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There are three galleries in a coal mine. On the first day, two galleries are operative and after some time, the third gallery is made operative. With this, the output of the mine became half as large again. What is the capacity of the second gallery as a percentage of the first, if it is given that a four-month output of the first and the third galleries was the same as the annual output of the second gallery?
- a)60%
- b)64%
- c)65%
- d)70%
Correct answer is option 'A'. Can you explain this answer?
There are three galleries in a coal mine. On the first day, two galleries are operative and after some time, the third gallery is made operative. With this, the output of the mine became half as large again. What is the capacity of the second gallery as a percentage of the first, if it is given that a four-month output of the first and the third galleries was the same as the annual output of the second gallery?
a)
60%
b)
64%
c)
65%
d)
70%
|
Tanishq Sengupta answered |
The third gallery making the capacity ‘half as large again’ means an increase of 50%.
Further, it is given that: 4(first + third) = 12 (second) In order to get to the correct answer, try to fit in the options into this situation.
(Note here that the question is asking you to find the capacity of the second gallery as a percentage of the first.)
If we assume option (a) as correct – 70% the following solution follows:
If the second is 70, then first is 100 and the first + second is 170. Then third will be 85 (50% of first + second).
If the second is 70, then first is 100 and the first + second is 170. Then third will be 85 (50% of first + second).
Then the equation:
4 X (100 + 85) should be equal to 12 X 70
But this is not true.
4 X (100 + 85) should be equal to 12 X 70
But this is not true.
Through trial and error, you can see that the third option fits correctly.
4 X (100 + 80) = 12 X 60.
Hence, it is the correct answer.
4 X (100 + 80) = 12 X 60.
Hence, it is the correct answer.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
- a)Rs. 200
- b)Rs. 250
- c)Rs. 300
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
a)
Rs. 200
b)
Rs. 250
c)
Rs. 300
d)
None of these
|
Ishani Rane answered |
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
= z + 120/100 z = 550
= 11/5 z = 550
= (550 * 5)/11 = 250.
A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:
- a)588 apples
- b)600 apples
- c) 672 apples
- d)700 apples
Correct answer is option 'D'. Can you explain this answer?
a)
588 apples
b)
600 apples
c)
672 apples
d)
700 apples
|
Harshitha Desai answered |
x-x(40/100)=420
x-40x/100=420
or, 60x/100=420
x=42000/60
x= 700
x-40x/100=420
or, 60x/100=420
x=42000/60
x= 700
In solution of sugar and water the ratio of sugar and water by weight is 1:4. This solution is heated and in the process it loses 50% weight. What is the ratio of weight of sugar and water in the final mixture?- a)4:1
- b)2:1
- c)2:3
- d)3.5:2
Correct answer is option 'C'. Can you explain this answer?
In solution of sugar and water the ratio of sugar and water by weight is 1:4. This solution is heated and in the process it loses 50% weight. What is the ratio of weight of sugar and water in the final mixture?
a)
4:1
b)
2:1
c)
2:3
d)
3.5:2
|
Arjun Joshi answered |
Weight of solution = (1+4) = 5 units weight of sugar = 1 unit weight of water after heating =1.5 units Required ration =1 : 1.5 = 2 : 3
In the country of Tattoland, a new term tercentage has been introduced in the place of percentage. While percentage is per 100, tercentage is per 125. What will be the tercentage marks obtained by a student in Tattoland if his percentage of marks is 60?- a)48 tercentage
- b)75 tercentage
- c)60 tercentage
- d)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
In the country of Tattoland, a new term tercentage has been introduced in the place of percentage. While percentage is per 100, tercentage is per 125. What will be the tercentage marks obtained by a student in Tattoland if his percentage of marks is 60?
a)
48 tercentage
b)
75 tercentage
c)
60 tercentage
d)
Cannot be determined
|
Future Foundation Institute answered |
The numerator has been increased by 25%. Hence, denominator will also increase by 25%.
Value in tercentage = 60 x 1.25 = 75 tercentage
Value in tercentage = 60 x 1.25 = 75 tercentage
If 20% of a = b, then b% of 20 is the same as:
- a)4% of a
- b)5% of a
- c)20% of a
- d) None of these
Correct answer is option 'A'. Can you explain this answer?
a)
4% of a
b)
5% of a
c)
20% of a
d)
None of these
|
Subham Basu answered |
20% of a = b => (20/100)a = b
b% of 20 =(b/100) x 20 = (20a/100) x (1/100) x (20) = 4a/100 = 4% of a.
Sailesh is working as a sales executive with a reputed FMCG Company in Hyderabad. As per the Company’s policy, Sailesh gets a commission of 6% on all sales upto Rs. 1,00,000 and 5% on all sales in excess of this amount. If Sailesh remits Rs. 2,65,000 to the FMCG company after deducting his commission, his total sales were worth:- a)Rs. 2,80,000
- b)Rs. 2,90,526
- c)Rs. 2,21,054
- d)Rs. 1,20,000
Correct answer is option 'A'. Can you explain this answer?
Sailesh is working as a sales executive with a reputed FMCG Company in Hyderabad. As per the Company’s policy, Sailesh gets a commission of 6% on all sales upto Rs. 1,00,000 and 5% on all sales in excess of this amount. If Sailesh remits Rs. 2,65,000 to the FMCG company after deducting his commission, his total sales were worth:
a)
Rs. 2,80,000
b)
Rs. 2,90,526
c)
Rs. 2,21,054
d)
Rs. 1,20,000
|
EduRev CLAT answered |
Let total sales be ‘x’
The commission that Sailesh will get is x – 265000
He gets 6% on sales upto 100000 and 5% on sales greater than that.
Calculating his commission on total sales:
0.06*100000 + 0.05(x-100000)
Equating,
0.05x + 1000 = x – 265000
0.95x = 266000
x= 280000
Hence, his sales were worth 280,000
In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
- a)2700
- b)2900
- c)3000
- d)3100
Correct answer is option 'A'. Can you explain this answer?
In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
a)
2700
b)
2900
c)
3000
d)
3100
|
Dhruv Mehra answered |
Read the passage below and solve the questions based on it.
All students of class X took the pre-board test. One third of the class received B: one fourth received B+: one sixth received B-, and one eighth of the class failed (grade C). Everyone else got A.
Q.
What can be the minimum number of students in class X
- a)8
- b)48
- c)24
- d)Cannot be determined
Correct answer is option 'C'. Can you explain this answer?
Read the passage below and solve the questions based on it.
All students of class X took the pre-board test. One third of the class received B: one fourth received B+: one sixth received B-, and one eighth of the class failed (grade C). Everyone else got A.
All students of class X took the pre-board test. One third of the class received B: one fourth received B+: one sixth received B-, and one eighth of the class failed (grade C). Everyone else got A.
Q.
What can be the minimum number of students in class X
a)
8
b)
48
c)
24
d)
Cannot be determined
|
Yash Patel answered |
For (3x/24) to be an integer, min. value of x = 24.
A is an alloy of tin and copper and B is an alloy of copper and zinc. A has 30% copper while B has 50% copper, x gins of A is mixed with 30 gins of B to form another alloy which has 45% copper. What is the value ofx?- a)5
- b)10
- c)15
- d)20
Correct answer is option 'B'. Can you explain this answer?
A is an alloy of tin and copper and B is an alloy of copper and zinc. A has 30% copper while B has 50% copper, x gins of A is mixed with 30 gins of B to form another alloy which has 45% copper. What is the value ofx?
a)
5
b)
10
c)
15
d)
20
|
Debolina Roy answered |
60% of the students of a class are boys and in an examination, 80% of the girls scored more than 40 marks (out of a maximum possible 150 marks). If 60% of the total students scored more than 40 marks in the same examination, find the fraction of the boys who scored 40 marks or less.- a)8/15
- b)7/15
- c)4/5
- d)1/5
Correct answer is option 'B'. Can you explain this answer?
60% of the students of a class are boys and in an examination, 80% of the girls scored more than 40 marks (out of a maximum possible 150 marks). If 60% of the total students scored more than 40 marks in the same examination, find the fraction of the boys who scored 40 marks or less.
a)
8/15
b)
7/15
c)
4/5
d)
1/5
|
Roshni Sen answered |
Assume Total no of students = 100
60% of the students are boys, so Boys = 60, Girls = 40
No. of girls who scored more than 40 marks = 80% of girls = 80% of 40 = 32.
No. of students who scored more than 40 marks = 60% of Total Students = 60
Therefore No. of boys who scored more than 40 marks = 60 - 32 = 28
No. of boys who scored less= Total boys – Boys(scored more) = 60 - 28 = 32
Fraction= (scored less)/Total boys = 32/60 =8/15
60% of the students are boys, so Boys = 60, Girls = 40
No. of girls who scored more than 40 marks = 80% of girls = 80% of 40 = 32.
No. of students who scored more than 40 marks = 60% of Total Students = 60
Therefore No. of boys who scored more than 40 marks = 60 - 32 = 28
No. of boys who scored less= Total boys – Boys(scored more) = 60 - 28 = 32
Fraction= (scored less)/Total boys = 32/60 =8/15
A locomotive engine runs at a speed of 50 km/h when no compartment is attached to it. For every new compartment that is attached to it, the speed of the train is reduced by 10% of the earlier speed. At most, how many compartments can be attached so that the train can cover a distance of 180 km in a maximum of 8 hours?- a)7
- b)5
- c)6
- d)8
Correct answer is option 'A'. Can you explain this answer?
A locomotive engine runs at a speed of 50 km/h when no compartment is attached to it. For every new compartment that is attached to it, the speed of the train is reduced by 10% of the earlier speed. At most, how many compartments can be attached so that the train can cover a distance of 180 km in a maximum of 8 hours?
a)
7
b)
5
c)
6
d)
8
|
|
Nikhil Joshi answered |
Let n = number of components attached, Vn = speed of train when ‘n ’ compartm ents are attached
V0 = 50
V1 = 45
V1 = 45
V2 = 40.5 and so on
At n = 7, we get the answer.
There were only two contestants A and B in the recent assembly election in Bihar at Raghopur constituency. B got 50% of the votes that A got. Had A got 200 votes less, there would have been a tie. What is the total number of votes polled?
- a)1,000
- b)800
- c)1,200
- d)600
Correct answer is option 'D'. Can you explain this answer?
There were only two contestants A and B in the recent assembly election in Bihar at Raghopur constituency. B got 50% of the votes that A got. Had A got 200 votes less, there would have been a tie. What is the total number of votes polled?
a)
1,000
b)
800
c)
1,200
d)
600
|
Bryan Ronnie answered |
1200 is the answer, you have not mentioned invalid votes
An amount is lent at x% p.a. simple interest for two years. Instead, had it been lent at 2x% p.a. simple interest for y more years, then the interest would have been five times the earlier interest. Find the value of y.- a)2
- b)3
- c)4
- d)5
Correct answer is option 'B'. Can you explain this answer?
An amount is lent at x% p.a. simple interest for two years. Instead, had it been lent at 2x% p.a. simple interest for y more years, then the interest would have been five times the earlier interest. Find the value of y.
a)
2
b)
3
c)
4
d)
5
|
|
Sajal Bdw answered |
What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
- a)1
- b)14
- c)20
- d)21
Correct answer is 'C'. Can you explain this answer?
a)
1
b)
14
c)
20
d)
21
|
Gowri Chakraborty answered |
Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
Required percentage = (14/70 * 100)% = 20%
A man spends 25% of his money on food. After spending 50% of the remaining, he is left with Rs 375. How much money was with that man initially?- a)Rs 5,000
- b)Rs 4,000
- c)Rs 5,800
- d)Rs 1,000
Correct answer is option 'D'. Can you explain this answer?
A man spends 25% of his money on food. After spending 50% of the remaining, he is left with Rs 375. How much money was with that man initially?
a)
Rs 5,000
b)
Rs 4,000
c)
Rs 5,800
d)
Rs 1,000
|
Naroj Boda answered |
Assume that he had initially Rs 100.
After spending on food, money left = Rs 75
After spending 50% of Rs 75, he had Rs 37.5
What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
- a)1
- b)14
- c)20
- d)21
Correct answer is option 'C'. Can you explain this answer?
a)
1
b)
14
c)
20
d)
21
|
Nitya Reddy answered |
Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
In an examination, 80% students passed in philosophy and 70% students passed in maths. At the same time 15% failed in both the subjects. If390 students passed in both the subjects, how many students appeared in the examination?- a)500
- b)400
- c)800
- d)600
Correct answer is option 'D'. Can you explain this answer?
In an examination, 80% students passed in philosophy and 70% students passed in maths. At the same time 15% failed in both the subjects. If390 students passed in both the subjects, how many students appeared in the examination?
a)
500
b)
400
c)
800
d)
600
|
Kapil Aggarwal answered |
Here, 85% students are passed in any one of the subjects. Then According to set theory Students passed in both subjects=students passed in maths+students passed in philosophy -students passed in any one Students passed in both subjects = (80%+70%-85%)=65% Let total students be x Then x=(390×100)/65 =600
Practice Quiz or MCQ (Multiple Choice Questions) with solution are available for Practice, which would help you prepare for Percentages under Quantitative Aptitude. You can practice these practice quizzes as per your speed and improvise the topic. The same topic is covered under various competitive examinations like - CAT, GMAT, Bank PO, SSC and other competitive examinations.Q. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:- a)39, 30
- b)41, 32
- c)42, 33
- d)43, 34
Correct answer is option 'C'. Can you explain this answer?
Practice Quiz or MCQ (Multiple Choice Questions) with solution are available for Practice, which would help you prepare for Percentages under Quantitative Aptitude. You can practice these practice quizzes as per your speed and improvise the topic. The same topic is covered under various competitive examinations like - CAT, GMAT, Bank PO, SSC and other competitive examinations.
Q. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
a)
39, 30
b)
41, 32
c)
42, 33
d)
43, 34
|
Raghavendra Sharma answered |
Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
=> 25(x+9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33
In a maternity centre, 5% of all the childbirth cases result in twins. What is the approximate percentage of twins out of total children born?- a)5%
- b)7.6%
- c)9.5%
- d)10.4%
Correct answer is option 'C'. Can you explain this answer?
In a maternity centre, 5% of all the childbirth cases result in twins. What is the approximate percentage of twins out of total children born?
a)
5%
b)
7.6%
c)
9.5%
d)
10.4%
|
Swati Choudhary answered |
Let there be x number of birth cases.
Thus, the number of birth cases of twins = (5*x)/100 = x/20
So the total number of children born are = x + (x/20)(since in cases of twins there is an additional child) = 21x/20
Total number of twin born = (x/20)* 2 = x/10
percentage of twins in the total population born = ((x/10)/(21x/20)) * 100 = 9.5 %
Thus, the number of birth cases of twins = (5*x)/100 = x/20
So the total number of children born are = x + (x/20)(since in cases of twins there is an additional child) = 21x/20
Total number of twin born = (x/20)* 2 = x/10
percentage of twins in the total population born = ((x/10)/(21x/20)) * 100 = 9.5 %
After spending 20% on clothes, 10% on books, 9% on purchasing gift for girl friend and 7% on others, Chandra has a balance of Rs 2,700. How much money was there with him initially?- a)Rs 5,000
- b)Rs 6,000
- c)Rs 7,000
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
After spending 20% on clothes, 10% on books, 9% on purchasing gift for girl friend and 7% on others, Chandra has a balance of Rs 2,700. How much money was there with him initially?
a)
Rs 5,000
b)
Rs 6,000
c)
Rs 7,000
d)
None of these
|
Isha Patel answered |
Let initial Amount = Rs. 100
Money left = 100 – (20 + 10 + 9 + 7)
= Rs. (100 – 46)
= Rs. 54
This 54r = 2700
r = 50
100r = 5000
In the recently concluded referendum in New York, regarding calling back US troops from Iraq, 600 people voted on a referendum, but after some discussion the opponents increased by 150%. The motion was then rejected by a majority two times as great as that by, which it was formerly passed. How many people voted against the initial referendum?- a)400
- b)300
- c)200
- d)500
Correct answer is option 'C'. Can you explain this answer?
In the recently concluded referendum in New York, regarding calling back US troops from Iraq, 600 people voted on a referendum, but after some discussion the opponents increased by 150%. The motion was then rejected by a majority two times as great as that by, which it was formerly passed. How many people voted against the initial referendum?
a)
400
b)
300
c)
200
d)
500
|
Dhanraj Bhadauriya answered |
C
The length of rectangle is increased by 30% and the breadth is decreased by 25%. What is the percentage change in the area of the rectangle due to this?
- a)2.5% increase
- b)25% decrease
- c)25% increase
- d)2.5% decrease
Correct answer is option 'D'. Can you explain this answer?
The length of rectangle is increased by 30% and the breadth is decreased by 25%. What is the percentage change in the area of the rectangle due to this?
a)
2.5% increase
b)
25% decrease
c)
25% increase
d)
2.5% decrease
|
Bank Exams India answered |
Let Length = 100, Breadth =100 Hence, Area = 10000
Now, Length =130, Breadth = 75 Hence, Area = 130 x 75 = 9750
A community service organisation has raised 80% of the donation that it needed for a new building by receiving an average donation of Rs 400 per person from a group of people. To raise the remaining amount, the organisation now intends approaching another group of people which has two-thirds the number of people as the first group. What should be the average donation per person from the new group?- a)Rs 100
- b)Rs 150
- c)Rs 200
- d)Rs 250
Correct answer is option 'B'. Can you explain this answer?
A community service organisation has raised 80% of the donation that it needed for a new building by receiving an average donation of Rs 400 per person from a group of people. To raise the remaining amount, the organisation now intends approaching another group of people which has two-thirds the number of people as the first group. What should be the average donation per person from the new group?
a)
Rs 100
b)
Rs 150
c)
Rs 200
d)
Rs 250
|
Kavya Saxena answered |
The pollution in normal atmosphere is less than 0.01%. Due to leakage of methyl isocyanide (MIC) from a factory the pollution is increased to 20%. If every day 80% of the pollution in the atmosphere is neutralized, in how many days will the atmosphere become normal?- a)6 days
- b)3 days
- c)4 days
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
The pollution in normal atmosphere is less than 0.01%. Due to leakage of methyl isocyanide (MIC) from a factory the pollution is increased to 20%. If every day 80% of the pollution in the atmosphere is neutralized, in how many days will the atmosphere become normal?
a)
6 days
b)
3 days
c)
4 days
d)
None of these
|
Rhea Reddy answered |
The pollution has been increased to 20%.
Every day, 80% pollution is being neutralized, so only 20% of the total pollution remains the next day.
Let x days be needed to bring back the pollution to normal.
Thus, (0.2)x×0.2<0.0001
⇒(0.2)x<0.0005
We have (0.2)4=0.0016 and (0.2)5 = 0.00032 (can guess the value x on the basis of number of digits after decimal point too)
Hence,minimum of 6 days will be required to bring the pollution back to normal.
Let x days be needed to bring back the pollution to normal.
Thus, (0.2)x×0.2<0.0001
⇒(0.2)x<0.0005
We have (0.2)4=0.0016 and (0.2)5 = 0.00032 (can guess the value x on the basis of number of digits after decimal point too)
Hence,minimum of 6 days will be required to bring the pollution back to normal.
If the length and breadth of a rectangular plot are increased by 20% and 50% respectively, Then the new area is how many times the original area?- a)5/8
- b)9/5
- c)3/7
- d)7/3
Correct answer is option 'B'. Can you explain this answer?
If the length and breadth of a rectangular plot are increased by 20% and 50% respectively, Then the new area is how many times the original area?
a)
5/8
b)
9/5
c)
3/7
d)
7/3
|
Aman Chatterjee answered |
LetL= 100, B = 100 A= 10000
New length = 120, new breadth =150 New Area = 18000
New length = 120, new breadth =150 New Area = 18000
The number of girls appearing for an admission test is twice the number of boys. If 30% of the girls and 45% of the boys get admission, the percentage of candidates who do not get admission is- a)65
- b)50
- c)60
- d)35
Correct answer is option 'A'. Can you explain this answer?
The number of girls appearing for an admission test is twice the number of boys. If 30% of the girls and 45% of the boys get admission, the percentage of candidates who do not get admission is
a)
65
b)
50
c)
60
d)
35
|
Riverdale Learning Institute answered |
Let the number of girls be 2x and number of boys be x.
Girls getting admission = 0.6x
Boys getting admission = 0.45x
Number of students not getting admission = 3x – 0.6x -0.45x = 1.95x
Percentage = (1.95x/3x) * 100 = 65%
In an exam of two papers maths and chemistry, 60% of the students pass in maths and 70% pass in chemistry. What is minimum percentage of students who could have failed in both the subjects?- a)0%
- b)30%
- c)40%
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
In an exam of two papers maths and chemistry, 60% of the students pass in maths and 70% pass in chemistry. What is minimum percentage of students who could have failed in both the subjects?
a)
0%
b)
30%
c)
40%
d)
None of these
|
Aravind Mehta answered |
Since, we have to find the minimum percentage, it can be possible that no one has failed in both the subjects.
The cost of an article was Rs.75. The cost was first increased by 20% and later on it was reduced by 20%. The present cost of the article is:- a)Rs. 60
- b)Rs. 75
- c)Rs. 76
- d)Rs. 72
Correct answer is option 'D'. Can you explain this answer?
The cost of an article was Rs.75. The cost was first increased by 20% and later on it was reduced by 20%. The present cost of the article is:
a)
Rs. 60
b)
Rs. 75
c)
Rs. 76
d)
Rs. 72
|
Meera Kapoor answered |
Initial Cost = Rs. 75
After 20% increase in the cost, it becomes,
(75 + 20% of 75) = Rs. 90
Now, Cost is decreased by 20%,
So cost will become, (90 - 20% of 90) = Rs. 72
So, present cost is Rs. 72
After 20% increase in the cost, it becomes,
(75 + 20% of 75) = Rs. 90
Now, Cost is decreased by 20%,
So cost will become, (90 - 20% of 90) = Rs. 72
So, present cost is Rs. 72
If the price of an article rose by 25% every odd year and fell by 20% every even year, what would be the percentage change after 180 years?- a)10% increase
- b)25% increase
- c)No change
- d)20% decrease
Correct answer is 'C'. Can you explain this answer?
If the price of an article rose by 25% every odd year and fell by 20% every even year, what would be the percentage change after 180 years?
a)
10% increase
b)
25% increase
c)
No change
d)
20% decrease
|
Ishani Mishra answered |
Let the original price = Rs 100
Price after 1st year = Rs 125
Price after 2nd year = Rs 100
Hence, after 180 year, there will be no change in the price
Read the passage below and solve the questions based on it Abhay, Bhaskar. Chitra and Danny work in the same office. Abhay S salary is 20% less than Bhaskar "s salary China’s salary is 25% more than Abhay's salary. Danny s salary is 20% more than Abhay's salary.Q.If Chitra received a raise and her new salary is 10% higher than Danny’s, what is her new monthly salary? (use the data from the previous question).- a)Rs 12,750
- b)Rs 13,200
- c)Rs 13,333
- d)Rs 14,225
Correct answer is option 'B'. Can you explain this answer?
Read the passage below and solve the questions based on it Abhay, Bhaskar. Chitra and Danny work in the same office. Abhay S salary is 20% less than Bhaskar "s salary China’s salary is 25% more than Abhay's salary. Danny s salary is 20% more than Abhay's salary.
Q.
If Chitra received a raise and her new salary is 10% higher than Danny’s, what is her new monthly salary? (use the data from the previous question).
a)
Rs 12,750
b)
Rs 13,200
c)
Rs 13,333
d)
Rs 14,225
|
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Avik Choudhury answered |
Chitra’s New Salary = Rs 13200
The income of Amala is 20% more than that of Bimala and 20% less than that of Kamala. If Kamala’s income goes down by 4% and Bimala’s goes up by 10%, then the percentage by which Kamala’s income would exceed Bimala’s is nearest to- a) 31
- b) 29
- c) 28
- d) 32
Correct answer is option 'A'. Can you explain this answer?
The income of Amala is 20% more than that of Bimala and 20% less than that of Kamala. If Kamala’s income goes down by 4% and Bimala’s goes up by 10%, then the percentage by which Kamala’s income would exceed Bimala’s is nearest to
a)
31
b)
29
c)
28
d)
32
|
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EduRev CLAT answered |
Assuming the income of Bimla = 100a, then the income of Amala will be 120a.
And the income of Kamala will be 120a*100/80=150a
If Kamala’s income goes down by 4%, then new income of Kamala = 150a-150a(4/100) = 150a-6a=144a
If Bimla’s income goes up by 10 percent, her new income will be 100a+100a(10/100)=110a
=> Hence the Kamala income will exceed Bimla income by (144a-110a)*100/110a=31
Dataman Infosys Systems is a Lucknow-based software company which is growing tremendously. It doubled its turnover in 1998 from Rs 50 crores in 1997. Then it tripled its turnover in 1999 and grew by 50% in 2000. What is the turnover at the end of 2000?- a)Rs 250 cr
- b)Rs 450 cr
- c)Rs 300 cr
- d)Rs 600 cr
Correct answer is option 'B'. Can you explain this answer?
Dataman Infosys Systems is a Lucknow-based software company which is growing tremendously. It doubled its turnover in 1998 from Rs 50 crores in 1997. Then it tripled its turnover in 1999 and grew by 50% in 2000. What is the turnover at the end of 2000?
a)
Rs 250 cr
b)
Rs 450 cr
c)
Rs 300 cr
d)
Rs 600 cr
|
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Yash Patel answered |
Turnover in 1998 = Rs 100 cr Turnover in 1999 = Rs 300 cr Turnover in 2000 = Rs 450 cr
Because of the budget presented by Yashwant Sinha, the price of sugar increased by 40%. The Verma family reduced its consumption so that expenditure on sugar is up by 12%. If the total consumption of sugarbefore the rise in price was 50 kg. What is the present consumption of sugar (in kg)?- a)48 kg
- b)40 kg
- c)36 kg
- d)32 kg
Correct answer is option 'B'. Can you explain this answer?
Because of the budget presented by Yashwant Sinha, the price of sugar increased by 40%. The Verma family reduced its consumption so that expenditure on sugar is up by 12%. If the total consumption of sugarbefore the rise in price was 50 kg. What is the present consumption of sugar (in kg)?
a)
48 kg
b)
40 kg
c)
36 kg
d)
32 kg
|
Pallabi Deshpande answered |
E = P x C
Using successive Rule,
Let the c consumption due
12 = 40 + x + 40x/100
-28=7x/5
x = –20%
Thus, consumption decreases by 20%
Present consumption = 50 (0.8) = 40 kg.
If a certain weight of an alloy of silver and copper is mixed with 3 kg of pure silver, the resulting alloy will have 90% silver by weight. If the same weight of the initial alloy is mixed with 2 kg of another alloy which has 90% silver by weight, the resulting alloy will have 84% silver by weight. Then, the weight of the initial alloy, in kg, is
- a)3.5
- b)2
- c)2.5
- d)3
Correct answer is option 'D'. Can you explain this answer?
If a certain weight of an alloy of silver and copper is mixed with 3 kg of pure silver, the resulting alloy will have 90% silver by weight. If the same weight of the initial alloy is mixed with 2 kg of another alloy which has 90% silver by weight, the resulting alloy will have 84% silver by weight. Then, the weight of the initial alloy, in kg, is
a)
3.5
b)
2
c)
2.5
d)
3
|
Glance Learning Institute answered |
Let the alloy contain x Kg silver and y kg copper
Now when mixed with 3Kg Pure silver
we get 10x+30 =9x+9y+27
9y-x=3 (1)
Now as per condition 2
silver in 2nd alloy = 2(0.9) =1.8
we get 21y-4x =3 (2)
solving (1) and (2) we get y= 0.6 and x =2.4
so x+y = 3
Now when mixed with 3Kg Pure silver
we get 10x+30 =9x+9y+27
9y-x=3 (1)
Now as per condition 2
silver in 2nd alloy = 2(0.9) =1.8
we get 21y-4x =3 (2)
solving (1) and (2) we get y= 0.6 and x =2.4
so x+y = 3
Out of 51,600 candidates who appeared in an examination, 35% failed, while 15% passed with honours. What is the number of candidates who passed the examination, but failed to obtain honours, assuming that no student who has failed can obtain honours?- a)25,000
- b)30,000
- c)27,309
- d)25,800
Correct answer is option 'D'. Can you explain this answer?
Out of 51,600 candidates who appeared in an examination, 35% failed, while 15% passed with honours. What is the number of candidates who passed the examination, but failed to obtain honours, assuming that no student who has failed can obtain honours?
a)
25,000
b)
30,000
c)
27,309
d)
25,800
|
Pallabi Kaur answered |
Note: 15% of the remaining No. of students failed to obtain honour but got passed = 28509
In the US opinion polls held during August, 60% of the respondents favoured Walter Mondale while the rest favoured George W. Bush. It was found in September polls that 10% of Mondale supporters switched their preference to Bush, while the same percentage of Bush’s supporters also switched their preference toMondale. What percentage of the electorate should now switch their preference from Mondale to Bush so that they are at par?- a)6%
- b)8%
- c)10%
- d)14%
Correct answer is option 'D'. Can you explain this answer?
In the US opinion polls held during August, 60% of the respondents favoured Walter Mondale while the rest favoured George W. Bush. It was found in September polls that 10% of Mondale supporters switched their preference to Bush, while the same percentage of Bush’s supporters also switched their preference toMondale. What percentage of the electorate should now switch their preference from Mondale to Bush so that they are at par?
a)
6%
b)
8%
c)
10%
d)
14%
|
|
Ishani Rane answered |
Let total respondents = 100
People favoured mandale = 60
People favoured Bush = 40
New no. favouring mandale = 60 – 6 + 4 = 58
New no. favouring Bush = 40 – 4 + 6 = 42
Required percentage = 8/58x100=14%
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Quantitative Aptitude (Quant)
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