All questions of Time and Distance for Electrical Engineering (EE) Exam
Without any stoppages a person travels a certain distance at an average speed of 40 km/hr and with stoppages he covers the same distance at an average of 20 km/hr. How many minutes per hour does he stop?- a)15 minutes
- b)20 minutes
- c)30 minutes
- d)45 minutes
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Without any stoppages a person travels a certain distance at an average speed of 40 km/hr and with stoppages he covers the same distance at an average of 20 km/hr. How many minutes per hour does he stop?
a)
15 minutes
b)
20 minutes
c)
30 minutes
d)
45 minutes
e)
None of these
|
Preeti Khanna answered |
In one hour the distance covered at actual speed = 40km and with stoppages it covers only 20 km
so to travel 20 km at original speed i.e. 20 = 40*t, so t = 1/2 hour = 30
minutes
so to travel 20 km at original speed i.e. 20 = 40*t, so t = 1/2 hour = 30
minutes
Ajay covers certain distance with his own speed but when he reduces his speed by 10kmph his time duration for the journey increases by 40 hours while if he increases his speed by 5 kmph from his original speed he takes 10 hours less than the original time taken. Find the distance covered by him. - a) 1000 km
- b)1200 km
- c)1500 km
- d)1800 km
Correct answer is option 'C'. Can you explain this answer?
Ajay covers certain distance with his own speed but when he reduces his speed by 10kmph his time duration for the journey increases by 40 hours while if he increases his speed by 5 kmph from his original speed he takes 10 hours less than the original time taken. Find the distance covered by him.
a)
1000 km
b)
1200 km
c)
1500 km
d)
1800 km
|
Aisha Gupta answered |
x/(y – 10) – x/y = 40
x = 4y(y-10) —(i)
x/y – x/(y + 5) = 10
x = 2y(y + 5) — (ii) From (i) and (ii) ⇒ y = 25; x = 1500
x = 4y(y-10) —(i)
x/y – x/(y + 5) = 10
x = 2y(y + 5) — (ii) From (i) and (ii) ⇒ y = 25; x = 1500
Pranav walked at 5 kmph for certain part of the journey and then he took an auto for the remaining part of the journey travelling at 25 kmph. If he took 10 hours for the entire journey, what part of journey did he travelled by auto if the average speed of the entire journey be 17 kmph- a)750 km
- b)100 km
- c)150 km
- d)200 km
Correct answer is option 'C'. Can you explain this answer?
Pranav walked at 5 kmph for certain part of the journey and then he took an auto for the remaining part of the journey travelling at 25 kmph. If he took 10 hours for the entire journey, what part of journey did he travelled by auto if the average speed of the entire journey be 17 kmph
a)
750 km
b)
100 km
c)
150 km
d)
200 km
|
Naroj Boda answered |
Total distance = 17*10 = 170
Let Journey travelled by auto in x hr
25 * x + (10-x ) 5 = 170
25 x + 50 – 5x = 170
x = 6
Required Distance = 6 * 25 = 150 km
A train covers a distance between two stations P and Q in 30 minutes. If the speed of the train is reduced by 10km/hr, then the same distance is covered in 45 minutes. The distance between P and Q- a)10km
- b)15km
- c)20km
- d)30km
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A train covers a distance between two stations P and Q in 30 minutes. If the speed of the train is reduced by 10km/hr, then the same distance is covered in 45 minutes. The distance between P and Q
a)
10km
b)
15km
c)
20km
d)
30km
e)
None of these
|
Cstoppers Instructors answered |
D = S*1/2 and D = (S-10)*3/4
solve both equation. u will get D = 15km
solve both equation. u will get D = 15km
Mani drove at the speed of 45 kmph. From home to a resort. Returning over the same route, he got stuck in traffic and took an hour longer, also he could drive only at the speed of 40 kmph. How many kilometers did he drive each way ?- a)520km
- b)240km
- c)360km
- d)420km
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Mani drove at the speed of 45 kmph. From home to a resort. Returning over the same route, he got stuck in traffic and took an hour longer, also he could drive only at the speed of 40 kmph. How many kilometers did he drive each way ?
a)
520km
b)
240km
c)
360km
d)
420km
e)
None of these
|
|
Preeti Khanna answered |
x/40 – x/45 = 1
9x-8x/360 = 1
x/360 = 1
x = 360km
9x-8x/360 = 1
x/360 = 1
x = 360km
Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance between A and B is 50 km. what is the speed of the slower rabbit?- a)20 kmph
- b)10 kmph
- c)15 kmph
- d)25 kmph
Correct answer is option 'A'. Can you explain this answer?
Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance between A and B is 50 km. what is the speed of the slower rabbit?
a)
20 kmph
b)
10 kmph
c)
15 kmph
d)
25 kmph
|
Divey Sethi answered |
Let second rabbit takes x hr with speed s2
First rabbit takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2 = 50/x
As they cross each other in 1hr…
Total speed = s1 + s2
Now, T = D / S
50/(s1+s2) = 1
x = 5/2, 1/3
Put x = 5/2 in s2 –> 20km/hr
First rabbit takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2 = 50/x
As they cross each other in 1hr…
Total speed = s1 + s2
Now, T = D / S
50/(s1+s2) = 1
x = 5/2, 1/3
Put x = 5/2 in s2 –> 20km/hr
Two stations A and B are 150 km apart from each other. One train starts from A at 6 AM at a speed of 30 km/hr and travels towards B. Another train starts from station B at 7 AM at a speed of 20 km/hr. At what time they will meet.- a)9:34 AM
- b)10:34 AM
- c)8:34 AM
- d)7:34 AM
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Two stations A and B are 150 km apart from each other. One train starts from A at 6 AM at a speed of 30 km/hr and travels towards B. Another train starts from station B at 7 AM at a speed of 20 km/hr. At what time they will meet.
a)
9:34 AM
b)
10:34 AM
c)
8:34 AM
d)
7:34 AM
e)
None of these
|
|
Cstoppers Instructors answered |
Distance travel by first train in one hour = 30, now the distance remains 120 km only.
x/30 = (120 – x)/20, so we get x = 72 km
Now, time = (30 + 72)/30 = 3hrs and 24minutes i.e. 9: 34 am
x/30 = (120 – x)/20, so we get x = 72 km
Now, time = (30 + 72)/30 = 3hrs and 24minutes i.e. 9: 34 am
If a Car runs at 45Km/hr it reaches its destination by 10 min late. If it runs at 60Km/hr it is late by 4min. Then what is the correct time for the journey?- a)12 min
- b)14 min
- c)16 min
- d)18 min
- e)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
If a Car runs at 45Km/hr it reaches its destination by 10 min late. If it runs at 60Km/hr it is late by 4min. Then what is the correct time for the journey?
a)
12 min
b)
14 min
c)
16 min
d)
18 min
e)
Cannot be determined
|
|
Divey Sethi answered |
45(t+10) = 60(t+4)
T = 14
T = 14
A boat running downstream covers a distance of 40 km in 5 hrs and for covering the same distance upstream it takes 10 hrs. What is the speed of the stream? - a)5 km/hr
- b)2 km/hr
- c)6 km/hr
- d)4 km/hr
- e)3 km/hr
Correct answer is option 'B'. Can you explain this answer?
A boat running downstream covers a distance of 40 km in 5 hrs and for covering the same distance upstream it takes 10 hrs. What is the speed of the stream?
a)
5 km/hr
b)
2 km/hr
c)
6 km/hr
d)
4 km/hr
e)
3 km/hr
|
Kavya Saxena answered |
Downstream speed = 40/5 = 8 km/hr
Upstream speed = 40/10 = 4 km/hr
So speed of stream = 1/2*(8-4)
Upstream speed = 40/10 = 4 km/hr
So speed of stream = 1/2*(8-4)
Two places A and B are at a distance of 480Km. Sita started from A towards B at the speed of 40Kmph. After 2 hours Gita started from B towards A at speed of 60 Kmph. They meet at a Place C then what is the difference between the time taken by them to reach their destinations from Place C?- a)1 hour
- b)2 hours
- c)3 hours
- d)4 hours
- e)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
Two places A and B are at a distance of 480Km. Sita started from A towards B at the speed of 40Kmph. After 2 hours Gita started from B towards A at speed of 60 Kmph. They meet at a Place C then what is the difference between the time taken by them to reach their destinations from Place C?
a)
1 hour
b)
2 hours
c)
3 hours
d)
4 hours
e)
Cannot be determined
|
Faizan Khan answered |
t*40+ (t-2)*60 = 480
t=6
From Place C to A = C to B = 240
Then time taken by Sita = 6hours and GIta = 4 hours
Difference = 6-4 = 2 hours
t=6
From Place C to A = C to B = 240
Then time taken by Sita = 6hours and GIta = 4 hours
Difference = 6-4 = 2 hours
Two trains of length 120 meter and 150 meter crosses a stationary man in 10 and 15 seconds respectively. In what time they will cross each other when they are moving in same direction.- a)120 sec
- b)125 sec
- c)135 sec
- d)140 sec
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Two trains of length 120 meter and 150 meter crosses a stationary man in 10 and 15 seconds respectively. In what time they will cross each other when they are moving in same direction.
a)
120 sec
b)
125 sec
c)
135 sec
d)
140 sec
e)
None of these
|
Nikita Singh answered |
120 = a*10, a = 12 m/sec (speed of first train)
150 = b*15, b = 10 m/sec (speed of second train)
270 = (2)*T, T = 135 seconds
150 = b*15, b = 10 m/sec (speed of second train)
270 = (2)*T, T = 135 seconds
Two cars namely A and B start simultaneously from a certain place at the speed of 40 kmph and 55 kmph, respectively.The car B reaches the destination 2 hours earlier than A. What is the distance between the starting point and destination?- a)8 hours 12 minutes
- b)6 hours 15 minutes
- c)7 hours 20 minutes
- d)7 hours 12 minutes
Correct answer is option 'C'. Can you explain this answer?
Two cars namely A and B start simultaneously from a certain place at the speed of 40 kmph and 55 kmph, respectively.The car B reaches the destination 2 hours earlier than A. What is the distance between the starting point and destination?
a)
8 hours 12 minutes
b)
6 hours 15 minutes
c)
7 hours 20 minutes
d)
7 hours 12 minutes
|
|
Kavya Saxena answered |
Let the time taken by car A to reach destination is T hours
So, the time taken by car B to reach destination is (T – 2) hours.
S1T1 = S2T2
⇒ 40(T) = 55 (T – 2)
⇒ 40T = 55T -110
⇒ 15T = 110
T = 7 hours 20 minutes
So, the time taken by car B to reach destination is (T – 2) hours.
S1T1 = S2T2
⇒ 40(T) = 55 (T – 2)
⇒ 40T = 55T -110
⇒ 15T = 110
T = 7 hours 20 minutes
A thief steals a car at 3 pm and drives at 75 km/hr. He got discovered by the police at 4 pm Then the police start chasing him in another car travelling at 100km/hr. When will the policeman catch the thief?- a)5pm
- b)6pm
- c)7pm
- d)8pm
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A thief steals a car at 3 pm and drives at 75 km/hr. He got discovered by the police at 4 pm Then the police start chasing him in another car travelling at 100km/hr. When will the policeman catch the thief?
a)
5pm
b)
6pm
c)
7pm
d)
8pm
e)
None of these
|
Machine Experts answered |
In one hour thief will travel 75 km. Now let after x distance thief get caught, then
x/75 = (75+x)/100
u will get x = 225, so to travel 225 + 75 = 300 km by police, he will take 3 hours i.e at 7 pm
x/75 = (75+x)/100
u will get x = 225, so to travel 225 + 75 = 300 km by police, he will take 3 hours i.e at 7 pm
Mr.Kavin walks at 4/5 of his normal speed and takes 60 minutes more than the usual time. What will be the new time taken by Mr. Kavin?- a)260 minutes
- b)235 minutes
- c)220 minutes
- d)300 minutes
Correct answer is option 'D'. Can you explain this answer?
Mr.Kavin walks at 4/5 of his normal speed and takes 60 minutes more than the usual time. What will be the new time taken by Mr. Kavin?
a)
260 minutes
b)
235 minutes
c)
220 minutes
d)
300 minutes
|
Yash Patel answered |
4/5 of speed = 5/4 of original time
5/4 of original time = original time + 60 minutes;
1/4 of original time = 60 minutes;
Thus, original time = 60*4 = 240 minutes = 240 + 60 = 300 minutes
5/4 of original time = original time + 60 minutes;
1/4 of original time = 60 minutes;
Thus, original time = 60*4 = 240 minutes = 240 + 60 = 300 minutes
The distance between two cities P and Q is 300km. A train starts from station P at 10 am with speed 80 km/hr towards Q. Another train starts from Q towards P with speed 40km/hr at 11 am. At what time do they meet?- a)12.20pm
- b)12.40 pm
- c)12.50 pm
- d)1 pm
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
The distance between two cities P and Q is 300km. A train starts from station P at 10 am with speed 80 km/hr towards Q. Another train starts from Q towards P with speed 40km/hr at 11 am. At what time do they meet?
a)
12.20pm
b)
12.40 pm
c)
12.50 pm
d)
1 pm
e)
None of these
|
|
Preeti Khanna answered |
First train starts at 10am so in one hour it covers 80 km in one hour. Now distance b/w P and Q is 220. Suppose at some’ x’ km they meet. So,
x/80 = (220-x)/40
x = 440/3. The time after which they meet = (440/3)/80 = 11/6 i.e = 1hr 50 min.
x/80 = (220-x)/40
x = 440/3. The time after which they meet = (440/3)/80 = 11/6 i.e = 1hr 50 min.
A girl goes to her school from her house at a speed of 6km/hr and returns at a speed of 4 km/hr. If she takes 10 hours in going and coming back, the distance between her school and house is- a)12km
- b)16 km
- c)20 km
- d)24 km
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A girl goes to her school from her house at a speed of 6km/hr and returns at a speed of 4 km/hr. If she takes 10 hours in going and coming back, the distance between her school and house is
a)
12km
b)
16 km
c)
20 km
d)
24 km
e)
None of these
|
Vanakkam Studios answered |
24km
The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?- a)28 kmph
- b)25 kmph
- c)20 kmph
- d)24 kmph
Correct answer is option 'C'. Can you explain this answer?
The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?
a)
28 kmph
b)
25 kmph
c)
20 kmph
d)
24 kmph
|
|
Divey Sethi answered |
80/x – 80/(x+4) = 1
x(x+20) – 16(x+20) = 0
x = 16kmph
Increased speed = 20 kmph
x(x+20) – 16(x+20) = 0
x = 16kmph
Increased speed = 20 kmph
Two places R and S are 800 km apart from each other. Two persons start from R towards S at an interval of 2 hours. Whereas A leaves R for S before B. The speeds of A and B are 40 kmph and 60 kmph respectively. B overtakes A at M, which is on the way from R to S. What is the ratio of time taken by A and B to meet at M?- a)1:3
- b)1:2
- c)1:4
- d)3:2
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Two places R and S are 800 km apart from each other. Two persons start from R towards S at an interval of 2 hours. Whereas A leaves R for S before B. The speeds of A and B are 40 kmph and 60 kmph respectively. B overtakes A at M, which is on the way from R to S. What is the ratio of time taken by A and B to meet at M?
a)
1:3
b)
1:2
c)
1:4
d)
3:2
e)
None of these
|
|
Kavya Saxena answered |
Time taken by B to reach at M = 4h
Time taken by A to reach at M = 6h
Ratio = 6:4 = 3:2
Time taken by A to reach at M = 6h
Ratio = 6:4 = 3:2
Aravind started for the station half a km from his home walking at 1 km/h to catch the train in time. After 3 minutes he realised that he had forgotten a document at home and returned with increased, but constant speed to get it succeded in catching the train. Find his latter speed in kmph?- a)1.25
- b)1.1
- c)11/9
- d)2
Correct answer is option 'C'. Can you explain this answer?
Aravind started for the station half a km from his home walking at 1 km/h to catch the train in time. After 3 minutes he realised that he had forgotten a document at home and returned with increased, but constant speed to get it succeded in catching the train. Find his latter speed in kmph?
a)
1.25
b)
1.1
c)
11/9
d)
2
|
|
Aarav Sharma answered |
Problem: Aravind started for the station half a km from his home walking at 1 km/h to catch the train in time. After 3 minutes he realised that he had forgotten a document at home and returned with increased, but constant speed to get it succeeded in catching the train. Find his latter speed in kmph?
Solution:
Let the speed at which Aravind returns to his home be x km/h.
Distance from home to station = 0.5 km
Time taken to walk to the station at 1 km/h = distance / speed = 0.5 / 1 = 0.5 hours
After 3 minutes = 3/60 = 1/20 hours, Aravind starts returning home.
Time taken to return home = 1/20 hours
Time taken to travel from home to station = 0.5 / x hours
Total time taken = 0.5 / 1 + 1/20 + 0.5 / x
As Aravind catches the train, the total time taken must be less than or equal to the time of the train's departure.
Let the train's departure time be T.
0.5 / 1 + 1/20 + 0.5 / x ≤ T
Simplifying, we get:
25 + x + 10 / x ≤ 20T
Simplifying further we get,
x² - 10x + 25 ≤ 0
(x - 5)² ≤ 0
Since x² - 10x + 25 is a perfect square, its minimum value is 0.
Therefore, the only possible value of x is 5 km/h.
Hence, Aravind's latter speed is 5 km/h or 11/9 km/h (approx).
Therefore, option C is correct.
Solution:
Let the speed at which Aravind returns to his home be x km/h.
Distance from home to station = 0.5 km
Time taken to walk to the station at 1 km/h = distance / speed = 0.5 / 1 = 0.5 hours
After 3 minutes = 3/60 = 1/20 hours, Aravind starts returning home.
Time taken to return home = 1/20 hours
Time taken to travel from home to station = 0.5 / x hours
Total time taken = 0.5 / 1 + 1/20 + 0.5 / x
As Aravind catches the train, the total time taken must be less than or equal to the time of the train's departure.
Let the train's departure time be T.
0.5 / 1 + 1/20 + 0.5 / x ≤ T
Simplifying, we get:
25 + x + 10 / x ≤ 20T
Simplifying further we get,
x² - 10x + 25 ≤ 0
(x - 5)² ≤ 0
Since x² - 10x + 25 is a perfect square, its minimum value is 0.
Therefore, the only possible value of x is 5 km/h.
Hence, Aravind's latter speed is 5 km/h or 11/9 km/h (approx).
Therefore, option C is correct.
Excluding stoppages, a train can travel with a speed of 60km/hr but with stoppages it can travel at an average 45km/hr. For how many minutes the train stops in one hour.- a)10min
- b)12min
- c)15min
- d)18min
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Excluding stoppages, a train can travel with a speed of 60km/hr but with stoppages it can travel at an average 45km/hr. For how many minutes the train stops in one hour.
a)
10min
b)
12min
c)
15min
d)
18min
e)
None of these
|
Ravi Singh answered |
due to stoppages 15km less is travel by train so,
15 = 60*t, t = 15 minutes – train stops in one hour
15 = 60*t, t = 15 minutes – train stops in one hour
A car runs at the speed of 50 km per hour when not serviced and runs at 60 kmph when serviced. After servicing the car covers a certain distance in 6 hours. How much time will the car take to cover the same distance when not serviced?- a)8 hours 12 minutes
- b)6 hours 15 minutes
- c)8 hours 15 minutes
- d)7 hours 12 minutes
Correct answer is option 'D'. Can you explain this answer?
A car runs at the speed of 50 km per hour when not serviced and runs at 60 kmph when serviced. After servicing the car covers a certain distance in 6 hours. How much time will the car take to cover the same distance when not serviced?
a)
8 hours 12 minutes
b)
6 hours 15 minutes
c)
8 hours 15 minutes
d)
7 hours 12 minutes
|
|
Faizan Khan answered |
Time = 60*6 / 50 = 7 hours 12 mins
A boy goes to school from his home at a speed of 4 km/hr and returns at a speed of 6 km/hr. If in total he took 5 hours in going and coming back, the distance between his house and school?- a)8km
- b)10km
- c)12km
- d)14km
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A boy goes to school from his home at a speed of 4 km/hr and returns at a speed of 6 km/hr. If in total he took 5 hours in going and coming back, the distance between his house and school?
a)
8km
b)
10km
c)
12km
d)
14km
e)
None of these
|
|
Vanakkam Studios answered |
12km
A man traveled 100 km by Bike in 2 hours. He then traveled in Bus for 8 hrs and then Train in 9 hrs. Ratio of Speeds of Bus to Train is 4:5. If speed of train is 4/5 of Bike speed then the entire journey covered by him in Km is?- a)516 Km
- b)616 Km
- c)716 Km
- d)816 Km
- e)None
Correct answer is option 'C'. Can you explain this answer?
A man traveled 100 km by Bike in 2 hours. He then traveled in Bus for 8 hrs and then Train in 9 hrs. Ratio of Speeds of Bus to Train is 4:5. If speed of train is 4/5 of Bike speed then the entire journey covered by him in Km is?
a)
516 Km
b)
616 Km
c)
716 Km
d)
816 Km
e)
None
|
|
Nikita Singh answered |
Speed of train = 50
Bus = 32
Train = 40
Distance = 100+32*8+40*9 = 716
Bus = 32
Train = 40
Distance = 100+32*8+40*9 = 716
Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much time Car B will be 20Km ahead of Car A?- a)5 Hours
- b)6 Hours
- c)8 Hours
- d)11 Hours
- e)None
Correct answer is option 'B'. Can you explain this answer?
Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much time Car B will be 20Km ahead of Car A?
a)
5 Hours
b)
6 Hours
c)
8 Hours
d)
11 Hours
e)
None
|
|
Alok Verma answered |
20 =40*(t-5) – 20*t
T = 11
11-5 = 6
T = 11
11-5 = 6
Vijay takes 4 hr in walking at certain place and return back. While it takes 3 hrs in walking at certain place and riding back. Find the time Vijay will take to ride both sides- a)1.5hr
- b)2 hr
- c)2.5 hr
- d)3.5 hr
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Vijay takes 4 hr in walking at certain place and return back. While it takes 3 hrs in walking at certain place and riding back. Find the time Vijay will take to ride both sides
a)
1.5hr
b)
2 hr
c)
2.5 hr
d)
3.5 hr
e)
None of these
|
Vijay C answered |
Time taken in first event, (from AtoB and back from BtoA) = 4hr
Time taken to walk to walk AtB/BtA= 4/2 = 2hrs
Time taken to walk from AtB and ride from BtA=3hrs
Time takes to ride back
=total time - time to walk
=3-2
=1hr
Time to ride from AtB and from BtA=1+1=2hrs
hence B)
Time taken to walk to walk AtB/BtA= 4/2 = 2hrs
Time taken to walk from AtB and ride from BtA=3hrs
Time takes to ride back
=total time - time to walk
=3-2
=1hr
Time to ride from AtB and from BtA=1+1=2hrs
hence B)
Two trains 210 meters and 180 meters are running on parallel track at the speed of 72km/hr and 45km/hr respectively. The time taken by them to cross each other, if they are running in opposite direction?- a)8 sec
- b)10 sec
- c)12 sec
- d)15 sec
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Two trains 210 meters and 180 meters are running on parallel track at the speed of 72km/hr and 45km/hr respectively. The time taken by them to cross each other, if they are running in opposite direction?
a)
8 sec
b)
10 sec
c)
12 sec
d)
15 sec
e)
None of these
|
Sagar Sharma answered |
Approach:
We will first calculate the relative speed of the two trains when they are running in opposite directions. Then, we will use the formula Time = Distance/Speed to find the time taken by the trains to cross each other.
Calculations:
- Speed of the first train = 72 km/hr = 72 * 5/18 m/s = 20 m/s
- Speed of the second train = 45 km/hr = 45 * 5/18 m/s = 12.5 m/s
Relative Speed:
When two objects move in opposite directions, their relative speed is the sum of their individual speeds.
Relative speed = Speed of first train + Speed of second train
Relative speed = 20 m/s + 12.5 m/s = 32.5 m/s
Time taken to cross each other:
- Total distance to be covered = Sum of lengths of both trains = 210 m + 180 m = 390 m
- Time = Distance / Relative speed
- Time = 390 m / 32.5 m/s = 12 seconds
Therefore, the time taken by the two trains to cross each other when they are running in opposite directions is 12 seconds. Hence, the correct answer is option C.
A boat whose speed in 20 km/hr in still water goes 40 km downstream and comes back in a total of 5 hours. The approx. speed of the stream (in km/hr) is:- a)6 km/hr
- b)9 km/hr
- c)12 km/hr
- d)16 km/hr
- e)18 km/hr
Correct answer is option 'B'. Can you explain this answer?
A boat whose speed in 20 km/hr in still water goes 40 km downstream and comes back in a total of 5 hours. The approx. speed of the stream (in km/hr) is:
a)
6 km/hr
b)
9 km/hr
c)
12 km/hr
d)
16 km/hr
e)
18 km/hr
|
|
Cstoppers Instructors answered |
Let the speed of the stream be x km/hr. Then,
Speed downstream = (20 + x) km/hr,
Speed upstream = (20 – x) km/hr.
40/20+x + 40/20-x = 5
X = 9 approx
Speed downstream = (20 + x) km/hr,
Speed upstream = (20 – x) km/hr.
40/20+x + 40/20-x = 5
X = 9 approx
Anita goes to College at 20 km/h and reaches college 4 minutes late. Next time she goes at 25 km/h and reaches the college 2 minutes earlier than the scheduled time. What is the distance of her school?- a)16 km
- b)12 km
- c)15 km
- d)10 km
Correct answer is option 'D'. Can you explain this answer?
Anita goes to College at 20 km/h and reaches college 4 minutes late. Next time she goes at 25 km/h and reaches the college 2 minutes earlier than the scheduled time. What is the distance of her school?
a)
16 km
b)
12 km
c)
15 km
d)
10 km
|
|
Anaya Patel answered |
20*25/(25-20)*6/60=10.
Speed of a man in still water is 5 km/hr and the river is running at 3km/hr. The total time taken to go to a place and come back is 10 hours. What is the distance travelled?- a)10 km
- b)16 km
- c)24 km
- d)32 km
- e)36 km
Correct answer is option 'D'. Can you explain this answer?
Speed of a man in still water is 5 km/hr and the river is running at 3km/hr. The total time taken to go to a place and come back is 10 hours. What is the distance travelled?
a)
10 km
b)
16 km
c)
24 km
d)
32 km
e)
36 km
|
|
Preeti Khanna answered |
Down speed = 5+3 = 8
Up speed = 5-3 = 2
Let distance travelled = X
(X/8)+(X/2) = 10
X= 16 km
Total distance is 16+16 = 32
Up speed = 5-3 = 2
Let distance travelled = X
(X/8)+(X/2) = 10
X= 16 km
Total distance is 16+16 = 32
A boat can travel 20 km downstream in 24 min. The ratio of the speed of the boat in still water to the speed of the stream is 4 : 1. How much time will the boat take to cover 15 km upstream?- a)20 min
- b)22 min
- c)25 min
- d)30 min
- e)35 min
Correct answer is option 'D'. Can you explain this answer?
A boat can travel 20 km downstream in 24 min. The ratio of the speed of the boat in still water to the speed of the stream is 4 : 1. How much time will the boat take to cover 15 km upstream?
a)
20 min
b)
22 min
c)
25 min
d)
30 min
e)
35 min
|
KS Coaching Center answered |
Down speed = 20/24*60 = 50km/hr
4:1 = 4x:x
Downstream speed = 4x+x = 5x
Upstream speed = 4x-x = 3x
5x = 50; x = 10
so up speed 3*10 = 30
Time = 15/30*60 = 30min.
4:1 = 4x:x
Downstream speed = 4x+x = 5x
Upstream speed = 4x-x = 3x
5x = 50; x = 10
so up speed 3*10 = 30
Time = 15/30*60 = 30min.
A train travelling with 54 km/hr takes 20 second to cross a bridge. Another train 70 meter shorter crosses the same bridge at 36 km/hr. Find the time taken by the second train to cross the bridge.- a)23 sec
- b)24 sec
- c)25 sec
- d)26 sec
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
A train travelling with 54 km/hr takes 20 second to cross a bridge. Another train 70 meter shorter crosses the same bridge at 36 km/hr. Find the time taken by the second train to cross the bridge.
a)
23 sec
b)
24 sec
c)
25 sec
d)
26 sec
e)
None of these
|
|
Yash Patel answered |
Let L and B are length of train and bridge respectively.
L + B = 54*5/18*20 = 300 meter
L + B – 70 = 36*5/18*t = 230, se we get t = 23 sec
L + B = 54*5/18*20 = 300 meter
L + B – 70 = 36*5/18*t = 230, se we get t = 23 sec
An inspector is 228 meter behind the thief. The inspector runs 42 meters and the thief runs 30 meters in a minute. In what time will the inspector catch the thief?- a)19 minutes
- b)20 minutes
- c)18 minutes
- d)21 minutes
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
An inspector is 228 meter behind the thief. The inspector runs 42 meters and the thief runs 30 meters in a minute. In what time will the inspector catch the thief?
a)
19 minutes
b)
20 minutes
c)
18 minutes
d)
21 minutes
e)
None of these
|
|
Anaya Patel answered |
inspector s 228 meter behind the thief and now after some x distance he will catch the thief. So,
x/30 = (228 + x)/42, we will get x = 570m
so time taken by inspector to catch the thief = (228+570)/42 = 19 minutes
x/30 = (228 + x)/42, we will get x = 570m
so time taken by inspector to catch the thief = (228+570)/42 = 19 minutes
A journey of 800 km is done in a total of 10 hours, If 320 km is travel by train and remaining by bus. The same journey is done in 8 hours if 240 km is travel by train and remaining is done by bus. Find the ratio of the speed of train to bus.- a)2:11
- b)3:11
- c)1:11
- d)4:11
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A journey of 800 km is done in a total of 10 hours, If 320 km is travel by train and remaining by bus. The same journey is done in 8 hours if 240 km is travel by train and remaining is done by bus. Find the ratio of the speed of train to bus.
a)
2:11
b)
3:11
c)
1:11
d)
4:11
e)
None of these
|
|
Preeti Khanna answered |
10 = 320/st + 480/sb and
8 = 240/st + 560/sb
st and sb are the speeds of train and bus respectively
8 = 240/st + 560/sb
st and sb are the speeds of train and bus respectively
Two Vans start from a place with a speed of 50 kmph at an interval of 12 minutes. What is the speed of a car coming from the opposite direction towards the place if the car meets the vans at an interval of 10 minutes?- a)13 kmph
- b)10 kmph
- c)14 kmph
- d)16 kmph
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Two Vans start from a place with a speed of 50 kmph at an interval of 12 minutes. What is the speed of a car coming from the opposite direction towards the place if the car meets the vans at an interval of 10 minutes?
a)
13 kmph
b)
10 kmph
c)
14 kmph
d)
16 kmph
e)
None of these
|
|
Faizan Khan answered |
50*12/60 = 10/60 * (50+x)
600 = 500 + 10x
x = 10 kmph
600 = 500 + 10x
x = 10 kmph
A car travels from a place A to B in 7 hour. It covers half the distance at 30 kmph and the remaining distance at 40 kmph, what is the total distance between A and B?- a) 120 Km
- b) 250 Km
- c)240 Km
- d)150 Km
Correct answer is option 'C'. Can you explain this answer?
A car travels from a place A to B in 7 hour. It covers half the distance at 30 kmph and the remaining distance at 40 kmph, what is the total distance between A and B?
a)
120 Km
b)
250 Km
c)
240 Km
d)
150 Km
|
Harsh Barapatre answered |
1)The car is is travel from A to B in 7 hr.
2)and it covers the x/2 distance at 30 kmph and the remaining distance at 40kmph.
3)while the total distance between A and B is ?
7= D/2×30 + D/2×40
7= D/60 + D/80
7=D(60+80)/4800
7=D 140/4800
7=D7/240
1=D/240
thus,D = 240 Kms.
2)and it covers the x/2 distance at 30 kmph and the remaining distance at 40kmph.
3)while the total distance between A and B is ?
7= D/2×30 + D/2×40
7= D/60 + D/80
7=D(60+80)/4800
7=D 140/4800
7=D7/240
1=D/240
thus,D = 240 Kms.
The driver of an ambulance sees a college bus 40 m ahead of him after 20 seconds, the college bus is 60 meter behind. If the speed of the ambulance is 30 km/h, what is the speed of the college bus?- a)10 kmph
- b)12 kmph
- c)15 kmph
- d)22 kmph
Correct answer is option 'B'. Can you explain this answer?
The driver of an ambulance sees a college bus 40 m ahead of him after 20 seconds, the college bus is 60 meter behind. If the speed of the ambulance is 30 km/h, what is the speed of the college bus?
a)
10 kmph
b)
12 kmph
c)
15 kmph
d)
22 kmph
|
|
Rajeev Kumar answered |
Relative Speed = (Total distance)/total time
= (60+40) /20 = 5 m/s = (5*18)/5 = 18 kmph
Relative Speed = (speed of ambulance – speed of College bus)
Speed of College bus = speed of ambulance – relative speed.
= 30-18 = 12 kmph.
= (60+40) /20 = 5 m/s = (5*18)/5 = 18 kmph
Relative Speed = (speed of ambulance – speed of College bus)
Speed of College bus = speed of ambulance – relative speed.
= 30-18 = 12 kmph.
Rakesh travelled 1800 kilometre by air which formed 3/5 of the total journey. He travels 1/4 of the trip by car and the remaining trip by train. Find the distance travelled by train.- a)350
- b)450
- c)550
- d)650
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Rakesh travelled 1800 kilometre by air which formed 3/5 of the total journey. He travels 1/4 of the trip by car and the remaining trip by train. Find the distance travelled by train.
a)
350
b)
450
c)
550
d)
650
e)
None of these
|
|
Sagar Sharma answered |
To find the distance travelled by train, we need to find the total distance of the journey and subtract the distance travelled by air and by car.
Let's assume the total distance of the journey is D.
Distance travelled by air: 3/5 of the total journey = (3/5) * D = 1800 km
Distance travelled by car: 1/4 of the total journey = (1/4) * D
Now, we can calculate the remaining distance travelled by train:
Remaining distance = Total distance - Distance travelled by air - Distance travelled by car
Remaining distance = D - 1800 km - (1/4) * D
Since the remaining distance is travelled by train, we need to find the value of D.
We know that the distance travelled by air is 1800 km, which is equal to 3/5 of the total distance:
1800 km = (3/5) * D
To find D, we can solve the equation:
D = (1800 km * 5) / 3
D = 3000 km
Now, we can substitute the value of D in the equation for the remaining distance:
Remaining distance = 3000 km - 1800 km - (1/4) * 3000 km
Remaining distance = 3000 km - 1800 km - 750 km
Remaining distance = 450 km
Therefore, the distance travelled by train is 450 km.
Hence, the correct answer is option 'B' (450 km).
Let's assume the total distance of the journey is D.
Distance travelled by air: 3/5 of the total journey = (3/5) * D = 1800 km
Distance travelled by car: 1/4 of the total journey = (1/4) * D
Now, we can calculate the remaining distance travelled by train:
Remaining distance = Total distance - Distance travelled by air - Distance travelled by car
Remaining distance = D - 1800 km - (1/4) * D
Since the remaining distance is travelled by train, we need to find the value of D.
We know that the distance travelled by air is 1800 km, which is equal to 3/5 of the total distance:
1800 km = (3/5) * D
To find D, we can solve the equation:
D = (1800 km * 5) / 3
D = 3000 km
Now, we can substitute the value of D in the equation for the remaining distance:
Remaining distance = 3000 km - 1800 km - (1/4) * 3000 km
Remaining distance = 3000 km - 1800 km - 750 km
Remaining distance = 450 km
Therefore, the distance travelled by train is 450 km.
Hence, the correct answer is option 'B' (450 km).
Sohail covers a distance by walking for 6 hours. While returning, his speed decreases by 2kmph and he takes 9 hours to cover the same distance. What was his speed while returning?- a)2 kmph
- b)5 kmph
- c)4 kmph
- d)7 kmph
Correct answer is option 'C'. Can you explain this answer?
Sohail covers a distance by walking for 6 hours. While returning, his speed decreases by 2kmph and he takes 9 hours to cover the same distance. What was his speed while returning?
a)
2 kmph
b)
5 kmph
c)
4 kmph
d)
7 kmph
|
|
Rhea Reddy answered |
The speed of Sohail in return journey = x
6(x + 2) = 9x
⇒ 6x + 12 = 9x
⇒ 9x – 6x = 12
x = 4kmph
6(x + 2) = 9x
⇒ 6x + 12 = 9x
⇒ 9x – 6x = 12
x = 4kmph
A boat takes 28 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 6km/hr and the speed of the boat in still water is 9 km/hr, what is the distance between A and B?- a)115 km
- b)120 km
- c)140 km
- d)165 km
- e)150 km
Correct answer is option 'B'. Can you explain this answer?
A boat takes 28 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 6km/hr and the speed of the boat in still water is 9 km/hr, what is the distance between A and B?
a)
115 km
b)
120 km
c)
140 km
d)
165 km
e)
150 km
|
|
KS Coaching Center answered |
Downstream speed = 9+6 = 15
Upstream speed = 9-6 = 3
Now total time is 28 hours
If distance between A and B is d, then distance BC = d/2
Now distance/speed = time, so
d/15 + (d/2)/3 = 28
Solve, d = 120 km
Upstream speed = 9-6 = 3
Now total time is 28 hours
If distance between A and B is d, then distance BC = d/2
Now distance/speed = time, so
d/15 + (d/2)/3 = 28
Solve, d = 120 km
Two stations P and Q are 400 km apart from each other. One train start from P at a speed of 60km/hr towards Q and after 2 hours another train starts from Q towards P at 45 km/hr. At what distance from P the train will meet.- a)220 km
- b)240 km
- c)260 km
- d)280 km
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Two stations P and Q are 400 km apart from each other. One train start from P at a speed of 60km/hr towards Q and after 2 hours another train starts from Q towards P at 45 km/hr. At what distance from P the train will meet.
a)
220 km
b)
240 km
c)
260 km
d)
280 km
e)
None of these
|
|
Divey Sethi answered |
First train will travel 120 km before the start of second train, Now the distance between them is 280km.
Now, x/60 = (280 – x)/45
We get x = 160 km, so distance from P = 120 + 160 = 280 km
We get x = 160 km, so distance from P = 120 + 160 = 280 km
A train running at 45 km/hr takes 36 sec to pass a platform. Next, the train takes 12 sec to pass a man walking at the speed of 15 km/hr in the same direction. Find the length of the platform.- a)250m
- b)300m
- c)350m
- d)400m
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A train running at 45 km/hr takes 36 sec to pass a platform. Next, the train takes 12 sec to pass a man walking at the speed of 15 km/hr in the same direction. Find the length of the platform.
a)
250m
b)
300m
c)
350m
d)
400m
e)
None of these
|
Bank Exams India answered |
Let ‘T’ and ‘P’ are the length of train and platform respectively
T = 12*30*5/18 = 100 meter
P + 100 = 45*5/18*36
P= 350
T = 12*30*5/18 = 100 meter
P + 100 = 45*5/18*36
P= 350
Two Cars started at same time, same place and towards same direction. First Car goes at a speed of 5km/hr in first and 7 Km/hr in second hour and repeats the cycle over the entire journey. Similarly second Car goes at 4km/hr in first hour and 9km/hr in second hour and repeats the cycle over the entire journey.Then these two Cars for the first time for after how many hours of journey?- a)3 Hours
- b)6 Hours
- c)9 Hours
- d)12 Hours
- e)None
Correct answer is option 'A'. Can you explain this answer?
Two Cars started at same time, same place and towards same direction. First Car goes at a speed of 5km/hr in first and 7 Km/hr in second hour and repeats the cycle over the entire journey. Similarly second Car goes at 4km/hr in first hour and 9km/hr in second hour and repeats the cycle over the entire journey.Then these two Cars for the first time for after how many hours of journey?
a)
3 Hours
b)
6 Hours
c)
9 Hours
d)
12 Hours
e)
None
|
|
Aarav Sharma answered |
First car : 5,12,17
Second Car: 4,3,17
A thief is spotted by a policeman from a distance of 200 metre. When the policeman starts chasing , the thief also starts running. If the speed of the thief be 16kmph and that of policeman be 20kmph, how far the thief will have run before he is overtaken?- a)800 m
- b)700 m
- c)650 m
- d)750 m
Correct answer is option 'A'. Can you explain this answer?
A thief is spotted by a policeman from a distance of 200 metre. When the policeman starts chasing , the thief also starts running. If the speed of the thief be 16kmph and that of policeman be 20kmph, how far the thief will have run before he is overtaken?
a)
800 m
b)
700 m
c)
650 m
d)
750 m
|
|
Faizan Khan answered |
d = 200 m, a = 16kmph = 40/9 m/s, b = 20kmph = 50/9 m/s
Required Distance D = d*(a/b-a)b= 200*(40/9/10/9) = 800m
Required Distance D = d*(a/b-a)b= 200*(40/9/10/9) = 800m
A train leaves Chennai for Bangalore at 2:15 p.m. and travels at the rate of 50 kmph. Another train leaves Bangalore for Chennai at 1:35 p.m. and travels at the rate of 60 kmph. If the distance between Bangalore and Chennai is 590 km at what distance from Chennai will the two trains meet?- a)280 km
- b)320 km
- c)250 km
- d)225 km
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A train leaves Chennai for Bangalore at 2:15 p.m. and travels at the rate of 50 kmph. Another train leaves Bangalore for Chennai at 1:35 p.m. and travels at the rate of 60 kmph. If the distance between Bangalore and Chennai is 590 km at what distance from Chennai will the two trains meet?
a)
280 km
b)
320 km
c)
250 km
d)
225 km
e)
None of these
|
|
Anaya Patel answered |
Total Distance = 590 km
Distance in 40 min = 60*40/60=40km
Remaining=550 km
Time = 550/110=5hr
Reqd Distance = 50*5=250 km
Distance in 40 min = 60*40/60=40km
Remaining=550 km
Time = 550/110=5hr
Reqd Distance = 50*5=250 km
Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be- a)400m
- b)500m
- c)600m
- d)650m
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be
a)
400m
b)
500m
c)
600m
d)
650m
e)
None of these
|
|
Rajeev Kumar answered |
Using pythagarous theorem,
distance travelled by first train = 36*5/18*30 = 300m
distance travelled by second train = 48*5/18*30 = 400m
so distance between them =√(90000 + 160000) = √250000 = 500m
distance travelled by first train = 36*5/18*30 = 300m
distance travelled by second train = 48*5/18*30 = 400m
so distance between them =√(90000 + 160000) = √250000 = 500m
A and B set out at the same time to walk towards each other respectively from a place P and Q 144 km apart. A walks at the constant speed of 8 km/h, while B walks 4 km in the first hour, 5 km in the second hour, 6 km in the third hour and so on. Then the “A” will meet “B” at?- a)36 km
- b)72 km
- c)56 km
- d)26 km
Correct answer is option 'B'. Can you explain this answer?
A and B set out at the same time to walk towards each other respectively from a place P and Q 144 km apart. A walks at the constant speed of 8 km/h, while B walks 4 km in the first hour, 5 km in the second hour, 6 km in the third hour and so on. Then the “A” will meet “B” at?
a)
36 km
b)
72 km
c)
56 km
d)
26 km
|
|
Naroj Boda answered |
Distance travelled by them in first hour = 12 km
Distance travelled by them in second hour = 13 km and so on
In 9 hours both will cover exactly 144 km.
In 9 hours each will cover half the total distance.
Distance travelled by them in second hour = 13 km and so on
In 9 hours both will cover exactly 144 km.
In 9 hours each will cover half the total distance.
Anu normally takes 4 hours more than the time taken by Sachin to walk D km. If Anu doubles her speed, she can make it in 2 hours less than that of Sachin. How much time does Sachin require for walking D km?- a)10 hours
- b)4 hours
- c)8 hours
- d)9 hours
Correct answer is option 'C'. Can you explain this answer?
Anu normally takes 4 hours more than the time taken by Sachin to walk D km. If Anu doubles her speed, she can make it in 2 hours less than that of Sachin. How much time does Sachin require for walking D km?
a)
10 hours
b)
4 hours
c)
8 hours
d)
9 hours
|
|
Aarav Sharma answered |
Let's assume that Sachin takes x hours to walk D km.
- Anu normally takes 4 hours more than Sachin to walk the same distance. So, Anu takes (x + 4) hours to walk D km.
- If Anu doubles her speed, she can complete the distance in 2 hours less than Sachin. So, Anu takes (x - 2) hours to walk D km.
To find the value of x, we can set up an equation using the given information:
(x + 4) = 2(x - 2)
Simplifying the equation:
x + 4 = 2x - 4
Bringing like terms together:
x - 2x = -4 - 4
-x = -8
Dividing both sides by -1:
x = 8
Therefore, Sachin requires 8 hours to walk D km.
Hence, the correct answer is option C) 8 hours.
- Anu normally takes 4 hours more than Sachin to walk the same distance. So, Anu takes (x + 4) hours to walk D km.
- If Anu doubles her speed, she can complete the distance in 2 hours less than Sachin. So, Anu takes (x - 2) hours to walk D km.
To find the value of x, we can set up an equation using the given information:
(x + 4) = 2(x - 2)
Simplifying the equation:
x + 4 = 2x - 4
Bringing like terms together:
x - 2x = -4 - 4
-x = -8
Dividing both sides by -1:
x = 8
Therefore, Sachin requires 8 hours to walk D km.
Hence, the correct answer is option C) 8 hours.
A police saw a Thief at a distance of 2km. When Police started chasing him Thief also started running. If the ratio of Speeds of Police to Thief is 5:4. Then thief was caught at a certain distance then how many Kms did police run to catch the Thief?- a)5 Km
- b)6 Km
- c)8 Km
- d)10 Km
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
A police saw a Thief at a distance of 2km. When Police started chasing him Thief also started running. If the ratio of Speeds of Police to Thief is 5:4. Then thief was caught at a certain distance then how many Kms did police run to catch the Thief?
a)
5 Km
b)
6 Km
c)
8 Km
d)
10 Km
e)
Cannot be determined
|
|
Bank Exams India answered |
2+x/5 = x/4
X = 8
Police = 8+2 = 10
X = 8
Police = 8+2 = 10
A truck covers a distance of 376 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 14 km more than that travelled by the truck ?- a)6 hours
- b)5 hours
- c)7 hours
- d)8 hours
Correct answer is option 'A'. Can you explain this answer?
A truck covers a distance of 376 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 14 km more than that travelled by the truck ?
a)
6 hours
b)
5 hours
c)
7 hours
d)
8 hours
Speed of the truck = Distance/time = 376/8 = 47 kmph
Now, speed of car = (speed of truck + 18) kmph = (47 + 18) = 65 kmph
Distance travelled by car = 376 + 14 = 390 km
Time taken by car = Distance/Speed = 390/65 = 6 hours.
Now, speed of car = (speed of truck + 18) kmph = (47 + 18) = 65 kmph
Distance travelled by car = 376 + 14 = 390 km
Time taken by car = Distance/Speed = 390/65 = 6 hours.
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