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There were only two contestants A and B in the recent assembly election in Bihar at Raghopur constituency. B got 50% of the votes that A got. Had A got 200 votes less, there would have been a tie. What is the total number of votes polled?

  • a)
    1,000

  • b)
    800

  • c)
    1,200

  • d)
    600

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
There were only two contestants A and B in the recent assembly electio...
Let A's votes be x and B's votes be y. We are given:



1. y = 0.5x (B got 50% of the votes that A got)

2. x - 200 = y (Had A got 200 votes less, there would have been a tie)



Now we can substitute the first equation into the second equation:



x - 200 = 0.5x

0.5x = 200

x = 400



Now we can find y using the first equation:



y = 0.5 * 400

y = 200



So the total number of votes polled is x + y = 400 + 200 = 600.
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Most Upvoted Answer
There were only two contestants A and B in the recent assembly electio...
1200 is the answer, you have not mentioned invalid votes

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Community Answer
There were only two contestants A and B in the recent assembly electio...
case 1- votes won by: A = v, B = 0.5v => total votes = 1.5v
case 2- votes won by: A = v-200, B = v-200 => total votes = 2v-400

equating total votes: 1.5v = 2v-400 => v = 800
total votes = 1.5v = 1200
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