All Courses
Get the App Signup / Login
Sign in Open App
All Exams  >   RRB NTPC/ASM/CA/TA  >   Mathematics for RRB NTPC / ASM  >   All Questions

All questions of Profit & Loss for RRB NTPC/ASM/CA/TA Exam

Clear all your RRB NTPC/ASM/CA/TA doubts with EduRev

Arun sells an article at 20% profit to Bala, Bala sells it to Catherine at 10% profit. Catherine sells it to Dinesh at Rs. 16 profit. The difference between the cost price of Dinesh and cost price of Arun was Rs. 500. How much did Bala pay to Arun for the article? 
  • a)
    Rs.1350
  • b)
    Rs.1815
  • c)
    Rs.1650
  • d)
    Rs.1750
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Kirti Dahiya answered
"use of successive percentage" Let article cost is 100x...,, 100x -> 120x -> 132x -> (132+16) Arun. Bala. Catherine Dinesh The difference between the cost price of Dinesh and cost price of Arun was Rs. 500 So, (132x+16) - 100x = 500 X= 121/8 Bala pay to Arun for the article is 120x => 120* 121/8 => 1815

Vinod incurred a loss of 45 per cent on selling an article for Rs. 3740. What was the cost price of the article.
  • a)
    Rs. 5725                   
  • b)
    Rs. 5080
  • c)
    Rs. 6250                   
  • d)
    Rs. 6400  
  • e)
    None of these
Correct answer is 'E'. Can you explain this answer?

Aarav Sharma answered
Given:
Selling price of an article = Rs. 3740
Loss percentage = 45%

To find:
Cost price of the article

Let the cost price of the article be x.

We know that the selling price of an article is given by:
Selling price = Cost price + Profit or Loss

As Vinod has incurred a loss of 45%, his selling price is only 55% of the cost price.
Hence, we can write:

Selling price = 55% of Cost price
⇒ 3740 = 0.55x

Solving the above equation for x, we get:
x = 6800

Therefore, the cost price of the article is Rs. 6800.

The correct answer is 'Option E' (None of these).

Anu sold 2 books at Rs. 1.40 each. Her profit on one was 20% and her loss on the other was 20%. Then she made
  • a)
    No loss no gain                     
  • b)
    gained 20 paise
  • c)
    lost 12 paise             
  • d)
    lost 20 paise
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Stellar Institute answered
It the SP for both the Items is same and
there is a profit of x% and a loss of x%,
then the resultant loss = x²/100%
So, the resultant loss = 4%.
Total SP = 2.80, which is equal to 96% of CP of 2 books.
.: CP of 2 books = 2.80 × 100/96 = 2.92 (Appx);
:. Loss = 2.92 – 2.80 = .12 = 12 paise.

The marked price of a book is Rs. 160 and it is sold for Rs. 136. What was the rate of discount.
  • a)
    15%                         
  • b)
    20%
  • c)
    12%                         
  • d)
    25%
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Sushmita Chaudhary answered
Cost price of book= 160
selling price of book=136

now, rate of discount = loss % (as discount only leads to some kind of loss)

so CP > SP
so loss = CP - SP = 160-136 = 24

loss % = ( loss / CP ) ÷ 100
=( 24 / 160 ) ÷ 100
= 15 %

So rate of discount = 15%

Shopkeeper purchased some goods for Rs.900 and sold one-third of the goods at a loss of  what 12%, then at gain % should the remainder goods he sold to gain 18% profit on the whole transaction ?
  • a)
    31%
  • b)
    26%
  • c)
    33%
  • d)
    18%
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Aarav Sharma answered
Given:
- Cost price of goods = Rs. 900
- One-third of the goods sold at a loss of 12%

To find:
- The gain percentage at which the remaining goods should be sold to gain an 18% profit on the whole transaction

Solution:

Let's calculate the selling price of one-third of the goods sold at a loss of 12%.

Step 1: Calculate the selling price of one-third of the goods at a loss of 12%
- Loss percentage = 12%
- Selling price = Cost price - Loss
- Loss = (Loss percentage/100) * Cost price
- Loss = (12/100) * 900
- Loss = 108
- Selling price = 900 - 108
- Selling price = 792

Now, let's calculate the cost price of the remaining goods.

Step 2: Calculate the cost price of the remaining goods
- Cost price = Total cost price - Cost price of goods sold
- Cost price of goods sold = Selling price of goods sold at a loss
- Cost price of goods sold = 792

- Cost price = 900 - 792
- Cost price = 108

Now, let's calculate the selling price of the remaining goods to gain a 18% profit on the whole transaction.

Step 3: Calculate the selling price of the remaining goods to gain a 18% profit
- Profit percentage = 18%
- Selling price = Cost price + Profit
- Profit = (Profit percentage/100) * Cost price
- Profit = (18/100) * 108
- Profit = 19.44
- Selling price = 108 + 19.44
- Selling price = 127.44

Now, let's calculate the gain percentage.

Step 4: Calculate the gain percentage
- Gain = Selling price - Cost price
- Gain = 127.44 - 108
- Gain = 19.44

- Gain percentage = (Gain/Cost price) * 100
- Gain percentage = (19.44/108) * 100
- Gain percentage ≈ 18%

Therefore, the shopkeeper should sell the remaining goods at a gain of approximately 18% to gain an 18% profit on the whole transaction.

Answer:
The correct option is c) 33%.

Meera incurred a loss of 40 per cent on selling an article for Rs. 5700/-. What was the cost of the article.
  • a)
    Rs. 7725                   
  • b)
    Rs. 9080
  • c)
    Rs. 8250                   
  • d)
    Rs. 9400
  • e)
    None of these
Correct answer is option 'E'. Can you explain this answer?

Aarav Sharma answered
Given, Meera incurred a loss of 40% on selling an article for Rs. 5700/-

Let's assume the Cost Price of the article be x.

Selling Price = Cost Price - Loss

5700 = x - (40% of x)

5700 = 0.6x

x = 5700/0.6

x = 9500

Therefore, the cost price of the article is Rs. 9500.

Hence, the correct answer is option E. None of these.

A scientist mixes 10% water in his solution but he is not content with it so he again mixes 10% more water in the previous mixture. What is the profit percentage of the scientist if he sells it at cost price:
  • a)
    15%
  • b)
    21%
  • c)
    18%
  • d)
    16%
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Aarav Sharma answered
Let Initial Quantity of Solution = 100 litre

After mixing 10% water, Quantity of the mixture = 110 * 110 / 100 = 121 litre

CP of One litre of Solution = Rs.1

Total CP = Rs.100

Total SP = Rs.121

Profit = 121 – 100 = 21

Profit % = 21 * 100/100 = 21%

A TV was purchased for Rs. 54000. Its price was marked up by 40%.It was sold at a discount of 20% on the marked price. What was the profit percent of the cost price?
  • a)
    10%
  • b)
    11%
  • c)
    15%
  • d)
    12%
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Aarav Sharma answered
Let's break down the given information and solve the problem step by step.

Given information:
- The TV was purchased for Rs. 54000.
- The price was marked up by 40%.
- It was sold at a discount of 20% on the marked price.

Step 1: Finding the marked price
Since the price was marked up by 40%, we can find the marked price by adding 40% of the purchase price to the purchase price itself.

Marked price = Purchase price + 40% of the purchase price
= Rs. 54000 + 40% of Rs. 54000
= Rs. 54000 + (40/100) * Rs. 54000
= Rs. 54000 + (2/5) * Rs. 54000
= Rs. 54000 + Rs. 21600
= Rs. 75600

So, the marked price of the TV is Rs. 75600.

Step 2: Finding the selling price
Since the TV was sold at a discount of 20% on the marked price, we can find the selling price by deducting 20% of the marked price from the marked price itself.

Selling price = Marked price - 20% of the marked price
= Rs. 75600 - 20% of Rs. 75600
= Rs. 75600 - (20/100) * Rs. 75600
= Rs. 75600 - (1/5) * Rs. 75600
= Rs. 75600 - Rs. 15120
= Rs. 60480

So, the selling price of the TV is Rs. 60480.

Step 3: Finding the profit percentage
Profit percentage can be calculated using the formula:

Profit percentage = (Profit / Cost price) * 100

In this case, the profit is the difference between the selling price and the purchase price, and the cost price is the purchase price.

Profit = Selling price - Purchase price
= Rs. 60480 - Rs. 54000
= Rs. 6480

Profit percentage = (6480 / 54000) * 100
= (12 / 100) * 100
= 12%

Therefore, the profit percentage of the cost price is 12%.

Hence, the correct answer is option D) 12%.

Rahul sells his laptop to Ravi at a loss of 20% who subsequently sells it to Suresh at a profit of 25%. Suresh after finding some defect in the laptop, returns it to Ravi but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Suresh’s loss if Rahul had paid Rs.50,000 for the laptop ?
  • a)
    Rs.6000
  • b)
    Rs.7000
  • c)
    Rs.2000
  • d)
    Rs.5000
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Ravi Singh answered
Solution:

Given:
- Rahul's cost price of laptop = Rs.50,000
- Rahul sells laptop to Ravi at a loss of 20%
- Ravi sells laptop to Suresh at a profit of 25%
- Suresh returns laptop to Ravi and recovers Rs.4.50 for every Rs.5 he paid

Calculations:
1. Rahul's selling price to Ravi:
- Rahul's selling price = 80% of Rs.50,000 (20% loss)
- Rahul's selling price = Rs.40,000

2. Ravi's cost price of laptop:
- Ravi's cost price = Rs.40,000

3. Ravi's selling price to Suresh:
- Ravi's selling price = 125% of Rs.40,000 (25% profit)
- Ravi's selling price = Rs.50,000

4. Amount recovered by Suresh after returning laptop:
- Amount recovered = Rs.4.50 for every Rs.5 paid
- Amount recovered = Rs.4.50 / Rs.5 = 90% of the cost price

5. Suresh's cost price of laptop:
- Suresh's cost price = Rs.50,000

6. Suresh's loss:
- Suresh's loss = Rs.50,000 - Rs.45,000 (Amount recovered)
- Suresh's loss = Rs.5,000

Therefore, the amount of Suresh's loss is Rs.5,000. So, the correct answer is option D: Rs.5,000.0.50/5 * 50,000 = 5000

A trader mixes 25% of solution A to his Solution B and then he sells the whole mixture at the price of Solution B. If the cost price of Solution A be 50% of the cost price of Solution B, what is the net profit percentage?
  • a)
    100/3%
  • b)
    200/7%
  • c)
    100/9%
  • d)
    200/3%
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Preeti Khanna answered
Quantity of Solution B = 100 litre
Quantity of Solution A = 25 litre
CP of 1 litre Solution B = Rs.10
CP of 1 litre Solution A = Rs.5
CP = 100 * 10 + 25 * 5 = 1125
SP = (100 + 25)*10 = 1250
Profit = 1250 – 1125 = 125
% = 125 * 100 / 1125 = 100/9%

Raghu purchased a scooter at 13/15th of its selling price and sold it for 12% more than the selling price. His gain is
  • a)
    20%                         
  • b)
    30%
  • c)
  • d)
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Aspire Academy answered
According to the question,


If they sold 12% more then its, old selling price.
So, new selling price is

= 16.8
∴ Profit = Selling price - Cost price
              = 16.8 - 13
              = 3.8

A boy  sells a Radio to B at a 10 % loss, B sells it to C at 25 % gain and C sells it to D at a loss of 8 %, if D pays Rs 1625 for it then how much does A pay for.
  • a)
    Rs.1620
  • b)
    Rs.1560
  • c)
    Rs.1570
  • d)
    Rs.1760
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Aarav Sharma answered
Given:
- A boy sells a radio to B at a 10% loss.
- B sells it to C at 25% gain.
- C sells it to D at a loss of 8%.
- D pays Rs. 1625 for it.

To find:
- The cost price of the radio for A.

Solution:

Let's assume that the cost price of the radio for A is Rs. x.

Step 1: A sells the radio to B at a 10% loss.

- A sells the radio to B at a loss of 10%.
- So, the selling price of the radio for B = x - (10% of x) = x - 0.1x = 0.9x.

Step 2: B sells the radio to C at a 25% gain.

- B sells the radio to C at a gain of 25%.
- So, the selling price of the radio for C = 0.9x + (25% of 0.9x) = 0.9x + 0.225x = 1.125x.

Step 3: C sells the radio to D at an 8% loss.

- C sells the radio to D at a loss of 8%.
- So, the selling price of the radio for D = 1.125x - (8% of 1.125x) = 1.125x - 0.09x = 1.035x.

Step 4: D pays Rs. 1625 for it.

- So, we have 1.035x = 1625.
- Solving for x, we get x = 1570.

Therefore, the cost price of the radio for A is Rs. 1570.

Hence, option (c) is the correct answer.

A vendor has two types of grapes. One is the fresh grapes containing 80% water and dry grapes containing 25% water. He sells 20 kg dry grapes, by adding water to the dry grapes, at cost price. What is the total profit percentage when after adding water the weight of 20 kg dry grapes increase in the proportion of water in fresh grapes?
  • a)
    265%
  • b)
    200%
  • c)
    280%
  • d)
    275%
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Yash Patel answered
Fresh grapes
Water: Pulp = 80% : 20% = 4 : 1
Dry grapes
Water: Pulp = 25% : 75% = 1 : 3
So out of 20 kg dry grapes, Water : Pulp = 5 kg : 15 kg
After adding of water the ratio of water : pulp is same as the fresh grapes = 4 : 1
After adding water the quantity of Water and Pulp are 60 kg and 15 kg respectively.
% = 55/20 * 100 = 275%

Aaradhana buys rice at Rs.10/kg and sell it in order to earn a profit of 40%. However, her faulty balance shows 1000gm when it is actually 800gm. What is her actual gain percentage?
  • a)
    35%
  • b)
    70%
  • c)
    75%
  • d)
    25%
  • e)
    None of the Above
Correct answer is option 'C'. Can you explain this answer?

Ravi Singh answered
Let price of 1 kg rice = Rs.10.
CP of 800 gm rice = Rs.8.
She wants to earn a profit of 40% on per Kg
SP = 10 + 40% of 10 = Rs. 14 per kg.
Faulty balance shows 800 gm = 1000 gm (1 kg)
She sells 800 gm for Rs.14.
Profit = 14 – 8 = Rs. 6.
Profit(%) = 6/8 * 100 = 75%.

Chapter doubts & questions for Profit & Loss - Mathematics for RRB NTPC / ASM 2025 is part of RRB NTPC/ASM/CA/TA exam preparation. The chapters have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for RRB NTPC/ASM/CA/TA 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

Chapter doubts & questions of Profit & Loss - Mathematics for RRB NTPC / ASM in English & Hindi are available as part of RRB NTPC/ASM/CA/TA exam. Download more important topics, notes, lectures and mock test series for RRB NTPC/ASM/CA/TA Exam by signing up for free.

Mathematics for RRB NTPC / ASM

146 videos|96 docs|98 tests

Signup to see your scores go up within 7 days!

Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup