Let's imagine two gases, A and B, separated by a wall that prevents heat transfer. When this wall is replaced with one that allows heat to flow, the pressure, volume, or both of the gases may change until they reach a balance. At this stage, there is no further energy transfer between gases A and B, indicating that they have achieved thermal equilibrium at the same temperature.
For two systems to be in equilibrium, specific conditions must be fulfilled:
According to this law, two systems in thermal equilibrium with a third system separately are in thermal equilibrium with each other. Thus, if A and B are separately in equilibrium with C, that is
If TA = TC and TB = TC, then
⇒ TA = TB
i.e., the systems A and B are also in thermal equilibrium.
Zeroth Law
In an ideal gas, there are no attractive forces between molecules, meaning intermolecular forces are absent, and the gas lacks intermolecular potential energy (Up = 0).
Therefore, the internal energy of an ideal gas is solely the sum of the kinetic energies from various types of random molecular motion, such as translational, rotational, and vibrational movements. This internal energy of an ideal gas is directly related to its temperature.
In a real gas, the intermolecular forces are significant because the gas molecules exert mutual attraction on each other. This attraction means that energy is required to alter the distances between molecules.
Therefore, the internal energy of a real gas consists of both the internal kinetic energy and the internal potential energy of the gas molecules. It is influenced by the temperature and volume of the gas.
Key points regarding internal energy in a real gas:
Macroscopic State Variable: Internal energy is a state property, depending on the gas’s pressure, volume, temperature, mass, and composition, as shown when the container is at rest in Fig. (a).
Path Independence: Internal energy depends on the system’s state, not the process or path used to reach that state.
Variable State Properties: Changes in internal energy lead to variations in the macroscopic state variables of the gas.
Exclusion of Kinetic Energy of Motion: In thermodynamics, the overall kinetic energy of the system's movement (e.g., if the gas container moves, as in Fig. (b)) does not contribute to the internal energy. Only the molecular motions within the gas matter for internal energy.
Problem 1. When a piece of ice is placed on your hand, why do you feel a cold sensation?
Ans: Feeling a cold sensation when ice is placed on your hand occurs because the temperature of the ice is lower than that of your hand. Heat transfers from the warmer body (hand) to the colder body (ice).
Problem 2. Is it possible to determine the absolute value of internal energy? Why or why not?
Ans: The absolute value of internal energy cannot be precisely determined since it comprises various forms of energy, some of which are not directly measurable.
Problem 3. What factors influence the internal energy of a system?
Ans: Temperature and volume play crucial roles in altering the internal energy of a system. As the system's temperature rises, molecules gain speed, leading to increased kinetic energy.
It is the energy that exchanged between a system and its environment because of the temperature difference between them.
SI unit of heat is joule. The amount of heat Q given to a body to raise its temperature from Ti to Tf depends on mass, nature of substance and change in its temperature.
or
Change in heat,
where, m = mass of body, Ti = initial temperature
Tf = final temperature, s = specific heat of material
When we discuss "work" in thermodynamics, it refers to the work done by or on a system. For example, if a gas is in a cylinder with a movable piston and pressure p acts on the piston with area A, then the force F exerted by the gas on the piston is F= p A. If the piston moves an infinitesimally small distance dx, then the work dW done by the gas can be expressed as:
For a finite volume change from Vi to Vf, the total work done W is calculated as:
If the system expands (Vf > Vi), W is positive. Conversely, if the system contracts (Vf < Vi), W is negative.
P - V Diagram
Work is path-dependent, meaning that it varies based on the process path taken. In cyclic processes, the work done corresponds to the area enclosed by the P - V curve, which is positive if clockwise and negative if counterclockwise.
Additionally, there are four ways to change the internal energy of a system:
Example 1. Work done = 280 J, Force (F) = 51 N. Calculate the distance moved by the piston (s).
Ans. Formula: Work (W) = Force (F) x Distance (s)
Distance moved, s = 280 / F
s = 280 / (51 x 10)
s = 0.54 meters
Example 2. An electric heater supplies heat at 50 W and work done is 25 J/s. Find the rate of increase in internal energy.
Ans. Given: Heat supplied (Q) = 50 W, Work done (W) = 25 J/s
Internal Energy Change: Q = ΔU + W
ΔU = Q - W = 50 - 25 = 25 J/s
The internal energy increases at a rate of 25 J/s.
To understand the concept, consider the following experiment:
Place a gas-filled cylinder over a burner. Heat energy flows from the burner to the gas, which increases the internal energy of the gas.
When the piston in the cylinder is pushed upward, the gas does work as it expands, causing a decrease in its internal energy.
Experimental Arrangement
These changes can also occur in reverse. For example, if the gas is in contact with something colder, heat will flow out, reducing its temperature and internal energy. If the piston is pushed downward, work is done on the gas, increasing its internal energy.
Heat and work are two different ways to transfer energy and change the internal energy of a system. Heat refers to energy in transit, not a state variable. The system's state is described by internal energy.
In summary, heat and work are not state variables; they are energy transfer methods that change the system's internal energy.
The first law of thermodynamics is important because it helps determine how much work can be done by transferring a certain amount of heat energy in a thermodynamic process. However, it has some limitations:
If an amount of heat ΔQ is needed to change its temperature by ΔT, then heat capacity can be defined as:
Heat capacity is numerically equal to the heat energy required to change the temperature of a body by unity. Its unit is J/K. Different amounts of heat may be needed for a unit rise in temperature at different temperatures.
The amount of heat required to change the temperature of unit mass of a substance by unity is known as specific heat capacity of heat substance.
Specific heat capacity,
where, s = specific heat capacity of the substance.
It depends on the nature of substance and its temperature. Its unit J/kg-K. Heat capacity per kg is known as specific heat capacity.
Heat capacity per mole is known as molar specific heat capacity.
where, μ = number of moles.
The amount of heat required to raise the temperature of one gram mole of a substance through a unit is called molar specific heat capacity of the substance.
C depends on the nature of the substance, its temperature and the conditions under which heat is supplied. Its unit is J/mol-K.
Using the law of equipartition of energy, we can predict molar specific heat capacities of solids. In a solid consisting of N-atoms, the energy corresponding to vibration in each dimension about the mean position is given by
Then, the average energy in three dimensions is 3KBT. For one mole of a solid, the total energy is
Now, at constant pressure
Since, for a solid, ΔV is negligible.
Therefore, by using Eq. (ii)
In old times, calorie was used as a unit of heat. It was initially defined as the amount of heat required to raise the temperature of 1 g of water by 1°C. Later, it was observed that the specific heat of water varies slightly with temperature, as shown in the figure below.Variation of specific heat capacity of water with temperature
Specifically, one calorie is defined to be the amount of heat required to raise the temperature of 1 g of water from 14.5°C to 15.5°C.
Since heat is a form of energy, the joule (J) is preferred as the unit of heat in the SI system. The specific heat capacity of water in SI units is 4186 J/kg-K or 4.186 J/g-K.
The mechanical equivalent of heat is defined as the amount of work needed to produce 1 calorie of heat. It acts as a conversion factor:
1 calorie (heat energy) ≈ 4.186 J ≈ 4.2 J.
For gases, specific heat capacity depends on the process or condition of heat exchange between the gas and its surroundings. There are two main specific heat capacities for a gas:
Molar heat capacity at constant volume (Cₚ):
Molar heat capacity at constant pressure (Cᵥ):
Note: For a gas, Cₚ > Cᵥ. At constant pressure, more heat is required to increase the temperature by 1°C (or 1 K) than at constant volume.
We can establish the relation between specific heat capacity at constant volume (Cv) and specific heat capacity at constant pressure (Cp) of a gas. For an ideal gas, the relation between Cp and Cv is:
This relation is known as Mayer's Formula.
To establish the relation, we begin with the first law of thermodynamics for 1 mole of the gas:
If heat ΔQ is absorbed at constant volume, then pΔV=0 and ΔQ = CvΔT for one mole of a gas ΔV=0.
Then,
where the subscript V is dropped in the last step, since U of an ideal gas depends only on temperature, not on volume.
Now, heat ΔQ is absorbed at constant pressure, then
The subscript p can be dropped from the first term since U of an ideal gas depends only on T, not on pressure.
Now, by using Eq. (ii), we have
For one mole of an ideal gas, we can write pV=RT.
If the pressure is kept constant,
From Eqs. (iii) and (iv), we get
Here, Cp and Cv are molar specific heat capacities of an ideal gas at constant pressure and volume, respectively and R is the universal gas constant.
The ratio of Cp and Cv is notified by γ:
It is also known as heat capacity ratio, then
Thermodynamic State Variables refer to the properties that define the state of a thermodynamic system at equilibrium. These include pressure, volume, temperature, and mass.
A thermodynamic system may not always start in a state of equilibrium. However, given enough time, it can achieve both mechanical and thermal equilibrium. For instance, consider the gases involved in an explosive chemical reaction, such as petrol vapour mixed with air and ignited by a spark. Initially, these gases are not in equilibrium. Over time, however, they reach a uniform temperature and pressure, thereby attaining equilibrium with their surroundings.(a) Partition in the box is suddenly removed leading to free expansion of the gas
(b) A mixture of gases undergoing an explosive chemical reaction
State variables are interconnected, and the relationship between them is called the equation of state. For example, an ideal gas follows the equation pV=μRT, where only two variables (like p and V or T and V) need to be fixed to define the system. A pressure-volume curve at constant temperature is called an isotherm.
Extensive and Intensive State Variables
State variables are either extensive or intensive.
Extensive Variables depend on system size, such as internal energy, volume, and total mass. Dividing a system in half also halves these values.
Intensive Variables are independent of system size, such as pressure, temperature, and density.
”Iso” means the same, and ”baric” means pressure.
PV Curve
Practically, it is not possible to attain an ideal constant and constant pressure. An isobaric process is one in which the pressure is constant. The quantity of the gas in an isobaric process remains constant and the work done by the system is directly promotional to the change in volume or temperature of the system.
The process, during which the volume of the system remains constant, is an isochoric process. Heating of a gas in a closed cylinder is an example of the isochoric process. The change in temperature for a given amount of heat is determined by the specific heat of the gas at a constant volume.
Work done in an isochoric process
W = ∫ PdV
Here, dV = 0
Therefore, W = 0
In an isothermal process, there is no change in temperature, that means the temperature remains constant.Like when hot water is kept in a thermos flask, if we remove a certain quantity of water from the flask, but keep its temperature constant then the process is said to be an isothermal process.
The process, during which the heat content of the system remains constant, is an adiabatic process. During this process, heat neither enters the system nor leaves the system.
For an adiabatic process,
ΔQ = 0
Then according to the first law of thermodynamics,
ΔU + ΔW = ΔQ = 0
where, Q is the heat supplied to the system and W is the work done by the system and U is the internal energy of the system.
When a process is which system remains close to an equilibrium state at each time, such process will be termed as the quasi-static process or quasi-equilibrium process. For example, if a person is coming down from roof to ground floor with the help of ladder steps then it is a quasi-static process. But if he jumps from roof to ground floor then it will not be a quasi-static process.
Q1. The process in which the internal energy of the system remains constant is:
(a) Adiabatic
(b) Isobaric
(c) Isochoric
(d) Isothermal
Ans: (d)
Solution: Internal energy is a function of temperature only. Therefore, in case of an isothermal process, it will be constant.
The second law of thermodynamics gives a fundamental limitation to the efficiency of a heat engine and the coefficient of performance of a refrigerator. It says that efficiency of a heat engine can never be unity (or 100%). This implies that heat released to the cold reservoir can never be made zero.
Kelvin’s Statement
It is impossible to obtain a continuous supply of work from a body by cooling it to a temperature below the coldest of its surroundings.
Clausius’ Statement
It is impossible to transfer heat from a lower temperature body to a higher temperature body without use of an external agency.
Planck’s Statement
It is impossible to construct a heat engine that will convert heat completely into work. All these statements are equivalent as one can be obtained from the other.
Entropy
Entropy is a physical quantity that remains constant during a reversible adiabatic change.
Change in entropy is given by dS = δQ / T
where, δQ = heat supplied to the system
and T = absolute temperature.
Entropy of a system never decreases, i.e., dS ≥ 0.
Entropy of a system increases in an irreversible process.
Here is the table for significance, limitations and applications for first and second law of thermodynamics:
A thermodynamic process is reversible if the process can return back in such a that both the system and the surroundings return to their original states, with no other change anywhere else in the universe. It means both system and surroundings are returned to their initial states at the end of the reverse process.
In the figure above, the system has undergone a change from state 1 to state 2. The reversible process can reverse completely and there is no trace left to show that the system had undergone thermodynamic change. During the reversible process, all the changes in state that occur in the system are in thermodynamic equilibrium with each other.
The process is internally reversible if no irreversibilities occur within the boundaries of the system. In these processes, a system undergoes through a series of equilibrium states, and when the process reverses, the system passes through exactly the same equilibrium states while returning to its initial state.
In externally reversible process no irreversibilities occur outside the system boundaries during the process. Heat transfer between a reservoir and a system is an externally reversible process if the surface of contact between the system and reservoir is at the same temperature.
A process can be reversible only when its satisfying two conditions
In simple words, the process which can reverse back completely is a reversible process. This means that the final properties of the system can perfectly reverse back to the original properties. The process can be perfectly reversible only if the changes in the process are infinitesimally small. In practical situations it is not possible to trace these extremely small changes in extremely small time, hence the reversible process is also an ideal process. The changes that occur during the reversible process are in equilibrium with each other.
Irreversible processes are a result of straying away from the curve, therefore decreasing the amount of overall work done. An irreversible process is a thermodynamic process that departs from equilibrium. In terms of pressure and volume, it occurs when the pressure (or the volume) of a system changes dramatically and instantaneously that the volume (or the pressure) do not have the time to reach equilibrium.
A classic example of an irreversible process is allowing a certain volume of gas to release into a vacuum. By releasing pressure on a sample and allowing it to occupy a large space, the system and surroundings are not in equilibrium during the expansion process.
Here little work occurs. However, there is a requirement of significant work, with a corresponding amount of energy dissipation as heat flows to the environment. This is in order to reverse the process.
A heat energy engine is a device which converts heat energy into mechanical energy.
Heat Engine
Carnot devised an ideal cycle of operation for a heat engine, called Carnot Cycle.
Therefore, efficiency of the cycle is,
A Carnot’s cycle contains the following four processes
(i) Isothermal expansion (AB)
(ii) Adiabatic expansion (BC)
(iii) Isothermal compression (CD)
(iv) Adiabatic compression (DA)
The net work done per cycle by the engine is numerically equal to the area of the loop representing the Carnot’s cycle .
After doing the calculations for different processes, we can show that
[Efficiency of Carnot engine is maximum (not 1000/0) for given temperatures T1 and T2. But still Carnot engine is not a practical engine because many ideal situations have been assumed while designing this engine which can practically not be obtained.]
A refrigerator or heat pump is a device used for cooling things. It absorb heat from sink at lower temperature and reject a larger amount of heat to source at higher temperature.
Coefficient of performance of refrigerator is given by
where Q2 is heat absorbed from the sink, Q1 is heat rejected to source and T1 and T2 are temperatures of source and sink.
Relation between efficiency (η) and coefficient of performance (β)
Coefficient of Performance of Carnot Engine
For Carnot refrigerator,
So, Coefficient of performance,
where, T1 = temperature of surroundings,
T2 = temperature of cold body.
It is clear that β=0 when T2=0, i.e. the coefficient of performance will be zero, if the cold body is at the temperature equal to absolute zero.
Example 3: At 500°C, a reversible engine absorbs heat from a reservoir and sends it to the sink at 120°C. To perform usable mechanical work at a rate of 700 watt, how many calories per second must be extracted from the reservoir? (Given, 1 cal.= 4.2 J)
Sol: Given that,
Temperature of the source, T1=500°C = (500+273)K = 773K
Temperature of the sink, T2 = 120°C = (120+273)K = 393K
Work done,
Heat extracted from reservoir, Q1 = ?
To solve this problem we need to apply the concept of efficiency incase of a reversible engine. According to it, we can write efficiency as,
After putting the values of the variables, we get:
The efficiency of the reversible is also given as,Or, we can also write it as,
After putting the values, we get:
Hence, the heat extracted from the reservoir is 338.73 cal/sec.
Example 4: When the source temperature is 220°C, the adiabatic compression ratio in a Carnot reversible cycle is 8. Determine the temperature of the sink. (Given γ=1.5)
Sol: Given that,
Source temperature, T1 = 220 + 273 = 493K
Adiabatic compression ratio,
Temperature of the sink, T2 = ?
To solve this problem, we have to apply the concept of adiabatic change. Now, according to this concept we are able to write,
On further simplification,
Hence, the temperature of the sink is −98.7° C.
119 videos|494 docs|98 tests
|
1. What is the Zeroth Law of Thermodynamics and why is it important? | ![]() |
2. How do heat, internal energy, and work relate to each other in thermodynamics? | ![]() |
3. What are the different types of thermodynamic processes? | ![]() |
4. What is the significance of the First Law of Thermodynamics? | ![]() |
5. How does the Second Law of Thermodynamics apply to real-world processes? | ![]() |