the two solutions, we obtain a yellow insoluble substance (precipitate). Thus there is a change of state and a change of colour.


Activity 2
Aim:

Perform an activity to show that a chemical reaction has taken place (evolution of a gas and change of temperature).

Materials Required:

Conical flask (250 mL), cork, glass tube, zinc granules, dilute sulphuric acid.

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

Formation of Hydrogen Gas by the action of Dilute Sulphuric Acid on Zinc

Procedure:

  • Set up the apparatus as shown in the above figure.
  • Remove the cork and glass tube. Place some dilute sulphuric acid into it.
  • Add a few small granules of zinc and immediately close the flask with the cork.
  • We observe that hydrogen gas is evolved which is indicated by the bubbles.
  • On touching the flask, we find that it is hotter now than before.

Chemical Equations

The description of a chemical reaction in a short form is called a chemical equation.
For example:
Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

Magnesium and oxygen which react are called reactants and magnesium oxide is formed after the reaction is called product. The reactants are written on the left-hand side (LHS) with a plus sign between them. Similarly, the products are written on the right-hand side (RHS) with a plus sign between them. The arrowhead points towards the product and shows the direction of the reaction.

Writing a Chemical Equation

Skeletal Chemical Equation

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRevA chemical equation written in the form of symbols and formulae is called skeletal chemical equation. Such an equation may not be balanced.

Example: Mg + O2 → MgO

In this equation, there are two oxygen atoms on the LHS while there is only one oxygen atom on RHS.

Balanced Chemical Equations

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRevNumber of Atoms on both sides should be Equal

A chemical equation in which the number of atoms of each element on LHS and RHS is equal is called a balanced chemical equation.

Example: Zn + H2SO4 → ZnSO4 + H2

is a balanced equation because the number of atoms of Zn, H, S, and O is equal on the reactant (LHS) and product (RHS) sides.

Balancing of Chemical Equation

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRevLet us illustrate the balancing of the chemical equations by taking.
Example: Fe + H2O → Fe3O4 + H2

The following steps are involved:
Step I. Draw boxes around each formula.
Fe + H2O → Fe3O4 + H2

Step II. We find that number of Fe and O atoms on the reactant and product sides are different. So the equation needs to be balanced.

Step III. Select the compound which has a maximum number of atoms. It may be a reactant or product. In that compound, select the element which has the maximum number of atoms. Using these criteria, we select Fe304 as the compound and oxygen as the element. There are four 0 atoms on RHS and one O atom on the LHS. Hence, multiply H20 (containing O) by four to balance O.

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

The partly balanced equation becomes:
Fe + 4H2O → Fe3O4 + H2

Step IV. Fe and H are still to be balanced. Take either now for balancing. Let us take H. There are eight H atoms on LHS and two H atoms on RHS. Multiply H2 by four to equalise H atoms.

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

The equation would become:
Fe + 4H2O → Fe3O4 + H2

Step V. Fe is left to be balanced. There is one Fe atom on LHS and three Fe atoms on RHS. Multiply Fe on LHS by three to equalize

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

We can write the equation now as:
3Fe + 4H2O → Fe3O4 + H2

Step VI. Finally, we write the equation, after removing boxes and check whether it is balanced or not
3Fe + 4H2O → Fe3O4 + 4H2
This method of balancing equations is known as the hit and trial method as we complete the balancing by making trials for different elements.

Step VII. Writing Symbols of Physical States. To make the equation more informative, we write the physical states of different substances on LHS and RHS. Thus,
3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2 (g)
Notations (s), (l) and (g) are used for solid, liquid and gaseous states respectively. In the above equation (g) after H2O means H2O is in the form of steam (gaseous), (aq) is written for aqueous solution.
Sometimes the reaction conditions, such as temperature, pressure, catalysts, etc., for the reaction are indicated above and/or below the arrow in the equation. For example,

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

Types of Chemical Reactions

Chemical reactions involve breaking and making of bonds between atoms to produce new substances.

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRevCombination Reactions

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

A reaction in which a single product is formed from two or more reactants is called a combination reaction.
For example,
(i) Burning of coal C(s) + O2 (g) → CO2 (g)
(ii) Formation of water from H2 and O2. 2H2 (g) + O2 (g) → 2H2O (I)

Activity 3

Aim: 

Perform an activity to illustrate a combination reaction.

Materials required:

Beaker (500 mL ), water, calcium oxide ( quick lime).

Procedure:
(i) Take a clean 500 mL pyrex glass beaker (Fig. 1.3).

(ii) Take about 50 g quick lime in it.

(iii) Add about 100 ml water to it carefully.

(iv) Quick lime (calcium oxide) reacts vigorously with water to form a single product slaked lime Ca(OH)2 and a large amount of heat is evoked. 

Overview of Chemical Reactions and Equations (Part - 1) Class 10 Notes | EduRev

 Formation of Slaked Lime by the Reaction of Calcium Oxide with Water

CaO (s) + H2O (l) → Ca(OH)2 (aq) + Heat
Some more examples of combination reactions are : Burning of coal
C(s) + O2 (g) → CO2 (g)
Formation of water from H2 (g) and 02 (g)
2H2 (g) + O2 (g) → 2H2O (l)

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