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Vandana ChopraEduRev Chemistry |
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Vandana Chopra
EduRev Chemistry
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Content, tests & courses saved by you for accessing later. (visible to you only)
Top Scoring Tests by Vandana
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Rated 5 
by Vandana
by Vandana | Gauge Pressure, Absolute Pressure, and Pressure Measurement Doc | 10 pages |  |
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Discussed Questions
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Vandana Chopra upvoted • 3 weeks ago |
What is the sequence of reagents that will accomplish the synthesis of the following aromatic amine from benzene?
- a)CH3Cl, AlCl3; HNO3, H2SO4; H2
- b)CH3Cl, AlCl3; HNO3, H2SO4; Fe, HCl; NaOH
- c)HNO3, H2SO4; Fe, HCl; NaOH; CH3Cl, AlCl3
- d)HNO3, H2SO4; CH3Cl, AlCl3; Fe, HCl; NaOH
Correct answer is option 'B'. Can you explain this answer?
What is the sequence of reagents that will accomplish the synthesis of the following aromatic amine from benzene?
a)
CH3Cl, AlCl3; HNO3, H2SO4; H2
b)
CH3Cl, AlCl3; HNO3, H2SO4; Fe, HCl; NaOH
c)
HNO3, H2SO4; Fe, HCl; NaOH; CH3Cl, AlCl3
d)
HNO3, H2SO4; CH3Cl, AlCl3; Fe, HCl; NaOH
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Edurev.iitjam answered |
Electrophilic Aromatic Substitution of the methyl group with lewis acid leads to toluene. Through nitration, the nitro group is added then the reduction of nitro group leads to the amine.
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Vandana Chopra upvoted • Feb 12, 2025 |
Find out the correct option which can be replaced in place of the underlined word in the given sentence. u The fugitive economic offender was finally stopped at the delhi airport ?- a)Stopping
- b)Apprehended
- c)Comprehended
- d)No improvement
Correct answer is option 'C'. Can you explain this answer?
Find out the correct option which can be replaced in place of the underlined word in the given sentence. u The fugitive economic offender was finally stopped at the delhi airport ?
a)
Stopping
b)
Apprehended
c)
Comprehended
d)
No improvement
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Jaya Sen answered |
When a fugitive is caught, the appropriate word used is comprehend.
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Vandana Chopra upvoted • Feb 10, 2025 |
In the trigonal bipyramidal crystal field, the d orbital with the highest energy is:- a)dxy
- b)
- c)dyx
- d)
Correct answer is option 'D'. Can you explain this answer?
In the trigonal bipyramidal crystal field, the d orbital with the highest energy is:
a)
dxy
b)
c)
dyx
d)
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Edurev.iitjam answered |
- The trigonal bipyramidal crystal field splits the d orbitals into different energy levels.
- The dz2 orbital has the highest energy because it points along the z-axis, which aligns with the axial positions of the trigonal bipyramidal geometry.
- These axial positions experience more repulsion, increasing the energy of the dz
- Other orbitals, like dxy and dyx, experience less direct interaction with ligands, leading to lower energy levels.
The difference between the equatorial and polar diameters of the Earth is _____
Correct answer is '43'. Can you explain this answer?
The difference between the equatorial and polar diameters of the Earth is _____
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Vandana Chopra answered • Feb 07, 2025 |
The Difference in Diameters
The Earth is not a perfect sphere; it is an oblate spheroid. This means that its diameter is slightly larger at the equator compared to the poles. The difference in these diameters is known to be approximately 43 kilometers.
Equatorial vs. Polar Diameter
- Equatorial Diameter:
- The equatorial diameter of the Earth is about 12,... more
The Earth is not a perfect sphere; it is an oblate spheroid. This means that its diameter is slightly larger at the equator compared to the poles. The difference in these diameters is known to be approximately 43 kilometers.
Equatorial vs. Polar Diameter
- Equatorial Diameter:
- The equatorial diameter of the Earth is about 12,... more
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Vandana Chopra upvoted • Feb 01, 2025 |
Which of the following pairs of electronic configuration of high–spin transition metal ions (3d) in an octahedral field undergo a substantial Jahn–Teller distortion:- a)d3, d9
- b)d4, d9
- c)d5 , d9
- d)d6 , d9
Correct answer is option 'B'. Can you explain this answer?
Which of the following pairs of electronic configuration of high–spin transition metal ions (3d) in an octahedral field undergo a substantial Jahn–Teller distortion:
a)
d3, d9
b)
d4, d9
c)
d5 , d9
d)
d6 , d9
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Asf Institute answered |
Jahn-Teller Distortion in Highspin Transition Metal Ions
The Jahn-Teller effect is a phenomenon observed in high-spin transition metal ions with partially filled d-orbitals in an octahedral field. It occurs due to the interaction between electrons and the degenerate molecular orbitals in the octahedral crystal field.
Explanation:
- Highspin transition metal ions have partially filled d-orbitals and exhibit strong electron-electron repulsion.
- When placed in an octahedral field, the d-orbitals split into two sets of degenerate orbitals, known as t2g and eg.
- In highspin ions, the electrons occupy the t2g orbitals before the eg orbitals due to the Hund's rule.
- However, this arrangement is not energetically favorable as the t2g orbitals are more stable than the eg orbitals.
- The Jahn-Teller effect occurs when the degeneracy of the eg orbitals is lifted by a distortion of the octahedral field, leading to a lowering of the energy of the system.
- The distortion can be either elongation or compression of the octahedral field along one of the axes.
- The distortion causes the electrons to occupy the lower energy eg orbital, resulting in a non-degenerate ground state.
- Only those pairs of electronic configurations of highspin transition metal ions that exhibit the Jahn-Teller effect undergo substantial distortion.
- Option 'B' is correct as it represents the pair of electronic configurations d4 and d9, which exhibit the Jahn-Teller effect. The d4 ion has two electrons in the eg orbitals and two in the t2g orbitals, while the d9 ion has one electron in the eg orbitals and four in the t2g orbitals. Both these ions have partially filled eg orbitals, which are energetically unstable and undergo Jahn-Teller distortion to lower the energy.
The Jahn-Teller effect is a phenomenon observed in high-spin transition metal ions with partially filled d-orbitals in an octahedral field. It occurs due to the interaction between electrons and the degenerate molecular orbitals in the octahedral crystal field.
Explanation:
- Highspin transition metal ions have partially filled d-orbitals and exhibit strong electron-electron repulsion.
- When placed in an octahedral field, the d-orbitals split into two sets of degenerate orbitals, known as t2g and eg.
- In highspin ions, the electrons occupy the t2g orbitals before the eg orbitals due to the Hund's rule.
- However, this arrangement is not energetically favorable as the t2g orbitals are more stable than the eg orbitals.
- The Jahn-Teller effect occurs when the degeneracy of the eg orbitals is lifted by a distortion of the octahedral field, leading to a lowering of the energy of the system.
- The distortion can be either elongation or compression of the octahedral field along one of the axes.
- The distortion causes the electrons to occupy the lower energy eg orbital, resulting in a non-degenerate ground state.
- Only those pairs of electronic configurations of highspin transition metal ions that exhibit the Jahn-Teller effect undergo substantial distortion.
- Option 'B' is correct as it represents the pair of electronic configurations d4 and d9, which exhibit the Jahn-Teller effect. The d4 ion has two electrons in the eg orbitals and two in the t2g orbitals, while the d9 ion has one electron in the eg orbitals and four in the t2g orbitals. Both these ions have partially filled eg orbitals, which are energetically unstable and undergo Jahn-Teller distortion to lower the energy.
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Vandana Chopra upvoted • Jan 30, 2025 |
Proton decoupled 13C NMR spectrum of a bicyclooctane (C8H14) exhibits only two signals. The structure of the compound is:- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
Proton decoupled 13C NMR spectrum of a bicyclooctane (C8H14) exhibits only two signals. The structure of the compound is:
a)
b)
c)
d)
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Asf Institute answered |
has Plane of Symmetry so, show two signals.If A=[3,-2][2,-1]is a2×2 matrix then find value of A^20?
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Vandana Chopra answered • Jan 04, 2025 |
To find A^20 for the matrix A = [3, -2; 2, -1], we can use the method of diagonalization. Here’s a step-by-step explanation.
Step 1: Find Eigenvalues
- Calculate the characteristic polynomial:
det(A - λI) = 0
- For A = [3, -2; 2, -1], we have:
(3-λ)(-1-λ) - (-2)(2) = 0
This simplifies to:
λ^2 - 2λ + 1 = 0
- The eigenvalues are λ = 1 (multipl... more
Step 1: Find Eigenvalues
- Calculate the characteristic polynomial:
det(A - λI) = 0
- For A = [3, -2; 2, -1], we have:
(3-λ)(-1-λ) - (-2)(2) = 0
This simplifies to:
λ^2 - 2λ + 1 = 0
- The eigenvalues are λ = 1 (multipl... more
?
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Vandana Chopra answered • Nov 12, 2024 |
Understanding Root Mean Square Velocity
The root mean square (RMS) velocity is a measure of the speed of particles in a gas. It is derived from the kinetic theory of gases, which relates the temperature of a gas to the average kinetic energy of its molecules.
RMS Velocity Formula
The RMS velocity (v_rms) can be expressed as:
- v_rms = sqrt(3RT/M)
Where:
... more
The root mean square (RMS) velocity is a measure of the speed of particles in a gas. It is derived from the kinetic theory of gases, which relates the temperature of a gas to the average kinetic energy of its molecules.
RMS Velocity Formula
The RMS velocity (v_rms) can be expressed as:
- v_rms = sqrt(3RT/M)
Where:
... more
I have only 5 months.statergy within 5 months?
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Vandana Chopra answered • Sep 14, 2024 |
Define Your Goals
- Clearly outline what you want to achieve in 5 months.
- Set specific, measurable, achievable, relevant, and time-bound (SMART) goals related to your chemistry studies, such as mastering organic chemistry or acing an upcoming exam.
Create a Study Schedule
- Develop a weekly planner that allocates time for different ch... more
- Clearly outline what you want to achieve in 5 months.
- Set specific, measurable, achievable, relevant, and time-bound (SMART) goals related to your chemistry studies, such as mastering organic chemistry or acing an upcoming exam.
Create a Study Schedule
- Develop a weekly planner that allocates time for different ch... more
What are the variables of phase rule equation?
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Vandana Chopra answered • Jul 29, 2024 |
Variables of Phase Rule Equation
Phase rule equation is a fundamental concept in thermodynamics that helps in determining the number of degrees of freedom in a system at equilibrium. The equation is given by:
F = C - P + 2
Where:
- F is the number of degrees of freedom
- C is the number of components in the system
- P is the number of p... more
2 centre 2 electron bond?
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Vandana Chopra answered • Jul 06, 2024 |
2 Centre 2 Electron Bond
The 2 centre 2 electron bond is a type of chemical bond that involves two atoms sharing two electrons. This type of bond is commonly found in diatomic molecules like hydrogen (H2) and halogens (Cl2, F2, etc.). The bond is formed when two atomic orbitals overlap to share two electrons.
Formation of 2 Centre 2 Electron Bond
- In the case of... more
The 2 centre 2 electron bond is a type of chemical bond that involves two atoms sharing two electrons. This type of bond is commonly found in diatomic molecules like hydrogen (H2) and halogens (Cl2, F2, etc.). The bond is formed when two atomic orbitals overlap to share two electrons.
Formation of 2 Centre 2 Electron Bond
- In the case of... more
The number of tetrahedral angles in dichloromethane?
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Vandana Chopra answered • May 29, 2024 |
In dichloromethane, the molecular formula is CH2Cl2. To determine the number of tetrahedral angles in dichloromethane, we need to first understand the molecular structure of the compound.
- Molecular Structure:
Dichloromethane consists of a central carbon atom bonded to two chlorine atoms and two hydrogen atoms. Each chlorine atom and hydrogen atom forms a single covalent bond wi... more
- Molecular Structure:
Dichloromethane consists of a central carbon atom bonded to two chlorine atoms and two hydrogen atoms. Each chlorine atom and hydrogen atom forms a single covalent bond wi... more
Both isolated and closed systems are the same.- a)True
- b)False
- c)can not be determined
- d)none of the above
Correct answer is option 'B'. Can you explain this answer?
Both isolated and closed systems are the same.
a)
True
b)
False
c)
can not be determined
d)
none of the above
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Vandana Chopra answered • Feb 20, 2024 |
Explanation:
Isolated and closed systems are not the same in the field of thermodynamics. Let's differentiate between the two:
Isolated System:
- An isolated system does not exchange matter or energy with its surroundings.
- It does not allow the transfer of heat or work across its boundaries.
- The total energy within an isolated system remains constant.
Closed System:
- A closed system allows the exchange of energy but not matter with its surroundings.
- It permits the transfer of heat and work across its boundaries.
- The total energy within a closed system can change due to heat or work interactions.
Explanation of the Answer:
The statement that isolated and closed systems are the same is false because they have different characteristics regarding the exchange of matter and energy with the surroundings. Isolated systems do not allow any exchange, while closed systems permit the transfer of energy. It is essential to understand these distinctions to apply the appropriate thermodynamic principles in different scenarios.
An element X on exposure to moist air turns reddish-brown and a new compound Y is formed. The substance X and Y are- a)X = Fe, Y = Fe2O3
- b) X = Ag, Y = Ag2S
- c)X = Cu, Y = CuO
- d)X = Al, Y = Al2O3
Correct answer is option 'A'. Can you explain this answer?
An element X on exposure to moist air turns reddish-brown and a new compound Y is formed. The substance X and Y are
a)
X = Fe, Y = Fe2O3
b)
X = Ag, Y = Ag2S
c)
X = Cu, Y = CuO
d)
X = Al, Y = Al2O3
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Vandana Chopra answered • Feb 20, 2024 |
Explanation:
- Element X turning reddish-brown on exposure to moist air: This characteristic is a property of iron (Fe), which oxidizes in the presence of moisture in the air to form a reddish-brown compound.
- Formation of compound Y: The new compound formed, Y, is iron(III) oxide (Fe2O3), which is commonly known as rust. When iron reacts with ox... more
The half-life of the chemical reaction, A → Product, for initial reactant concentrations of 0.1 and 0.4 mol L–1 are 200 and 50 s, respectively. The order of the reaction is- a)0
- b)1
- c)2
- d)3
Correct answer is option 'C'. Can you explain this answer?
The half-life of the chemical reaction, A → Product, for initial reactant concentrations of 0.1 and 0.4 mol L–1 are 200 and 50 s, respectively. The order of the reaction is
a)
0
b)
1
c)
2
d)
3
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Vandana Chopra answered • Feb 02, 2024 |
The half-life of a chemical reaction refers to the time it takes for half of the reactants to be converted into products. It is a measure of the rate at which the reaction progresses.
The half-life of a chemical reaction, A, can be determined experimentally by measuring the concentration of A at regular intervals and plotting it on a graph. The half-life is then determined by the time i... more
The half-life of a chemical reaction, A, can be determined experimentally by measuring the concentration of A at regular intervals and plotting it on a graph. The half-life is then determined by the time i... more
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Vandana Chopra asked • Aug 17, 2023 |
Can I get the direct link to download the IIT JAM Chemistry answer key online?
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Shivani Mehta answered |
Direct Link to Download IIT JAM Chemistry Answer Key Online
To download the IIT JAM Chemistry answer key online, follow the steps below:
Step 1: Open your preferred web browser and go to the official website of IIT JAM (Joint Admission Test for M.Sc.) or use the direct link provided by EduRev.
Step 2: Look for the "Answer Key" section on the we... more
To download the IIT JAM Chemistry answer key online, follow the steps below:
Step 1: Open your preferred web browser and go to the official website of IIT JAM (Joint Admission Test for M.Sc.) or use the direct link provided by EduRev.
Step 2: Look for the "Answer Key" section on the we... more
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Vandana Chopra asked • Aug 02, 2023 |
How are the answer sheets evaluated in the IIT JAM Chemistry exam?
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Soumya Sharma answered |
Answer:
Evaluation of IIT JAM Chemistry Exam Answer Sheets
The evaluation process of the IIT JAM Chemistry exam answer sheets is carried out meticulously to ensure fairness and accuracy. The following steps are involved in evaluating the answer sheets:
Step 1: Collection of Answer Sheets
- After the examination, the answer sheets are colle... more
Evaluation of IIT JAM Chemistry Exam Answer Sheets
The evaluation process of the IIT JAM Chemistry exam answer sheets is carried out meticulously to ensure fairness and accuracy. The following steps are involved in evaluating the answer sheets:
Step 1: Collection of Answer Sheets
- After the examination, the answer sheets are colle... more
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Vandana Chopra asked • Aug 02, 2023 |
What are the important topics to focus on in Organic Chemistry for the IIT JAM exam?
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Soumya Sharma answered |
Important Topics in Organic Chemistry for the IIT JAM Exam
Organic Chemistry is a crucial section in the IIT JAM exam. It requires a strong understanding of various concepts and topics. Here are some important topics that you should focus on while preparing for the exam:
1. General Organic Chemistry:
- Structure and Bonding: Understand the concepts of hybri... more
Organic Chemistry is a crucial section in the IIT JAM exam. It requires a strong understanding of various concepts and topics. Here are some important topics that you should focus on while preparing for the exam:
1. General Organic Chemistry:
- Structure and Bonding: Understand the concepts of hybri... more
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Vandana Chopra asked • Dec 07, 2022 |
Which of the bonding orbital has greater energy comparatively?- a)Both Bonding molecular orbital and Anti-bonding molecular orbital have the same energy
- b)The energy of Bonding molecular orbital and Anti-bonding molecular orbital depends on the situation
- c)Bonding molecular orbital
- d)Anti-bonding molecular orbital
Correct answer is option 'D'. Can you explain this answer?
Which of the bonding orbital has greater energy comparatively?
a)
Both Bonding molecular orbital and Anti-bonding molecular orbital have the same energy
b)
The energy of Bonding molecular orbital and Anti-bonding molecular orbital depends on the situation
c)
Bonding molecular orbital
d)
Anti-bonding molecular orbital
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Hema answered |
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Vandana Chopra asked • Dec 04, 2022 |
In NMR spectroscopy, what is the product of Nuclear ‘g’ factor (gN), the nuclear magneton and the magnetic field strength (B0)?- a)energy of transition from alpha to beta state
- b)chemical shift
- c)spin-spin coupling constant
- d)magnetogyric ratio
Correct answer is option 'A'. Can you explain this answer?
In NMR spectroscopy, what is the product of Nuclear ‘g’ factor (gN), the nuclear magneton and the magnetic field strength (B0)?
a)
energy of transition from alpha to beta state
b)
chemical shift
c)
spin-spin coupling constant
d)
magnetogyric ratio
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Vivek Khatri answered |
In NMR spectroscopy. the product of Nuclear ‘g’ factor (gN), the nuclear magneton (βN) and the magnetic field strength (B0) gives the energy of transition from alpha to beta state. As shown below:
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Vandana Chopra asked • Nov 30, 2022 |
Which of the following is an incorrect statement?
- a)Rate of formation of (II) and (IV)would be identical
- b)Rate of formation of (I) would be slower than that of (III)
- c)Formation of (I) would show primary isotope effect
- d)Formation of (III) involves E1 reaction
Correct answer is option 'D'. Can you explain this answer?
Which of the following is an incorrect statement?
a)
Rate of formation of (II) and (IV)would be identical
b)
Rate of formation of (I) would be slower than that of (III)
c)
Formation of (I) would show primary isotope effect
d)
Formation of (III) involves E1 reaction
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Pioneer Academy answered |
Rate of formation of II and IV similar because H & D are approximately of same size.
C–H & C–D bond breaking is the part of RDS hence rate in (I) is slower than (III)
It undergoes E2 not via E1 because carbocation is not stable.
C–H & C–D bond breaking is the part of RDS hence rate in (I) is slower than (III)
It undergoes E2 not via E1 because carbocation is not stable.
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