Short & Long Answer Questions: Redox Reactions | Chemistry Class 11 - NEET PDF Download

Q1. The blue colour of copper sulphate solution is discharged when a rod of zinc is dipped in it. Explain.

Ans: Zinc lies below copper in the electrochemical series and can therefore, release electrons to the   ions. As a result, Zn is oxidised while  ions are reduced. Since the concentration of   ions in the solution decreases, the blue colour of the solution is slowly discharged.


Q2. Why cannot oxidation occur without reduction?
Ans: Oxidation involves the loss of electrons while the reduction involves the gain of electrons. Energy is needed when a species loses electrons and is released when it accepts electrons. This means that a species can gain energy only at the cost of electron releasing species. In other words, oxidation cannot occur without reduction or oxidation and reduction go side by side.

Q3. Articles of iron are generally coated with zinc. Explain.
Ans: Iron gets easily rusted in the presence of moist air. Formation of rust (Fe2O3. x H2O) is a redox reaction in which Fe is oxidised to  ions. Since zinc is more reactive than iron (placed below iron in the activity series), it is oxidised to   ions instead of iron when coated over the surface of iron. Thus, zinc takes part in the redox reaction while surface of iron remains intact.

Q4. Why is anode negatively charged in an electrochemical cell?

Ans: Anode is negatively charged in an electrochemical because electrons are released at this electrode.

Q5. Why is standard hydrogen electrode called reversible electrode?
Ans: A standard hydrogen electrode is called reversible electrode because it can act both as anode as well as cathode in an electrochemical cell.

Q6. Check the feasibility of the following redox reaction with the help of electrochemical series
Ans:  The E° value of  is 0.25V while that of  

is +0.80 V. This means that nickel is placed below silver in the series and can easily reduce  ions to silver by releasing electrons. The redox reaction is therefore, feasible.

Q7. What will happen when chlorine is passed through an aqueous solution of potassium bromide?
Ans: The solution will acquire an orange colour due to the vapours of bromine that are evolved. Actually, chlorine is a stronger oxidising agent than bromine and oxidises ions (in KBr) to Br2 and itself is reduced to  ions.

Q8. What is the source of electrical energy in a galvanic cell?
Ans: In a galvanic cell, the redox reaction is of spontaneous nature. The energy as free energy  is released in the reaction. This gets converted into the electrical energy.

Q9. Knowing that:

reason out whether, 1M silver nitrate solution can be stored in copper vessel or 1M copper sulphate solution in silver vessel.
Ans:  A solution of an electrolyte can be stored in a particular vessel only in case there is no chemical reaction taking place with the material of the vessel. Now if silver nitrate solution is to be kept in copper vessel, the probable reaction will be: 

Since copper is placed below silver in the activity series, this means that it can lose electrons to ions and the chemical reaction will occur. Therefore, silver nitrate solution cannot be kept in copper vessel. Now, when copper sulphate solution is placed in silver vessel, the likely chemical reaction is:

Since Ag is placed above copper in the activity series, the chemical reaction will not take place. As a result, copper sulphate can be easily stored in silver vessel.

Q10. Determine the oxidation number of the element in the bold in the following species
(i) SiH4
(ii) BH3
(iii) BF3

(iv)
(v)
(vi)
Ans:


Q11. Identify the oxidants and reductants in the following reactions
(a)
(b)
(c)
Ans:
(a) Let us write the oxidation numbers of all the atoms of the reactants and products taking part in the reaction. CH4 is reductant (reducing agent) and Cl2 is oxidant (oxidising agent).

(b) Let us write the oxidation numbers of all the atoms of the reactants and products taking part in the reaction. C2H2O4 is reductant (reducing agent) and MnO2 is oxidant (oxidising agent).
(c) Let us write the oxidation numbers of all the atoms of the reactants and products taking part in the reaction. is reductant (reducing agent) and I2 is oxidant (oxidising agent).
(d) Let us write the oxidation numbers of atoms of all the reactants and products taking part in the reaction. is reductant (reducing agent) and Cl₂ is oxidant (oxidising agent).

Q12. Write the O.N. of all the atoms in the following well known oxidants:
(i) KMnO4
(ii) K2Cr2O7
(iii) KClO4
Ans:
(i) KMnO₄: K(+1); Mn(+7); O(-2)
(ii) K₂Cr₂O₇: K(+1); Cr(+6); O(-2) 
(iii) KClO4: K(+1); Cl(+7); O(-2)

Q13. What is oxidation according to electronic concept?
Ans: Oxidation involves loss of one or more electrons by a species during a reaction.

Q14. Define reducing agent.
Ans: A species which loses electrons as a result of oxidation is a reducing agent.

Q15. Arrange the following in order of increasing O.N. of iodine: I2, HI, HIO2, KIO3, ICl.
Ans: The increasing order is: HI < I2 < ICl < HIO2 < KIO3.

Q16. What is the oxidation number of hydrogen in LiAlH4 ? Name a compound in which hydrogen has the same oxidation state.
Ans: In sodium hydride (NaH); O.N. of H = -1.

Q17. H2O2 changes to O2. What is the change in oxidation number of oxygen per atom?
Ans:  Change in O.N. of oxygen per atom = 1 unit.