Table of contents  
Simple Interest and Compound Interest  
Simple Interest  
Compound Interest  
Solved Examples 
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Principal is the amount on which interest is paid / earned.
If principal is denoted by P
The rate of interest is denoted by R
The time for which the principal is given on interest = T
Then
Simple interest earned / paid is devoted by S.I.
Then (1) S.I. =
Amount (A) = P + SI (Amount is the sum of P and the SI earned)
Amount x 100 = Principal x (100 + RT)
Principal =
Or CI = A – P
Difference of CI and SI for a period of one year in zero
For 2 years the difference of CI and SI is
For 3 years the difference of CI and SI is
=
Example 1: Ramesh deposited Rs. 29400 for 6 years at simple interest. After 6 years he received Rs. 4200 as interest. Find the annual rate of interest.
For finding out the rate of interest R
Example 2: I invested an amount of Rs. 17500 at the rate of 8% per annum. After how many years will I get Rs. 16800 as simple interest?
So T =
So time is 12 years
Example 3: Pritam invested Rs. 16840 at 6% for 5 years. What amount of SI, he will get after 5 years.
R = 6%
T = 5 years
= RS. 5052
Example 4: At what rate percent per annum simple interest a sum of money doubles itself in 15 years.
T = 15 years
SI = Rs.100
R = ?
Example 5: A sum of Rs. 3100 was lent partly at 5% and partly at 8% simple interest. The total interest received after 3 years was Rs. 600. Amount lent on 5% per annum was how much.
So
Or 15x + 24 (3100 – x) = 60000
Or 9x = 74400 – 60000
Let us suppose that whole amount was given at 5%
Interest =
But the interest earned in 600. It means some amount which earns Rs. 135 at 3% interest (8%  5%) was given. This amount is
So 3100 – 1500 = Rs. 1600 was given an interest of 5%.
Example 6: The simple interest on a sum of money is 4/9 of the principal and the number of years is equal to the rate percent per annum. The rate per annum is what?
SI = Rs. 4/9
Let rate be = x%
Then T = x years
As per the formula SI = PRT / 100
So rate per annum =
Example 7: In 4 years, the simple interest on a sum of money is 9/25 of the principal. Find out the annual rate of interest.
Interest =
T = 4 years
R =
Example 8: A sum of money at simple interest amounts to Rs. 1012 in 2½ years and to Rs. 1067.20 in 4 years. Find out the rate of interest, per year.
Solution: From the question it is clear that
Rs. 1067.20 – Rs. 1012.00 = Rs. 55.20 is the simple interest earned in a period of 1½ years. So now we can find the interest earned in 2½ year which will be
= 18.40 x 5 = 92.00
So the principal in the beginning was Rs. 101292 = Rs. 920
So now P = Rs. 920
T = 5/2 year
Simple Interest = Rs. 92
Example: I borrowed Rs. 40,000 from a bank. The bank charges interest at the rate of 10% per annum. At the end of the year I will have to pay Rs. i.e. Rs. 4000 as interest.
Thus total amount of Rs. 40000 + Rs. 4000 = Rs. 44000 will have to be paid back to the bank.
If due to some reason I am not able to pay, the bank will charge 10% interest for the next year on the principal of Rs. 44000. At the end of the 2^{nd} year the interest will be Rs.
= Rs. 4400.
Thus total interest payable to the bank will be Rs. (4400 + 4000) = Rs. 8400. This interest is Rs. 400 more than the simple interest on 40000 for 2 years at 10%. This Rs. 400 is the interest on the interest of 4000 for the first year. So the interest calculated in this way is called compound interest.
Remarks: For the first unit of time the simple and the compound interest are equal. From the second unit of time onwards the compound interest is more than the simple interest.
Example 1: find the compound interest on Rs. 3000 for 3 years at 8% per annum.
Rate = 8%
Time = one year
Interest = = Rs. 240
Amount = Principal + interest = Rs. 3000 + 240 = Rs. 3240
Principal for 2^{nd} year = Rs. 3240
Rate = 8%
Time = 1 year
So interest for 2^{nd} year =
So amount = Rs. 3240 + Rs. 259.20 = Rs. 3499.20
Principal for 3^{rd} year = Rs. 3499.20
Rate = 8%
Time = 1 year
Interest for 3^{rd} year =
So compound interest for 3 years
= Rs. 240 + Rs. 259.20 + Rs. 279.94 = Rs. 779.14
When interest is compounded half yearly.
Example 2: Find the compound interest on Rs. 1000 for 1½ year at 12% per annum when the interest is compounded half yearly.
So the rate per half year will be 12/2 % or 6%. Also there will be 3 half years in 1½ year. By using the formula
In this case P = 1000
r = 6% per half year
t = 3 half years
So A =
So compound interest = Rs. 1191.02 – Rs. 1000 = Rs. 191.02
When the interest is compounded quarterly
Example 3: Find the compound interest on Rs. 6000 for one year at 16% per annum when the interest is compounded quarterly.
Time is one year or 4 quarters
By the formula of compound interest
So compound interest for 4 quarters at the rate of 16% on 6000 is 7019.15 – 6000 = Rs. 1019.15
Example 4: At what rate per cent interest per annum, will Rs. 10000 amount to Rs. 14641 in 2 years. If the interest is compounded half yearly.
A = Rs. 14641
R = ?
T = 2 years or 4 half years
Formula isA =
or 14641 =
or
so 10% is half yearly rate
annual rate will be 10 x 2 = 20%
Example 5: The difference between the compound interest and simple interest on a certain sum at 14% per annum for 2 years is Rs. 147. Find the sum.
SI on 100 for 2 years at 14% is =
CI on 100 for 2 years at 14% = A – P
Difference in CI and SI =
If difference is = 100
If difference 1=
If difference is Rs. 147 =
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