# Adding and Subtracting Mixed Numbers With Unlike Denominators
Section A: Multiple Choice Questions
Q1: What is the sum of \(2\frac{1}{3}\) and \(1\frac{1}{4}\)? (a) \(3\frac{7}{12}\) (b) \(3\frac{2}{7}\) (c) \(3\frac{5}{12}\) (d) \(3\frac{1}{2}\)
Solution:
Ans: (a) Explanation: First, find the least common denominator (LCD) of 3 and 4, which is 12. Convert the fractions: \(\frac{1}{3} = \frac{4}{12}\) and \(\frac{1}{4} = \frac{3}{12}\). Add the whole numbers: \(2 + 1 = 3\). Add the fractions: \(\frac{4}{12} + \frac{3}{12} = \frac{7}{12}\). The sum is \(3\frac{7}{12}\).
Q2: What is \(5\frac{2}{5} - 2\frac{1}{10}\)? (a) \(3\frac{3}{10}\) (b) \(3\frac{1}{5}\) (c) \(3\frac{1}{2}\) (d) \(3\frac{2}{5}\)
Solution:
Ans: (a) Explanation: The LCD of 5 and 10 is 10. Convert \(\frac{2}{5} = \frac{4}{10}\). Now subtract: \(5\frac{4}{10} - 2\frac{1}{10}\). Subtract whole numbers: \(5 - 2 = 3\). Subtract fractions: \(\frac{4}{10} - \frac{1}{10} = \frac{3}{10}\). The answer is \(3\frac{3}{10}\).
Q3: Which of the following shows the correct first step when adding \(4\frac{1}{6}\) and \(3\frac{2}{3}\)? (a) Find the LCD of 6 and 3 (b) Add 4 and 3 to get 7 (c) Convert both mixed numbers to improper fractions (d) Multiply the denominators
Solution:
Ans: (a) Explanation: When adding mixed numbers with unlike denominators, the first step is to find the least common denominator (LCD) so the fractions can be rewritten with the same denominator. While option (c) is also a valid approach, finding the LCD is the most direct first step for this method.
Q4: What is \(6\frac{1}{4} - 2\frac{5}{8}\)? (a) \(3\frac{5}{8}\) (b) \(4\frac{5}{8}\) (c) \(3\frac{3}{8}\) (d) \(4\frac{1}{8}\)
Solution:
Ans: (a) Explanation: The LCD of 4 and 8 is 8. Convert \(\frac{1}{4} = \frac{2}{8}\). Now we have \(6\frac{2}{8} - 2\frac{5}{8}\). Since \(\frac{2}{8}\) is less than \(\frac{5}{8}\), we need to regroup. Borrow 1 from 6: \(6\frac{2}{8} = 5\frac{10}{8}\). Now subtract: \(5\frac{10}{8} - 2\frac{5}{8} = 3\frac{5}{8}\).
Q5: What is the sum of \(1\frac{2}{3}\) and \(2\frac{3}{4}\)? (a) \(4\frac{5}{12}\) (b) \(3\frac{5}{12}\) (c) \(4\frac{1}{12}\) (d) \(3\frac{5}{7}\)
Solution:
Ans: (a) Explanation: The LCD of 3 and 4 is 12. Convert the fractions: \(\frac{2}{3} = \frac{8}{12}\) and \(\frac{3}{4} = \frac{9}{12}\). Add the whole numbers: \(1 + 2 = 3\). Add the fractions: \(\frac{8}{12} + \frac{9}{12} = \frac{17}{12}\). Since \(\frac{17}{12}\) is an improper fraction, convert it: \(\frac{17}{12} = 1\frac{5}{12}\). Add to the whole number: \(3 + 1\frac{5}{12} = 4\frac{5}{12}\).
Q6: What is \(7\frac{1}{6} - 3\frac{2}{3}\)? (a) \(3\frac{1}{2}\) (b) \(4\frac{1}{2}\) (c) \(3\frac{3}{6}\) (d) \(4\frac{1}{6}\)
Solution:
Ans: (a) Explanation: The LCD of 6 and 3 is 6. Convert \(\frac{2}{3} = \frac{4}{6}\). Now we have \(7\frac{1}{6} - 3\frac{4}{6}\). Since \(\frac{1}{6} < \frac{4}{6}\),="" we="" need="" to="">regroup. Borrow 1 from 7: \(7\frac{1}{6} = 6\frac{7}{6}\). Subtract: \(6\frac{7}{6} - 3\frac{4}{6} = 3\frac{3}{6}\). Simplify: \(\frac{3}{6} = \frac{1}{2}\), so the answer is \(3\frac{1}{2}\).
Q7: The least common denominator of \(\frac{3}{8}\) and \(\frac{5}{12}\) is: (a) 24 (b) 96 (c) 20 (d) 48
Solution:
Ans: (a) Explanation: To find the least common denominator (LCD), we find the least common multiple (LCM) of 8 and 12. Multiples of 8: 8, 16, 24, 32... Multiples of 12: 12, 24, 36... The smallest common multiple is 24.
Q8: What is \(5\frac{3}{10} + 2\frac{1}{5}\)? (a) \(7\frac{1}{2}\) (b) \(7\frac{4}{15}\) (c) \(7\frac{5}{10}\) (d) \(7\frac{2}{5}\)
Solution:
Ans: (a) Explanation: The LCD of 10 and 5 is 10. Convert \(\frac{1}{5} = \frac{2}{10}\). Add whole numbers: \(5 + 2 = 7\). Add fractions: \(\frac{3}{10} + \frac{2}{10} = \frac{5}{10}\). Simplify: \(\frac{5}{10} = \frac{1}{2}\). The answer is \(7\frac{1}{2}\).
Section B: Fill in the Blanks
Q9: The first step in adding mixed numbers with unlike denominators is to find the __________.
Solution:
Ans: least common denominator (LCD) or common denominator Explanation: Before adding or subtracting fractions with unlike denominators, we must find the least common denominator (LCD) to rewrite the fractions with the same denominator.
Q10: When subtracting \(4\frac{1}{8} - 1\frac{5}{8}\), you must __________ because the fraction in the first mixed number is smaller than the fraction in the second mixed number.
Solution:
Ans: regroup or borrow Explanation: When the fraction part of the first mixed number is smaller than the fraction part being subtracted, we must regroup (or borrow) 1 from the whole number and add it to the fraction.
Q11: The least common denominator of 4 and 6 is __________.
Solution:
Ans: 12 Explanation: The least common multiple (LCM) of 4 and 6 is 12. Multiples of 4: 4, 8, 12, 16... Multiples of 6: 6, 12, 18... The smallest common multiple is 12.
Q12: After adding \(3\frac{5}{6} + 2\frac{5}{6}\), the sum is \(5\frac{10}{6}\), which simplifies to __________.
Solution:
Ans: \(6\frac{2}{3}\) Explanation: The improper fraction \(\frac{10}{6}\) can be converted to \(1\frac{4}{6}\), which simplifies to \(1\frac{2}{3}\). Adding this to 5 gives \(6\frac{2}{3}\).
Q13: When converting \(\frac{3}{5}\) to an equivalent fraction with a denominator of 15, the numerator becomes __________.
Solution:
Ans: 9 Explanation: To convert \(\frac{3}{5}\) to a denominator of 15, we multiply both numerator and denominator by 3: \(\frac{3 × 3}{5 × 3} = \frac{9}{15}\). The numerator is 9.
Ans: \(2\frac{2}{3}\) Explanation: Since \(\frac{1}{3} < \frac{2}{3}\),="" we="" must="">regroup: \(8\frac{1}{3} = 7\frac{4}{3}\). Now subtract: \(7\frac{4}{3} - 5\frac{2}{3} = 2\frac{2}{3}\).
Section C: Word Problems
Q15: Maria walked \(2\frac{1}{4}\) miles on Monday and \(1\frac{2}{3}\) miles on Tuesday. How many miles did she walk in total?
Solution:
Ans: Step 1: Find the LCD of 4 and 3, which is 12. Step 2: Convert the fractions: \(\frac{1}{4} = \frac{3}{12}\) and \(\frac{2}{3} = \frac{8}{12}\). Step 3: Add the whole numbers: \(2 + 1 = 3\). Step 4: Add the fractions: \(\frac{3}{12} + \frac{8}{12} = \frac{11}{12}\). Final Answer: \(3\frac{11}{12}\) miles
Q16: A recipe calls for \(3\frac{1}{2}\) cups of flour. If Sarah only has \(1\frac{3}{4}\) cups of flour, how much more flour does she need?
Solution:
Ans: Step 1: Find the LCD of 2 and 4, which is 4. Step 2: Convert: \(\frac{1}{2} = \frac{2}{4}\), so we have \(3\frac{2}{4} - 1\frac{3}{4}\). Step 3: Since \(\frac{2}{4} < \frac{3}{4}\),="" regroup:="" \(3\frac{2}{4}=""> Step 4: Subtract: \(2\frac{6}{4} - 1\frac{3}{4} = 1\frac{3}{4}\). Final Answer: \(1\frac{3}{4}\) cups
Q17: Jacob had \(5\frac{1}{3}\) feet of ribbon. He used \(2\frac{3}{4}\) feet for a project. How much ribbon does he have left?
Solution:
Ans: Step 1: Find the LCD of 3 and 4, which is 12. Step 2: Convert the fractions: \(\frac{1}{3} = \frac{4}{12}\) and \(\frac{3}{4} = \frac{9}{12}\). Step 3: We have \(5\frac{4}{12} - 2\frac{9}{12}\). Since \(\frac{4}{12} < \frac{9}{12}\),="" regroup:="" \(5\frac{4}{12}=""> Step 4: Subtract: \(4\frac{16}{12} - 2\frac{9}{12} = 2\frac{7}{12}\). Final Answer: \(2\frac{7}{12}\) feet
Q18: Emma practiced piano for \(1\frac{3}{5}\) hours on Saturday and \(2\frac{1}{10}\) hours on Sunday. What is the total time she practiced over the weekend?
Solution:
Ans: Step 1: Find the LCD of 5 and 10, which is 10. Step 2: Convert: \(\frac{3}{5} = \frac{6}{10}\). Step 3: Add the whole numbers: \(1 + 2 = 3\). Step 4: Add the fractions: \(\frac{6}{10} + \frac{1}{10} = \frac{7}{10}\). Final Answer: \(3\frac{7}{10}\) hours
Q19: A board is \(6\frac{1}{2}\) feet long. If \(3\frac{5}{6}\) feet are cut off, how much of the board is left?
Solution:
Ans: Step 1: Find the LCD of 2 and 6, which is 6. Step 2: Convert: \(\frac{1}{2} = \frac{3}{6}\), so we have \(6\frac{3}{6} - 3\frac{5}{6}\). Step 3: Since \(\frac{3}{6} < \frac{5}{6}\),="" regroup:="" \(6\frac{3}{6}=""> Step 4: Subtract: \(5\frac{9}{6} - 3\frac{5}{6} = 2\frac{4}{6}\). Step 5: Simplify: \(\frac{4}{6} = \frac{2}{3}\). Final Answer: \(2\frac{2}{3}\) feet
Q20: Tom ran \(4\frac{2}{3}\) miles in the morning and \(2\frac{3}{4}\) miles in the evening. How many more miles did he run in the morning than in the evening?
Solution:
Ans: Step 1: Find the LCD of 3 and 4, which is 12. Step 2: Convert the fractions: \(\frac{2}{3} = \frac{8}{12}\) and \(\frac{3}{4} = \frac{9}{12}\). Step 3: We have \(4\frac{8}{12} - 2\frac{9}{12}\). Since \(\frac{8}{12} < \frac{9}{12}\),="" regroup:="" \(4\frac{8}{12}=""> Step 4: Subtract: \(3\frac{20}{12} - 2\frac{9}{12} = 1\frac{11}{12}\). Final Answer: \(1\frac{11}{12}\) miles
The document Worksheet (with Solutions): Adding and Subtracting Mixed Numbers With Unlike Denominators is a part of the Grade 5 Course Math Grade 5.
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