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All questions of Network Basics & Basic Laws for Electrical Engineering (EE) Exam
Find the voltage across the 6 ohm resistor.
- a)150V
- b)181,6V
- c) 27.24V
- d)54.48V
Correct answer is option 'C'. Can you explain this answer?
Find the voltage across the 6 ohm resistor.
a)
150V
b)
181,6V
c)
27.24V
d)
54.48V
|
Cstoppers Instructors answered |
Total current = 150/(6+12+15) = 4.55A.
V across 6 ohm = Total current x resistance
= 4.55 * 6 = 27.24V.
Calculate the total current in the circuit.
a)20A
b)11.42A
c)12Ad)15ACorrect answer is option 'B'. Can you explain this answer?
|
Gargi Basak answered |
The 1 ohm and 2-ohm resistor are in series which is in parallel to the 3-ohm resistor.
The equivalent of these resistances is in series with the 4 ohms and 5-ohm resistor.
Total R= 10.5 ohm. I=V/R= 120/10.5= 11.42A.
The equivalent of these resistances is in series with the 4 ohms and 5-ohm resistor.
Total R= 10.5 ohm. I=V/R= 120/10.5= 11.42A.
ib = ?
- a)0.5 A
- b)0.6 A
- c)0.4 A
- d)0.3 A
Correct answer is option 'B'. Can you explain this answer?
ib = ?
a)
0.5 A
b)
0.6 A
c)
0.4 A
d)
0.3 A
|
Yash Patel answered |
Correct Answer :- B
Explanation : Current due to voltage source is:
I' = 10/(64+36)
= 0.1A.
Current due to current source is:
I = 0.5A.
Current ib = I' + I
= 0.5+ 0.1
= 0.6A
Find the current in the circuit.
a)1Ab)2Ac)3Ad)4ACorrect answer is option 'B'. Can you explain this answer?
|
Nandita Bajaj answered |
I = V/R.
Total resistance = 20+40 = 60ohm.
I = 120V.
I = 120/60 = 2A.
Voltage across the 60ohm resistor is______
- a)72V
- b)0V
- c) 48V
- d) 120V
Correct answer is option 'B'. Can you explain this answer?
Voltage across the 60ohm resistor is______
a)
72V
b)
0V
c)
48V
d)
120V
|
Bhavana Reddy answered |
The 60ohm resistance is shorted since current always choses the low resistance path. Voltage across short circuit is equal to zero, hence voltage across the resistor is 0.
Calculate the equivalent resistance between A and B.
- a) 60 ohm
- b) 15 ohm
- c)12 ohm
- d)48 ohm
Correct answer is option 'C'. Can you explain this answer?
Calculate the equivalent resistance between A and B.
a)
60 ohm
b)
15 ohm
c)
12 ohm
d)
48 ohm
|
Akanksha Chopra answered |
The 5 ohm and 15 ohm resistances are connected in series and 10 ohm and 20 ohm resistors are also connected in series. Therefore,20 ohm and 30 ohm are parallel with each other.
In the circuit of the fig P1.1.7, the value of the voltage source E is
- a)-16 V
- b)4 V
- c)-6 V
- d)16 V
Correct answer is option 'A'. Can you explain this answer?
In the circuit of the fig P1.1.7, the value of the voltage source E is
a)
-16 V
b)
4 V
c)
-6 V
d)
16 V
|
Gate Funda answered |
Going from 10 V to 0 V
10 + 5 + E + 1 + 0 = 0 or E =-16 V
10 + 5 + E + 1 + 0 = 0 or E =-16 V
The total resistance between A and B are?
- a)20 ohm
- b)5 ohm
- c)80 ohm
- d)0 ohm
Correct answer is option 'B'. Can you explain this answer?
The total resistance between A and B are?
a)
20 ohm
b)
5 ohm
c)
80 ohm
d)
0 ohm
|
Ameya Gupta answered |
The resistors are connected in parallel, hence the equivalent resistance= 1/(1/20=1/20+1/20+1/20)=5ohm.
Find the value of the currents I1 and I2 flowing clockwise in the first and second mesh respectively.
- a)5A, 0A
- b)-5A, 0A
- c)0A, 5A
- d)0A, -5A
Correct answer is option 'B'. Can you explain this answer?
Find the value of the currents I1 and I2 flowing clockwise in the first and second mesh respectively.
a)
5A, 0A
b)
-5A, 0A
c)
0A, 5A
d)
0A, -5A
|
Gate Gurus answered |
The two mesh equations are:
5I1-3I2=10
-3I1+7I2=-15
Solving the equations simultaneously, we get I1=0.96A and I2=-1.73A.
5I1-3I2=10
-3I1+7I2=-15
Solving the equations simultaneously, we get I1=0.96A and I2=-1.73A.
Can you explain the answer of this question below:What is the value of x if the current in the circuit is 5A?
A:15 ohmB:65 ohmC:55 ohmD:45 ohmThe answer is a.
|
Ishani Iyer answered |
Total voltage=sum of voltages across each resistor. =>150=10*5+5*5+5*x. Solving the equation, we get x=15 ohm.
Calculate the equivalent resistance between A and B.
- a) 2 ohm
- b)4 ohm
- c)6 ohm
- d)8 ohm
Correct answer is option 'A'. Can you explain this answer?
Calculate the equivalent resistance between A and B.
a)
2 ohm
b)
4 ohm
c)
6 ohm
d)
8 ohm
|
Sharmila Kulkarni answered |
R=((2+3)||5)+1.5)||4.The 2 and the 3 ohm resistor are in series. The equiva-lent of these two resistors is in parallel with the 5 ohm resistor. The equivalent of these three resistances is in series with the 1.5 ohm resistor. Finally, the equivalent of these re-sistances is in parallel with the 4 ohm resistor.
Find the value of the currents I1 and I2.
- a) 0.3, 0.1
- b) -0.1, -0.3
- c) 0.1, 0.2
- d)-0.3, -0.1
Correct answer is option 'C'. Can you explain this answer?
Find the value of the currents I1 and I2.
a)
0.3, 0.1
b)
-0.1, -0.3
c)
0.1, 0.2
d)
-0.3, -0.1
|
Neha Nambiar answered |
To explain: Using KVL in loop 1, 10-100 i1=0. i1=0.1A
Using KVL in outer loop, -100i2+20=0 i2=0.2A.
Correct Answer is d) 0.1, 0.2
If two bulbs are connected in parallel and one bulb blows out, what happens to the other bulb?- a)The other bulb blows out as well
- b)The other bulb continues to glow with the same brightness
- c)The other bulb glows with increased brightness
- d)The other bulb stops glowing
Correct answer is option 'B'. Can you explain this answer?
If two bulbs are connected in parallel and one bulb blows out, what happens to the other bulb?
a)
The other bulb blows out as well
b)
The other bulb continues to glow with the same brightness
c)
The other bulb glows with increased brightness
d)
The other bulb stops glowing
|
Sanchita Sharma answered |
In a parallel circuit, if one bulb blows out, it acts as an open circuit. Current does not flow in that branch but it continues to flow in the other branch hence the bulb continues to glow.
Calculate the current across the 20 ohm resistor.
- a)20A
- b)1A
- c)0.67A
- d)0.33A
Correct answer is option 'D'. Can you explain this answer?
Calculate the current across the 20 ohm resistor.
a)
20A
b)
1A
c)
0.67A
d)
0.33A
|
Aashna Dey answered |
Using current divider rule the current through the 20 ohm resistor= (total current in the circuit x resistance of the other branch)/total resistance= 1×10/30=3.33A.
KCL deals with the conservation of?- a)Mass
- b)Momentum
- c)Charge
- d)Energy
Correct answer is option 'D'. Can you explain this answer?
KCL deals with the conservation of?
a)
Mass
b)
Momentum
c)
Charge
d)
Energy
|
Bijoy Kapoor answered |
Kirchhoff’s Current Law
Kirchhoff’s Current Law (KCL) is Kirchhoff’s first law that deals with the conservation of charge entering and leaving a junction. To determine the amount or magnitude of the electrical current flowing around an electrical or electronic circuit, we need to use certain laws or rules that allows us to write down these currents in the form of an equation. The network equations used are those according to Kirchhoff’s laws, and as we are dealing with circuit currents, we will be looking at Kirchhoff’s current law, (KCL).
KVL is applied in ____________- a)Mesh analysis
- b)Nodal analysis
- c)Both mesh and nodal
- d)Neither mesh nor nodal
Correct answer is option 'A'. Can you explain this answer?
KVL is applied in ____________
a)
Mesh analysis
b)
Nodal analysis
c)
Both mesh and nodal
d)
Neither mesh nor nodal
|
Ritika Mukherjee answered |
Explanation:
Mesh analysis helps us to utilize the different voltages in the circuit as well as the IR products in the circuit which is nothing but KVL.
You can know more about Kirchhoff's Laws through the document:
i = ?
- a)1 A
- b)2 A
- c)3 A
- d)4 A
Correct answer is option 'A'. Can you explain this answer?
i = ?
a)
1 A
b)
2 A
c)
3 A
d)
4 A
|
|
Ravikumar Pasula answered |
By kcl
points are mentioned in diagram
at Point D
the incoming currents are i and 5
outgoing current at point D is 6
i +5 = 6
I = 1 amps
points are mentioned in diagram
at Point D
the incoming currents are i and 5
outgoing current at point D is 6
i +5 = 6
I = 1 amps
Calculate the current A.
- a) 5A
- b)10A
- c)15A
- d) 20A
Correct answer is option 'C'. Can you explain this answer?
Calculate the current A.
a)
5A
b)
10A
c)
15A
d)
20A
|
Anoushka Kumar answered |
KCl states that the total current leaving the junction is equal to the current entering it. In this case, the current entering the junction is 5A+10A=15A.
KCL is associated with_________- a)Mesh analysis
- b)Nodal analysis
- c)Both mesh and nodal
- d)Neither mesh nor nodal
Correct answer is option 'B'. Can you explain this answer?
KCL is associated with_________
a)
Mesh analysis
b)
Nodal analysis
c)
Both mesh and nodal
d)
Neither mesh nor nodal
|
Mrinalini Sen answered |
Potassium chloride (KCl) is a metal halide salt composed of potassium and chlorine. It is odorless and has a white or colorless vitreous crystal appearance. The solid dissolves readily in water and its solutions have a salt-like taste.
Calculate the current across the 20 ohm resistor.
- a)10A
- b) 20A
- c) 36.67A
- d) 6.67A
Correct answer is option 'A'. Can you explain this answer?
Calculate the current across the 20 ohm resistor.
a)
10A
b)
20A
c)
36.67A
d)
6.67A
|
|
Sharmila Bajaj answered |
Explanation: I=V/R. Since in parallel circuit, voltage is same across all resistors. Hence across the 20 ohm resistor, V=200V so I=200/20=10A.
The voltage across the short is?
- a)135V
- b)Infinity
- c) Zero
- d)11.25V
Correct answer is option 'C'. Can you explain this answer?
The voltage across the short is?
a)
135V
b)
Infinity
c)
Zero
d)
11.25V
|
Sanvi Kapoor answered |
The voltage across a short is always equal to zero whether it is connected in seroes or parallel.
Calculate the resistance between A and B.
- a)3.56 ohm
- b)7 ohm
- c)14.26 ohm
- d)29.69 ohm
Correct answer is option 'A'. Can you explain this answer?
Calculate the resistance between A and B.
a)
3.56 ohm
b)
7 ohm
c)
14.26 ohm
d)
29.69 ohm
|
Lavanya Menon answered |
- The 1 ohm, 2 ohm and 3 ohm resistors are connected in parallel. Its equivalent resistance is in series with the 4 ohm resistor and the parallel connection of the 5 ohm and 6 ohm resistor.
- The equivalent resistance of this combination is 80/11 ohm. This is in parallel with 7 ohm to give equivalent resistance between A and B is 3.56 ohm.
Batteries are generally connected in______- a)Series
- b)Parallel
- c)Either series or parallel
- d)Neither series nor parallel
Correct answer is option 'A'. Can you explain this answer?
Batteries are generally connected in______
a)
Series
b)
Parallel
c)
Either series or parallel
d)
Neither series nor parallel
|
Sakshi Roy answered |
Batteries are generally connected in series so that we can obtain the desired voltage since voltages add up once they are connected in series.
What happens to the current in the series circuit if the resistance is doubled?- a)It becomes half its original value
- b)It becomes double its original value
- c)It becomes zero
- d)It becomes infinity
Correct answer is option 'A'. Can you explain this answer?
What happens to the current in the series circuit if the resistance is doubled?
a)
It becomes half its original value
b)
It becomes double its original value
c)
It becomes zero
d)
It becomes infinity
|
Rajesh Verma answered |
I=V/R. Hence if R=2R V=I/2R, and I=I/2.
For the circuit shown in fig P.1.1.9 the value of voltage vo is
- a)10 V
- b)15 V
- c)20 V
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
For the circuit shown in fig P.1.1.9 the value of voltage vo is
a)
10 V
b)
15 V
c)
20 V
d)
None of the above
|
|
Aashna Dey answered |
Voltage is constant because of 15 V source.
In a series circuit, which of the parameters remain constant across all circuit elements such as resistor, capacitor and inductor etcetera?- a)Voltage
- b)Current
- c)Both voltage and current
- d)Neither voltage nor current
Correct answer is option 'B'. Can you explain this answer?
In a series circuit, which of the parameters remain constant across all circuit elements such as resistor, capacitor and inductor etcetera?
a)
Voltage
b)
Current
c)
Both voltage and current
d)
Neither voltage nor current
|
Swara Dasgupta answered |
In a series circuit, the current across all elements remain the same and the total voltage of the circuit is the sum of the voltages across all the elements.
v1 = ?
- a)-11 V
- b)5 V
- c)8 V
- d)18 V
Correct answer is option 'C'. Can you explain this answer?
v1 = ?
a)
-11 V
b)
5 V
c)
8 V
d)
18 V
|
Ashwin Kapoor answered |
If we go from +side of 1 kΩ through 7 V, 6 V and 5V, we get v1 = 0 + 7 + 6 - 5 = 8 V
If there are two bulbs connected in series and one blows out, what happens to the other bulb?- a)The other bulb continues to glow with the same brightness
- b)The other bulb stops glowing
- c)The other bulb glows with increased brightness
- d)The other bulb also burns out
Correct answer is option 'B'. Can you explain this answer?
If there are two bulbs connected in series and one blows out, what happens to the other bulb?
a)
The other bulb continues to glow with the same brightness
b)
The other bulb stops glowing
c)
The other bulb glows with increased brightness
d)
The other bulb also burns out
|
Bijoy Nair answered |
Since the two bulbs are connected in series, if the first bulb burns out there is a break in the circuit and hence the second bulb does not glow.
Find the value of v if v1=20V.
- a)10V
- b) 12V
- c)14V
- d)16V
Correct answer is option 'B'. Can you explain this answer?
Find the value of v if v1=20V.
a)
10V
b)
12V
c)
14V
d)
16V
|
|
Cstoppers Instructors answered |
The current through the 10 ohm resistor = v1 / 10 = 2A
Applying KCL at node 1: i5 = i10 + i2
i2 = 6 - 2 = 4A
Thus the drop in the 2 ohm resistor = 4×2 = 8V
v1 = 20V; hence v2 = 20-v across 2 ohm resistor = 20 - 8 = 12V
v2 = v since they are connected in parallel.
v = 12V
v2 = v since they are connected in parallel.
v = 12V
Every____________ is a ____________ but every __________ is not a __________- a)Mesh, loop, loop, mesh
- b)Loop, mesh, mesh, loop
- c)Loop, mesh, loop, mesh
- d)Mesh, loop, mesh, loop
Correct answer is option 'A'. Can you explain this answer?
Every____________ is a ____________ but every __________ is not a __________
a)
Mesh, loop, loop, mesh
b)
Loop, mesh, mesh, loop
c)
Loop, mesh, loop, mesh
d)
Mesh, loop, mesh, loop
|
|
Raj Desai answered |
According to Kirchhoff’s Voltage Law, Every mesh is a loop but every loop is not a mesh.
A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is
- a)160.2 C
- b)-160.2 C
- c)-16.02 C
- d)16.02 C
Correct answer is option 'C'. Can you explain this answer?
A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is
a)
160.2 C
b)
-160.2 C
c)
-16.02 C
d)
16.02 C
|
|
Amar Sengupta answered |
Let's calculate the charge on the sphere
Understanding the problem:
- A copper sphere loses 10^20 electrons.
- We need to find the total charge on the sphere.
Solution:
- Charge of one electron (e) = -1.6 x 10^-19 C
- Number of electrons removed (n) = 10^20
Total charge (Q) = n * e
Q = 1020 * (-1.6 x 10^-19 C) Q = -1.632 x 10^-16 C
Approximately, Q = -16.02 x 10^-17 C
Therefore, the charge on the sphere is -16.02 C.
So, the correct answer is:
4. -16.02 C
Note that the charge is negative because electrons are removed, leaving a net positive charge on the sphere.
i1 = ?
- a)3.3 A
- b)2.1 A
- c)1.7 A
- d)1.1 A
Correct answer is option 'A'. Can you explain this answer?
i1 = ?
a)
3.3 A
b)
2.1 A
c)
1.7 A
d)
1.1 A
|
|
Ravikumar Pasula answered |
Using superposition theorem
first open the 6A current source, find the i1=3.5
second short circuit the voltage source current i1= -0.2 (here minus represent the reverse direction of i1)
the total current is sum of two
I = i1 + i2
= 3.5 + (-0.2)
= 3.3
first open the 6A current source, find the i1=3.5
second short circuit the voltage source current i1= -0.2 (here minus represent the reverse direction of i1)
the total current is sum of two
I = i1 + i2
= 3.5 + (-0.2)
= 3.3
What is the current through R1 and R2 in the following diagram?
- a)I1 =1.875 I2 = 3.125.
- b)
, 
.
- c)
, 
- d)
, 
.
Correct answer is option 'A'. Can you explain this answer?
What is the current through R1 and R2 in the following diagram?
a)
I1 =1.875 I2 = 3.125.
b)
, .c)
, d)
, .
|
Saumya Sen answered |
- All are In parallel so voltage is same
- I1 = ( R2/R1+R2 )V = ( 3/8 )x5A = 1.875
- I2 = ( R1/R1+R2 )V = ( 5/8 )x5A = 3.125
Calculate the value of V1 and V2.
- a)4V, 6V
- b)5V, 6V
- c)6V, 7V
- d)7V, 8V
Correct answer is option 'A'. Can you explain this answer?
Calculate the value of V1 and V2.
a)
4V, 6V
b)
5V, 6V
c)
6V, 7V
d)
7V, 8V
|
|
Nishtha Chauhan answered |
Using KVL, 12-V1-8=0. V1= 4V.
8-V2-2=0. V2=6V.
8-V2-2=0. V2=6V.
Calculate the voltage across the 10 ohm resistor.
- a)12V
- b) 4V
- c)10V
- d)0V
Correct answer is option 'B'. Can you explain this answer?
Calculate the voltage across the 10 ohm resistor.
a)
12V
b)
4V
c)
10V
d)
0V
|
Ravi Singh answered |
Using voltage divider rule, V=10*12/30=4V.
Voltage across a series resistor circuit is proportional to?- a)The amount of time the circuit was on for
- b)The value of the resistance itself
- c)The value of the other resistances in the circuit
- d)The power in the circuit
Correct answer is option 'B'. Can you explain this answer?
Voltage across a series resistor circuit is proportional to?
a)
The amount of time the circuit was on for
b)
The value of the resistance itself
c)
The value of the other resistances in the circuit
d)
The power in the circuit
|
Shivam Sharma answered |
V=IR hence voltage across a series resistor circuit is proportional to the value of the resistance.
A circuit has a resistor with a resistance of 3Ω followed by three parallel branches, each holding a resistor with a resistance of 5Ω. What is the total equivalent resistance of the circuit?- a)15/3 Ω
- b)14/3 Ω
- c)15/7 Ω
- d)19/3 Ω
Correct answer is option 'B'. Can you explain this answer?
A circuit has a resistor with a resistance of 3Ω followed by three parallel branches, each holding a resistor with a resistance of 5Ω. What is the total equivalent resistance of the circuit?
a)
15/3 Ω
b)
14/3 Ω
c)
15/7 Ω
d)
19/3 Ω
|
|
Lavanya Menon answered |
The voltage vo in fig. P1.1.11 is always equal to
- a)1 V
- b)5 V
- c)9 V
- d)None of the above
Correct answer is option 'D'. Can you explain this answer?
The voltage vo in fig. P1.1.11 is always equal to
a)
1 V
b)
5 V
c)
9 V
d)
None of the above
|
|
Sanvi Kapoor answered |
It is not possible to determine the voltage across 1 A source.
KCL is applied at _________- a)Loop
- b)Node
- c)Both loop and node
- d)Neither loop nor node
Correct answer is option 'B'. Can you explain this answer?
KCL is applied at _________
a)
Loop
b)
Node
c)
Both loop and node
d)
Neither loop nor node
|
Sanskriti Bajaj answered |
KCL states that the amount of charge leaving a node is equal to the amount of charge entering it, hence it is applied at nodes.
In the circuit of fig P1.1.6 a charge of 600 C is delivered to the 100 V source in a 1 minute. The value of v1 must be
- a)240 V
- b)120 V
- c)60 V
- d)30 V
Correct answer is option 'A'. Can you explain this answer?
In the circuit of fig P1.1.6 a charge of 600 C is delivered to the 100 V source in a 1 minute. The value of v1 must be
a)
240 V
b)
120 V
c)
60 V
d)
30 V
|
|
Cstoppers Instructors answered |
In order for 600 C charge to be delivered to the 100 V source, the current must be anticlockwise.
Applying KVL we get
Applying KVL we get
Many resistors connected in series will?- a)Divide the voltage proportionally among all the resistors
- b)Divide the current proportionally
- c)Increase the source voltage in proportion to the values of the resistors
- d)Reduce the power to zero
Correct answer is option 'A'. Can you explain this answer?
Many resistors connected in series will?
a)
Divide the voltage proportionally among all the resistors
b)
Divide the current proportionally
c)
Increase the source voltage in proportion to the values of the resistors
d)
Reduce the power to zero
|
|
Mansi Datta answered |
In a series circuit, the current remains the same across all resistors hence the voltage divides proportionally among all resistors.
The symbol shown here is:
- a)Voltage controlled current source
- b)Current controlled current source
- c)Current controlled voltage source
- d)Voltage controlled voltage source
Correct answer is option 'A'. Can you explain this answer?
The symbol shown here is:
a)
Voltage controlled current source
b)
Current controlled current source
c)
Current controlled voltage source
d)
Voltage controlled voltage source
|
|
Cstoppers Instructors answered |
Concept:
Independent sources:
An independent voltage source maintains a voltage (fixed or varying with time) which is not affected by any other quantity. Similarly, an independent current source maintains a current (fixed or time-varying) which is unaffected by any other quantity.
Independent sources:
An independent voltage source maintains a voltage (fixed or varying with time) which is not affected by any other quantity. Similarly, an independent current source maintains a current (fixed or time-varying) which is unaffected by any other quantity.
Dependent sources:
- Some voltage (current) sources have their voltage (current) values varying with some other variables.
- They are called dependent (voltage or current) sources or controlled (voltage or current) sources.
- It is represented in diamond symbol.
- Since the control of the dependent source is achieved by a voltage or current of some other element in the circuit, and the source can be voltage or current.
- It follows that there are four possible types of dependent sources, namely:
- Voltage-controlled voltage source (VCVS)
- Current-controlled voltage source (CCVS)
- Current-controlled current source (CCCS)
- Voltage-controlled current source (VCCS)
Application:
1. 
In the given circuit, the dependent source is a current source (gvc) which depends on the voltage in the other branch. Hence dependent source in the circuit is a voltage-controlled current source.
2. 
In the given circuit, the dependent source is a current source (dic) which depends on the current in the other branch. Hence dependent source in the circuit is a current-controlled current source.
3. 
In the given circuit, the dependent source is a voltage source (bvc) which depends on the voltage in the other branch. Hence dependent source in the circuit is a voltage-controlled voltage source.
4. 
In the given circuit, the dependent source is a voltage source (ric) which depends on the current in the other branch. Hence dependent source in the circuit is a current-controlled voltage source.
Find the value of the node voltage V.
- a)60V
- b)50V
- c)40V
- d)30V
Correct answer is option 'A'. Can you explain this answer?
Find the value of the node voltage V.
a)
60V
b)
50V
c)
40V
d)
30V
|
|
Ashwin Kapoor answered |
The node equation is:
-2+8+V/10=0 => 6 + v/10 = 0 => v = 10*6=>60v
Solving this equation, we get V=60V.
-2+8+V/10=0 => 6 + v/10 = 0 => v = 10*6=>60v
Solving this equation, we get V=60V.
For the circuit shown in the figure, V1 =8 V, DC and I1 =8A, DC. The voltage Vab in Volts is ___ (Round off to 1 decimal place).
- a)6
- b)4.2
- c)8
- d)10.6
Correct answer is option 'A'. Can you explain this answer?
For the circuit shown in the figure, V1 =8 V, DC and I1 =8A, DC. The voltage Vab in Volts is ___ (Round off to 1 decimal place).
a)
6
b)
4.2
c)
8
d)
10.6
|
EduRev GATE answered |
Reraw the circuit:
Now, using voltage division,
If there are 10 nodes in a circuit, how many equations do we get?- a)10
- b)9
- c)8
- d)7
Correct answer is option 'B'. Can you explain this answer?
If there are 10 nodes in a circuit, how many equations do we get?
a)
10
b)
9
c)
8
d)
7
|
Bharathi Donku answered |
In the circuit 10 nodes is there, we get 9 equations only we get. because 1 node is treated as reference node.
Mesh analysis is generally used to determine _________- a)Voltage
- b)Current
- c)Resistance
- d)Power
Correct answer is option 'B'. Can you explain this answer?
Mesh analysis is generally used to determine _________
a)
Voltage
b)
Current
c)
Resistance
d)
Power
|
|
Shivam Ghosh answered |
Mesh analysis uses Kirchhoff’s Voltage Law to find all the mesh currents. Hence it is a method used to determine current.
In a parallel circuit, with a number of resistors, the voltage across each resistor is ________- a)The same for all resistors
- b)Is divided equally among all resistors
- c)Is divided proportionally across all resistors
- d)Is zero for all resistors
Correct answer is option 'A'. Can you explain this answer?
In a parallel circuit, with a number of resistors, the voltage across each resistor is ________
a)
The same for all resistors
b)
Is divided equally among all resistors
c)
Is divided proportionally across all resistors
d)
Is zero for all resistors
|
Jyoti Basak answered |
In parallel circuits, the current across the circuits vary whereas the voltage remains the same.
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