Divyanshu Saini

EduRev Chemistry

Divyanshu Saini
EduRev Chemistry
Discussed Questions
Divyanshu Saini asked   •  Dec 27, 2018

Which of the following are correct:
  • a)
    Conductivity of a solution increases with dilution
  • b)
    Molar conductivity of a solution increases with dilution
  • c)
    Conductivity of a solution decreases with dilution
  • d)
    Molar conductivity of a solution decreases with dilution
Correct answer is option 'B,C'. Can you explain this answer?

Isha Bose answered
**Conductivity and Molar Conductivity**

Conductivity is a measure of a solution's ability to conduct electricity. It depends on the concentration of ions present in the solution. Molar conductivity, on the other hand, is a measure of the conductivity of a solution per unit concentration of solute. It is calculated by dividing the conductivity of the solution by its molar concentration.<
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Divyanshu Saini upvoted   •  Dec 22, 2018

Consider gases confined by a liquid, as shown in figure.
Density of the liquid = d (all values in SI unit)

Then
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Shreya Narayan answered
In this setup
The liquid in tube 1 has got lowered by height h1 which means that the pressure inside the tube is greater than the pressure exerted by the atmosphere. This excess pressure must be equal to the pressure exerted by h1 column of liquid of the same cross section ,therefore
Pressure inside tube 1=atmospheric pressure+h1dg
In tube 2 since the level of water is same as that
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Divyanshu Saini upvoted   •  Dec 21, 2018

 One mole of N2O4 is kept in a close container at 300K and 1 atm pressure. When it is heated to 600 K 20% of it decomposes to NO2 (g). Calculate the resultant pressure exerted on the walls of the container
  • a)
    3.4 atm
  • b)
    1.2 atm
  • c)
    2.0 atm
  • d)
    3.6 atm
Correct answer is option 'B'. Can you explain this answer?

Preeti Iyer answered
The answer is 2.4 atm
N2O4    ⇔  2NO2

1mole  0   Initial moles

-20% of 1=0.2  +2(20% of 1)=0.40  At equilibrium

1-0.2= 0.8  0.4  Moles at equilibrium

Total moles at equilibrium = 0.8+0.4 = 1.2 moles

1 mole vapour pressure = 1 atm at 300 K

Applying PV = nRT

 1xV = 1x R x 300 .... (1)

When n=1.2 moles, T = 600 K

 P x V = 1.2 x R x 600 .... (2)

Dividing (2) by (1),

PxV/(1xV) = (1.2 x R x 600)/ (1 x R x 300)

Therefore, P= 2.4 atm

Hence, resultant pressure of mixture is 2.4 atm 

Divyanshu Saini asked   •  Dec 19, 2018

An azeotropic mixture of two liquids has a boiling point higher than either of them when it:
  • a)
    Shows positive deviation from Raoult’s law.
  • b)
    Shows negative deviation from Raoult’s law.
  • c)
    Shows ideal behaviour.
  • d)
    Is saturated.
Correct answer is option 'B'. Can you explain this answer?

Rajeev Sharma answered
Azeotropic mixture of two liquids has lower B.P. if two liquids are dissolved and their boiling points will be different and they will increase either when there is one liquid the boiling point will be low.
So Option B is correct.

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