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Characteristics of Oxidation-Reduction
1. Oxidation or de-electronation is a process which liberates electrons.
2. Reduction or electronation is a process which gains electronselectron movement in oxidation and reductionelectron movement in oxidation and reduction

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSC

3. Oxidant are substances which

  • Oxidise other
  • Are reduced themselves
  • Show gain of electrons
  • Show a decrease in oxidation number during a change.
  • Have higher oxidation number in a conjugate pair of redox.

4. Reductants are the substances which

  • Reduce other.
  • Are oxidised themselves
  • Show loss of electrons
  • Show an increase in oxidation number during a change
  • Have lower oxidation number in a conjugate pair of redox.

5. A redox change involves the process in which a reductant is oxidized to liberate electron, which are then taken up by an oxidant to get itself reduced.

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSC

6. A redox change occur simulataneously.

 

Types of Redox Reactions

redox meaningredox meaning1. Inter-molecular redox reactions
Two substance reacts; one of them is oxidant and other is reductant, e.g.,

10FeSO4 + 2KMnO4 + 8H2SO4 → 2MnSO4 + 5Fe2 (SO)2 + K2SO4 + 8H2O
(reductant)         (Oxidant)

Or

2Fe2+ → (Fe3+)2 + 2e

And Mn7+ + 5e → Mn2+

2. Auto-redox or Disproportionation
The same element of a substance is oxidized and reduced as well, e.g.,

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSC

3. Intra-molecular redox reactions
One element of a compound is oxidized and the other element of the same compound is reduced, e.g.,

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSC


Oxidation Number

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSCelectron movement decides the oxidation numberOxidation number of an element in a particular compound represents the number of electrons lost or gained by an element during is change from free state into that compound. Oxidation number is given positive sign if electrons are lost. Oxidation number is given negative sing if electrons are gained. Oxidation number represents real charge in case of ionic compounds, however, in compounds it represents for imaginary charge.

The rules of deriving oxidation number
Following arbitrary rules have been adopted to derive oxidation number of elements on the basis of periodic properties of elements.
(i) In uncombined state or free state, oxidation number of an element is zero
(ii) In uncombined state oxidation number of

  • F is always –1
  • O is –2; in peroxides (—O—O—), it is –1. However, in F2O, it is +2. In superoxide, it is -1/2
  • H is +1; In ionic hydrides it is –1
  • Metals is positive except in some metal hydrides as CuH(Cu1–) and [Rh(CO)4], both metals have –ve oxidation number.
  • Alkali metals (IA, e.g., Li, Na, K, Rb, Cs, Fr) is always +1
  • Alkaline earth metals (IIA, e.g., Be, Mg, Ca, Sr, Ba, Ra) is always +2
  • Halogens in halides is always –1
  • Sulphur in sulphides is always –2]

(iii) The algebraic sum of all the oxidation numbers of elements in a compound is equal to zero, e.g., K2MnO4.
        2 × (oxidation number of K) + (oxidation number of Mn) + 4 × (oxidation number of O) = 0
(iv) The algebraic sum of all the oxidation numbers of elements in a radical is equal to net charge on that radical, e.g., C2O42- .
        2 × (oxidation number of C) + 4 × (oxidation number of O) = –2
(v) Oxidation number of can be zero, +ve, –ve integer or fraction.
(vi) Maximum oxidation number of an element (except O and F) = group number.
(vii) Minimum oxidation number of an element (except metals) = group number –8
(viii) Variable oxidation number is most commonly shown by transition elements as well as by p-block elements.


Iodimetric titration
Iodine is a moderately strong oxidising agent and can be used to titrate reducing agent but their number is limited.
The redox titrations involving iodine solution as an oxidant, e.g., Na2S2O3 vs. I2 are called iodometric titrations. However I2 being sparingly soluble in water and therefore solution of Iused for iodometric titrations is prepared in presence of KI. Presence of KI increases the solubility of I2 in water due to complex formation.
The reaction is:


 2Na2S2O3 + I2  → Na2S4O6 + 2NaI

Redox changes are:

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSC

Indicator: I2 acts as self-indicator with starch solution. The disappearance of blue colour of starch –I2 indicates the end point of titration.


Iodometric titrations
Iodide ion is a weak reducing agent and will reduce strong oxidising agents. The redox change involving liberated iodine as an oxidant e.g., CuSOvs. Hypo in presence of KI are called iodometric titration.
The reaction are:

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSC

Redox changes are like iodometry. However the iodometric titrations should be performed rapidly to minimise oxidation of iodide by air.

Example: A 1.100 g sample of copper ore is dissolved and the Cu2+ of is treated with excess KI. The liberated I2 requires 12.12 mL of 0.10 M Na2SOsolution for titration. What is % copper by mass in the ore:

Oxidation And Reduction - Mole Concept | Lucent for GK - UPSC

 

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FAQs on Oxidation And Reduction - Mole Concept - Lucent for GK - UPSC

1. What is oxidation and reduction in chemistry?
Ans. Oxidation and reduction are chemical processes that involve the transfer of electrons between reactant species. Oxidation refers to the loss of electrons by a substance, resulting in an increase in its oxidation state. Reduction, on the other hand, involves the gain of electrons by a substance, leading to a decrease in its oxidation state.
2. How does the mole concept relate to oxidation and reduction?
Ans. The mole concept is a fundamental concept in chemistry that helps us understand the quantitative aspects of chemical reactions. In the context of oxidation and reduction, the mole concept allows us to determine the number of electrons transferred during the redox reaction. This information is crucial in balancing redox equations and calculating the stoichiometry of reactions.
3. Can you provide an example of oxidation and reduction reactions?
Ans. Sure! One common example is the reaction between magnesium and oxygen to form magnesium oxide. In this reaction, magnesium (Mg) is oxidized as it loses two electrons to form Mg2+ ions, which have a higher oxidation state. Oxygen (O2) is reduced as it gains two electrons to form O2- ions, which have a lower oxidation state. The balanced equation for this reaction is 2Mg + O2 -> 2MgO.
4. How is oxidation and reduction related to the concept of electron transfer?
Ans. Oxidation and reduction are directly related to the concept of electron transfer. During oxidation, a substance loses electrons, which are transferred to another substance undergoing reduction. This transfer of electrons allows for the balancing of charges in a chemical reaction. The electrons that are lost during oxidation must be gained by another species during reduction, ensuring the conservation of charge.
5. What are some real-life applications of oxidation and reduction reactions?
Ans. Oxidation and reduction reactions have numerous real-life applications. Some examples include the rusting of iron (oxidation), combustion of fuels like gasoline (oxidation), photosynthesis in plants (reduction of carbon dioxide to glucose), and the operation of batteries (redox reactions involving electron transfer). Understanding these reactions is essential in various fields, such as environmental science, energy production, and pharmaceutical development.
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