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All questions of Class 10 Physics for CTET & State TET Exam
In parallel combination, total resistance - a)decreases
- b)increases
- c)may decrease or increase according to the situation
- d)no particular observation.
Correct answer is option 'A'. Can you explain this answer?
In parallel combination, total resistance
a)
decreases
b)
increases
c)
may decrease or increase according to the situation
d)
no particular observation.
|
Raghav Bansal answered |
To find the total resistance of all components, the reciprocals of the resistances of each component are added and the reciprocal of the sum is taken.
Thus, the Total resistance will always be less than the value of the smallest resistance.
Work done is moving a unit positive test charge from one point to other inside an electric field, is called- a)potential
- b)field
- c)field intensity
- d)potential difference.
Correct answer is option 'D'. Can you explain this answer?
Work done is moving a unit positive test charge from one point to other inside an electric field, is called
a)
potential
b)
field
c)
field intensity
d)
potential difference.
|
Kiran Mehta answered |
Potential difference is the difference in electric potential energy between two points.
It is the amount of work done in moving a unit positive charge from one point to another point in an electric field. This is measured in volt.
It is the amount of work done in moving a unit positive charge from one point to another point in an electric field. This is measured in volt.
To get 2Ω resistance using only 6Ω resistors, the number of them required is- a)2
- b)3
- c)4
- d)6
Correct answer is option 'B'. Can you explain this answer?
To get 2Ω resistance using only 6Ω resistors, the number of them required is
a)
2
b)
3
c)
4
d)
6
|
Avinash Patel answered |
Three resistors of 2Ω is required to get 6Ω because resultant is more than individual so they all must be connected in series.
Substances whose atoms have more free electrons, are called - a)electrolytes
- b)conductors
- c)insulators
- d)semiconductors.
Correct answer is option 'B'. Can you explain this answer?
Substances whose atoms have more free electrons, are called
a)
electrolytes
b)
conductors
c)
insulators
d)
semiconductors.
|
Meera Rana answered |
Materials with high electron mobility (many free electrons) are called conductors, while materials with low electron mobility (few or no free electrons) are called insulators.
In an atom, particle having a positive charge is called - a)neutron
- b)proton
- c)electron
- d)ion.
Correct answer is option 'B'. Can you explain this answer?
In an atom, particle having a positive charge is called
a)
neutron
b)
proton
c)
electron
d)
ion.
|
Vikas Kumar answered |
When an atom is electrically neutral, it means that the overall charge of the atom is zero. Atoms are made up of positively charged particles called protons and negatively charged particles called electrons as well as non-charged particles called neutrons.
The effective resistance between A and B is
- a)4Ω
- b)6Ω
- c)May be 10Ω
- d)Must be 10Ω
Correct answer is option 'A'. Can you explain this answer?
The effective resistance between A and B is
a)
4Ω
b)
6Ω
c)
May be 10Ω
d)
Must be 10Ω
|
Gaurav Kumar answered |
6Ω is shorted
as current will pass from wire having no resistance
so effective resistance is 4Ω.
as current will pass from wire having no resistance
so effective resistance is 4Ω.
The path connecting two points at different potentials, to make the electric charges flow, is called electric - a)circuit
- b)current
- c)potential difference
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
The path connecting two points at different potentials, to make the electric charges flow, is called electric
a)
circuit
b)
current
c)
potential difference
d)
none of these
|
|
Raghav Bansal answered |
An electric circuit is the representation of the whole path of current and also the various devices connected in it, like Cell, Resistor, etc.
In parallel combination, resistance decreases due to increase in- a)temperature
- b)humidity
- c)length
- d)area of cross-section.
Correct answer is option 'D'. Can you explain this answer?
In parallel combination, resistance decreases due to increase in
a)
temperature
b)
humidity
c)
length
d)
area of cross-section.
|
|
Raghav Bansal answered |
In parallel combination, change in length will not be effective, therefore we consider the area of cross-section.
As we know that resistance is inversely proportional to the area of cross-section.
As we know that resistance is inversely proportional to the area of cross-section.
Thus, resistance will decrease with an increase in area of crosssection.
Calculate the current flows through the 10Ω resistor in the following circuit.
- a)1.2A
- b)0.6A
- c)0.2A
- d)2.0A
Correct answer is option 'B'. Can you explain this answer?
Calculate the current flows through the 10Ω resistor in the following circuit.
a)
1.2A
b)
0.6A
c)
0.2A
d)
2.0A
|
Sun Ray Institute answered |
In parallel, potential difference across each resistor will remain same. So, current through 10Ω resistor
Transparent medium is one :
- a)Which allows light to pass through
- b)Which absorbs most of the light
- c)Which do not allows light to pass through
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
Transparent medium is one :
a)
Which allows light to pass through
b)
Which absorbs most of the light
c)
Which do not allows light to pass through
d)
None of these
|
Imk Pathshala answered |
A transparent medium is a material that partially allows light to pass through.
When light encounters a transparent medium, it can penetrate the material and transmit through it.
Examples of transparent mediums include glass, water, and air.
Transparent mediums are essential for various applications such as optics, windows, and lenses.
With increase in temperature, resistance of a conductor - a)decreases
- b)increases
- c)may decreases or increase according to the situation
- d)no particular observation.
Correct answer is option 'B'. Can you explain this answer?
With increase in temperature, resistance of a conductor
a)
decreases
b)
increases
c)
may decreases or increase according to the situation
d)
no particular observation.
|
|
Krishna Iyer answered |
As the temperature of a metallic conductor increases, the kinetic energy of the electrons of the conductor also increases
Due to this increase in kinetic energy more obstruction is offered to the flowing electrons i.e. current.
Therefore, as more obstruction is offered to the flowing electrons, the resistance is increased.
Due to this increase in kinetic energy more obstruction is offered to the flowing electrons i.e. current.
Therefore, as more obstruction is offered to the flowing electrons, the resistance is increased.
The space around a charge in which its effect can be felt is called its
- a)potential
- b)electric field
- c)field intensity
- d)potential difference.
Correct answer is option 'B'. Can you explain this answer?
The space around a charge in which its effect can be felt is called its
a)
potential
b)
electric field
c)
field intensity
d)
potential difference.
|
|
Rajdeep Chauhan answered |
Electric Field
The space around a charge in which its effect can be felt is called its electric field. The electric field is defined as the force per unit charge experienced by a small positive test charge placed at that point.
Mathematically, the electric field E at any point in space is given by the equation:
E = F/q
where F is the force experienced by a small positive test charge q placed at that point.
The electric field is a vector quantity, meaning it has both magnitude and direction. The direction of the electric field at any point is the direction of the force that would be experienced by a small positive test charge placed at that point.
Units
The SI unit of electric field is Newtons per Coulomb (N/C).
Applications
The concept of electric field is used extensively in the study of electricity and magnetism. Some of its applications include:
- Understanding the behavior of charged particles in electric fields
- Designing and analyzing electrical circuits
- Determining the electric potential at various points in space
- Calculating the force experienced by charged particles in electric fields.
The space around a charge in which its effect can be felt is called its electric field. The electric field is defined as the force per unit charge experienced by a small positive test charge placed at that point.
Mathematically, the electric field E at any point in space is given by the equation:
E = F/q
where F is the force experienced by a small positive test charge q placed at that point.
The electric field is a vector quantity, meaning it has both magnitude and direction. The direction of the electric field at any point is the direction of the force that would be experienced by a small positive test charge placed at that point.
Units
The SI unit of electric field is Newtons per Coulomb (N/C).
Applications
The concept of electric field is used extensively in the study of electricity and magnetism. Some of its applications include:
- Understanding the behavior of charged particles in electric fields
- Designing and analyzing electrical circuits
- Determining the electric potential at various points in space
- Calculating the force experienced by charged particles in electric fields.
The near point of a hypermetropic person is 75 cm if the person uses eye glasses having power +1.0D, Calculate the distance of distinct vision for him?- a)+400cm
- b)-400cm
- c)-300cm
- d)+300cm
Correct answer is option 'C'. Can you explain this answer?
The near point of a hypermetropic person is 75 cm if the person uses eye glasses having power +1.0D, Calculate the distance of distinct vision for him?
a)
+400cm
b)
-400cm
c)
-300cm
d)
+300cm
|
Ishan Choudhury answered |
u = -75 cm
P = 1/f
f = 1 m = 100 cm
So, by lens formula ;
1/f = 1/v - 1/ u
So, 1/ v = 1/f +1/u
1/ v = 1/100 + (-1/75)
1/v = -1/300
v = -300 cm
P = 1/f
f = 1 m = 100 cm
So, by lens formula ;
1/f = 1/v - 1/ u
So, 1/ v = 1/f +1/u
1/ v = 1/100 + (-1/75)
1/v = -1/300
v = -300 cm
The condition for an electric charge to flow from one point to other is that the two points must have electric- a)circuit
- b)current
- c)potential difference
- d)cell.
Correct answer is option 'C'. Can you explain this answer?
The condition for an electric charge to flow from one point to other is that the two points must have electric
a)
circuit
b)
current
c)
potential difference
d)
cell.
|
|
Arj Ufriended answered |
Flow of any particle needs a difference....suppose a river which flows from a mountain.....here there is a difference of height or altitude due to which river water flows......and as we know CURRENT:-FLOW OF CHARGES...so it also requires a difference i.e potential difference.......work done in bringing a unit positive charge from a point to the another point in the electric field is called potential difference between the two points...thats it
Electricity constituted by moving electric charges, is called- a)positive electricity
- b)negative electricity
- c)current electricity
- d)static electricity.
Correct answer is option 'C'. Can you explain this answer?
Electricity constituted by moving electric charges, is called
a)
positive electricity
b)
negative electricity
c)
current electricity
d)
static electricity.
|
|
Vikram Kapoor answered |
Electricity constituted by moving electric charge is called current.
If four resistors each of 1Ω are connected in parallel, the effective resistance will be- a)0.5Ω
- b)0.25Ω
- c)4Ω
- d)2Ω
Correct answer is option 'B'. Can you explain this answer?
If four resistors each of 1Ω are connected in parallel, the effective resistance will be
a)
0.5Ω
b)
0.25Ω
c)
4Ω
d)
2Ω
|
|
Gaurav Kumar answered |
If four resistors each of 1Ω are connected in parallel, the effective resistance will be 0.25Ω..
As, in parralel connection,
1/Reff. = 1/R1 + 1/R2 + ....
The device that maintains electric potential difference between two points is called electric- a)circuit
- b)current
- c)potential difference
- d)cell.
Correct answer is option 'D'. Can you explain this answer?
The device that maintains electric potential difference between two points is called electric
a)
circuit
b)
current
c)
potential difference
d)
cell.
|
|
Anjana Khatri answered |
The electric potential difference between the two points in an electric circuit carrying some current is the work done to move a unit charge from one point to other.
Earth wire carries- a)current
- b)voltage
- c)no current
- d)heat
Correct answer is option 'C'. Can you explain this answer?
Earth wire carries
a)
current
b)
voltage
c)
no current
d)
heat
|
|
Kiran Mehta answered |
A "grounding" wire on the other hand is a safety wire that has intentionally been connected to earth. The grounding wire does not carry electricity under normal circuit operations. It's purpose is to carry electrical current only under short circuit or other conditions that would be potentially dangerous.
Overloading is due to- a)Insulation of wire is damaged
- b)fault in the appliances
- c)accidental hike in supply voltage
- d)All of the above
Correct answer is option 'D'. Can you explain this answer?
Overloading is due to
a)
Insulation of wire is damaged
b)
fault in the appliances
c)
accidental hike in supply voltage
d)
All of the above
|
|
Rohit Sharma answered |
Overloading occurs when there is any fault in the appliances or the insulation of wire got damaged. It also occurs when there is sudden hike in supply voltage.
A lens has a power of +0.5 D. It is - a)a concave lens of focal length 5 m
- b)a convex lens of focal length 5 cm
- c)a convex lens of focal length 2 m
- d)a concave lens of focal length 2 m
Correct answer is option 'C'. Can you explain this answer?
A lens has a power of +0.5 D. It is
a)
a concave lens of focal length 5 m
b)
a convex lens of focal length 5 cm
c)
a convex lens of focal length 2 m
d)
a concave lens of focal length 2 m
|
Sanya jain answered |
Given, power of the lens = 0.5 D.
We know that the power of the lens is given by the formula:
Power (P) = 1/f, where f is the focal length of the lens.
Therefore, we can write:
0.5 D = 1/f
Solving for f, we get:
f = 1/0.5 D
f = 2 m
Hence, the focal length of the lens is 2 m.
Therefore, the correct option is (c) a convex lens of focal length 2 m.
Explanation:
A convex lens has a positive power and can converge the light rays to a point. The focal length of a convex lens is positive. When the power of the lens is given, we can find the focal length of the lens using the formula P = 1/f. Here, the power is given as 0.5 D. On substituting the values, we get the focal length as 2 m. Hence, the lens is a convex lens of focal length 2 m.
We know that the power of the lens is given by the formula:
Power (P) = 1/f, where f is the focal length of the lens.
Therefore, we can write:
0.5 D = 1/f
Solving for f, we get:
f = 1/0.5 D
f = 2 m
Hence, the focal length of the lens is 2 m.
Therefore, the correct option is (c) a convex lens of focal length 2 m.
Explanation:
A convex lens has a positive power and can converge the light rays to a point. The focal length of a convex lens is positive. When the power of the lens is given, we can find the focal length of the lens using the formula P = 1/f. Here, the power is given as 0.5 D. On substituting the values, we get the focal length as 2 m. Hence, the lens is a convex lens of focal length 2 m.
In parallel combination of electrical appliances, total electrical power- a)increases
- b)decreases
- c)may increase or decrease according to the situation
- d)no definite observation.
Correct answer is 'B'. Can you explain this answer?
In parallel combination of electrical appliances, total electrical power
a)
increases
b)
decreases
c)
may increase or decrease according to the situation
d)
no definite observation.
|
|
Gaurav Kumar answered |
As more and more resistors are added in parallel to a circuit, the equivalent resistance of the circuit decreases and the total current of the circuit increases.Therefore the power decreases.
The force acting on a unit positive test charge at a point inside an electric field is called- a)potential
- b)field
- c)field intensity
- d)potential difference.
Correct answer is 'C'. Can you explain this answer?
The force acting on a unit positive test charge at a point inside an electric field is called
a)
potential
b)
field
c)
field intensity
d)
potential difference.
|
|
Gaurav Kumar answered |
Electric Field Intensity (E): The electrostatic force acting per unit positive charge on a point in an electric field is called electric field intensity at that point.
Electric current is produced by flow of- a)electrons
- b)protons
- c)negative ions
- d)positive ions.
Correct answer is option 'A'. Can you explain this answer?
Electric current is produced by flow of
a)
electrons
b)
protons
c)
negative ions
d)
positive ions.
|
Sreemoyee Patel answered |
Electric current is electric charge in motion. It can take the form of a sudden discharge of static electricity, such as a lightning bolt or a spark between your finger and a ground light switch plate. More commonly, though, when we speak of electric current, we mean the more controlled form of electricity from generators, batteries, solar cells or fuel cells
The device which measures electric current through a conductor is called - a)ammeter
- b)voltmeter
- c)manometer
- d)water meter.
Correct answer is option 'A'. Can you explain this answer?
The device which measures electric current through a conductor is called
a)
ammeter
b)
voltmeter
c)
manometer
d)
water meter.
|
Molik answered |
Ammeter is used to measure electric current
The resistance whose V - I graph is given below is
- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
The resistance whose V - I graph is given below is
a)
b)
c)
d)
|
Prachi shukla answered |
Resistance = slope line of V-I graph
The total work done by an electrical appliance during its operation, is called electrical - a)current
- b)power
- c)potential
- d)energy.
Correct answer is option 'D'. Can you explain this answer?
The total work done by an electrical appliance during its operation, is called electrical
a)
current
b)
power
c)
potential
d)
energy.
|
|
Anjana Khatri answered |
The amount of electrical energy transferred to an appliance depends on its power and the length of time it is switched on. The amount of mains electrical energy transferred is measured in kilowatt-hours, kWh. One unit is 1 kWh.
Time rate of work done or electrical energy developed or consumed by a generator or appliance, is called electrical- a)current
- b)power
- c)potential
- d)energy.
Correct answer is option 'B'. Can you explain this answer?
Time rate of work done or electrical energy developed or consumed by a generator or appliance, is called electrical
a)
current
b)
power
c)
potential
d)
energy.
|
|
Vikram Kapoor answered |
Time rate of work done or electric energy develop or consumed by generator or appliance, is called electric power. We know, that the rate of work done per unit Time is known as power. So, here is some change ie., in terms of electricity Time rate of work done is known as electric power.
The unit of electrical energy is- a)watt (W)
- b)ampere (A)
- c)joule (J)
- d)ohm (?).
Correct answer is option 'C'. Can you explain this answer?
The unit of electrical energy is
a)
watt (W)
b)
ampere (A)
c)
joule (J)
d)
ohm (?).
|
|
Anita Menon answered |
The unit for electrical energy is the joule. The electrical unit for power is the watt. The formula calculating electrical energy then is the following formula. Electrical energy is expressed in joules, power is expressed in watts, and time is expressed in seconds.
Power voltage rating of an electric bulb is 100 W 200 V. Current drawn by it will be- a)1.0 A
- b)0.8 A
- c)0.5 A
- d)0.4 A.
Correct answer is option 'C'. Can you explain this answer?
Power voltage rating of an electric bulb is 100 W 200 V. Current drawn by it will be
a)
1.0 A
b)
0.8 A
c)
0.5 A
d)
0.4 A.
|
|
Krishna Iyer answered |
Power = voltage * current
Here, power = 100 W, voltage = 200 V
P = V*I
Therefore, 100 = 200 * I
I = 100/200 A
I = 0.5 A
Here, power = 100 W, voltage = 200 V
P = V*I
Therefore, 100 = 200 * I
I = 100/200 A
I = 0.5 A
A wire of resistance 8Ω is bent in the form of a closed circle. What is the effective resistance between the two points A and B, at the ends of any diameter of the circle ?
- a)8Ω
- b)4Ω
- c)2Ω
- d)1Ω
Correct answer is option 'C'. Can you explain this answer?
A wire of resistance 8Ω is bent in the form of a closed circle. What is the effective resistance between the two points A and B, at the ends of any diameter of the circle ?
a)
8Ω
b)
4Ω
c)
2Ω
d)
1Ω
|
Flembe Academy answered |
When a wire of 8Ω resistance is bent in the form of a closed circle, resistance of each half (semicircular) part is 8/2 Ω = 4Ω.
As these two parts are connected in parallel across points A and B, hence effective resistance will be 2Ω.
As these two parts are connected in parallel across points A and B, hence effective resistance will be 2Ω.
A point object is placed on the principal axis of a spherical mirror. The object-distance u is - a)definitely negative
- b)definitely positive
- c)positive if the object is to the left of the centre of curvature
- d)positive if the object is to the right of the centre of curvature
Correct answer is option 'A'. Can you explain this answer?
A point object is placed on the principal axis of a spherical mirror. The object-distance u is
a)
definitely negative
b)
definitely positive
c)
positive if the object is to the left of the centre of curvature
d)
positive if the object is to the right of the centre of curvature
|
|
Ritu Saxena answered |
Option ( a) is the correct answer. As the object is always placed on the left side of the mirror and according to the sign convention, it has negative value for 'so axis.
Therefore, spherical mirrors have only one reflecting surface and it will be negative only.
An object is placed before a concave lens. The image formed- a)is always erect
- b)may be erect or inverted
- c)is always inverted
- d)is always real
Correct answer is option 'A'. Can you explain this answer?
An object is placed before a concave lens. The image formed
a)
is always erect
b)
may be erect or inverted
c)
is always inverted
d)
is always real
|
|
Vivek Rana answered |
Because concave lens always produce an
Image which is always erect, diminished and virtual.
Image which is always erect, diminished and virtual.
Which of the following phenomena is not the result of total internal reflection ?- a)Twinkling of stars
- b)Mirage
- c)Looming
- d)both Looming and Twinkling of stars
Correct answer is option 'A'. Can you explain this answer?
Which of the following phenomena is not the result of total internal reflection ?
a)
Twinkling of stars
b)
Mirage
c)
Looming
d)
both Looming and Twinkling of stars
|
Pooja Shah answered |
Twinkling of stars is due to atmospheric refraction. Distant star acts like a point source of light. When the Starlight enters the earth's atmosphere it undergoes refraction continuously, due to changing refractive index ie. From rarer to denser medium.
Time rate of flow of electric charge measures electric- a)circuit
- b)current
- c)potential difference
- d)cell.
Correct answer is option 'B'. Can you explain this answer?
Time rate of flow of electric charge measures electric
a)
circuit
b)
current
c)
potential difference
d)
cell.
|
|
Ananya Das answered |
Current is defined as the amount of electric charge flowing through a cross-section of circuits in unit time.
I = Q/T
I = Q/T
SI unit of resistivity is- a)ohm/metre
- b)ohm-metre
- c)ohm/(metre)3
- d)ohm/(metre)2
Correct answer is option 'B'. Can you explain this answer?
SI unit of resistivity is
a)
ohm/metre
b)
ohm-metre
c)
ohm/(metre)3
d)
ohm/(metre)2
|
|
Krishna Iyer answered |
As resistivity of the material of a resistor of length l, cross-section area A and resistance R is given by :ρ = R.A/I, hence SI unit of resistivity is ohm -metre (Ω m).
A coil in the heater consume power P on passing current. If it is cut into halves and joined in parallel, it will consume power- a)P
- b)P/2
- c)2P
- d)4P
Correct answer is option 'D'. Can you explain this answer?
A coil in the heater consume power P on passing current. If it is cut into halves and joined in parallel, it will consume power
a)
P
b)
P/2
c)
2P
d)
4P
|
|
Pooja Shah answered |
Original power consumed, P = V2/R
When used in parallel
RP = R/4
∴ New power consumed when two halves in parallel
When used in parallel
RP = R/4
∴ New power consumed when two halves in parallel
An object of size 2.0 cm is placed perpendicular to the principal axis of a concave mirror. The distanceof the object from the mirror equals the radius of curvature. The size of the image will be - a)0.5 cm
- b)1.5 cm
- c)1.0cm
- d)2.0 cm
Correct answer is option 'D'. Can you explain this answer?
An object of size 2.0 cm is placed perpendicular to the principal axis of a concave mirror. The distance
of the object from the mirror equals the radius of curvature. The size of the image will be
a)
0.5 cm
b)
1.5 cm
c)
1.0cm
d)
2.0 cm
|
|
Ishan Choudhury answered |
The size of the image will be 2.0 cm.
V=U(given)
m=-v/u
m= - 1
m=h`/h
-1=h`/2
h`=-2
h=2cm
V=U(given)
m=-v/u
m= - 1
m=h`/h
-1=h`/2
h`=-2
h=2cm
Heating of a current carrying conductor is due to- a)loss of kinetic energy of moving atoms
- b)loss of kinetic energy of moving electrons
- c)attraction between electrons and atoms
- d)repulsion between electrons and atoms.
Correct answer is option 'B'. Can you explain this answer?
Heating of a current carrying conductor is due to
a)
loss of kinetic energy of moving atoms
b)
loss of kinetic energy of moving electrons
c)
attraction between electrons and atoms
d)
repulsion between electrons and atoms.
|
|
Gaurav Kumar answered |
When electrons starts drifting into lower potential to higher potential then it get collision with their atoms. Due to which electron loses their kinetic energy and cause heat effect of current.
An ammeter has 20 divisions between mark 0 and mark 2 on its scale. The least count of the ammeter is - a)0.02 A
- b)0.01 A
- c)0.2 A
- d)0.1 A.
Correct answer is option 'D'. Can you explain this answer?
An ammeter has 20 divisions between mark 0 and mark 2 on its scale. The least count of the ammeter is
a)
0.02 A
b)
0.01 A
c)
0.2 A
d)
0.1 A.
|
|
Vikas Kumar answered |
It is given that ammeter has 20 divisions between 0-2Amark
so least count will be 2/20=0.1A
Which two circuit components are connected in parallel in the following circuit diagram ?
- a)rheostate and voltmete
- b)voltmeter and resistor
- c)ammeter and resistor
- d)voltmeter and ammeter.
Correct answer is option 'B'. Can you explain this answer?
Which two circuit components are connected in parallel in the following circuit diagram ?
a)
rheostate and voltmete
b)
voltmeter and resistor
c)
ammeter and resistor
d)
voltmeter and ammeter.
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Gaurav Kumar answered |
We know that the voltmeter is always connected in parallel across the resistance to measure voltage across the resistance. So, option ( b) is the correct answer.
Match the following with correct response.
- a)1-B, 2-D, 3-A, 4-C
- b)1-C, 2-B, 3-D, 4-A
- c)1-A, 2-C, 3-B, 4-D
- d)1-D, 2-A, 3-C, 4-B
Correct answer is option 'A'. Can you explain this answer?
Match the following with correct response.
a)
1-B, 2-D, 3-A, 4-C
b)
1-C, 2-B, 3-D, 4-A
c)
1-A, 2-C, 3-B, 4-D
d)
1-D, 2-A, 3-C, 4-B
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Skyhigh Academy answered |
The ability of eye lens to focus near and far objects is called power of accommodation.
Nearest point which the eye can see clearly is called near points.
The farthest point to which the eye see clearly is known as far point.
Least distance of distinct vision is the minimum distance at which eye can see the object clearly without strain.
Nearest point which the eye can see clearly is called near points.
The farthest point to which the eye see clearly is known as far point.
Least distance of distinct vision is the minimum distance at which eye can see the object clearly without strain.
A person cannot see distinctly any object placed beyond 40cm from his eyes. Calculate the power of the lens which will help him to see distant objects clearly.- a)+1 Dioptre
- b)-2.5 Dioptre
- c)-1.5 Dioptre
- d)+2 Dioptre
Correct answer is option 'B'. Can you explain this answer?
A person cannot see distinctly any object placed beyond 40cm from his eyes. Calculate the power of the lens which will help him to see distant objects clearly.
a)
+1 Dioptre
b)
-2.5 Dioptre
c)
-1.5 Dioptre
d)
+2 Dioptre
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Ishan Choudhury answered |
A lens which can bring an object at infinity to 40 cm is required here.
So, u = infinity, v = -40 cm
We know, 1/f = 1/ v - 1/u
1/ f = 1/-40 - 1/infinity
So, f = -40 cm = -0. 4 m
Power of lens, P = 1/ f = 1/ -0. 4 = -2. 5 D
So, u = infinity, v = -40 cm
We know, 1/f = 1/ v - 1/u
1/ f = 1/-40 - 1/infinity
So, f = -40 cm = -0. 4 m
Power of lens, P = 1/ f = 1/ -0. 4 = -2. 5 D
Two devices are connected between two points say A and B in parallel. The physical quantity that will remain the same between the two points is- a)current
- b)voltage
- c)resistance
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
Two devices are connected between two points say A and B in parallel. The physical quantity that will remain the same between the two points is
a)
current
b)
voltage
c)
resistance
d)
None of these
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Meera Rana answered |
In parallel combination voltage remains same across two points.
A combination of three resistances has been shown here. Effective resistance between the points A and B is
- a)8Ω
- b)4Ω
- c)2Ω
- d)1Ω
Correct answer is option 'C'. Can you explain this answer?
A combination of three resistances has been shown here. Effective resistance between the points A and B is
a)
8Ω
b)
4Ω
c)
2Ω
d)
1Ω
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Pooja Shah answered |
Value of series combination of 2Ω and 2Ω resistances = 4Ω. As it is now connected in parallel to 4Ω resistance, hence the effective resistance R between the points A and B will be
In Fleming’s left-hand rule the thumb indicates the direction of- a)magnetic field applied
- b)current flown in the conductor
- c)induced current
- d)mechanical force on the conductor
Correct answer is option 'D'. Can you explain this answer?
In Fleming’s left-hand rule the thumb indicates the direction of
a)
magnetic field applied
b)
current flown in the conductor
c)
induced current
d)
mechanical force on the conductor
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Krishna Iyer answered |
In Fleming’s left-hand rule the thumb indicates the direction of mechanical force acting on the conductor. The forefinger points in the direction of magnetic field and the central finger in the direction of current flowing in the conductor.
Work done in moving a unit positive test charge from infinity to a point inside an electric field, is called- a)electric potential
- b)field
- c)field intensity
- d)potential difference.
Correct answer is option 'A'. Can you explain this answer?
Work done in moving a unit positive test charge from infinity to a point inside an electric field, is called
a)
electric potential
b)
field
c)
field intensity
d)
potential difference.
|
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Anjana Khatri answered |
Electric potential energy, or electrostatic potential energy, is a potential energy (measured in joules) that results from conservative Coulomb forces and is associated with the configuration of a particular set of point charges within a defined system.
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