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Edurev123 
Ordinary Differential Equations 
1. Formulation of Differential Equations 
1.1 Find the differential equations of the family of circles in the ???? -plane passing 
through (-?? ,?? ) and (?? ,?? ) . 
(2009 : 20 Marks) 
Solution: 
Approach : First use conditions to get the general equation of such a circle. Then get the 
differential equations 
General equation of circle in ???? plane is 
?? 2
+?? 2
+2???? +2???? +?? =0 (??) 
It passes through (-1,1) and (1,1) 
 
?                                                           2-2?? +2?? +?? =0?4?? =0
2+2?? +2?? +?? =0??? =-(2?? +2)
 
? General equation of circles passing through (-1,1) and (1,1) is 
?? 2
+?? 2
+2???? -(2?? +2)=0 (???? ) 
where ?? is the single parameter. 
Differentiating (ii) with respect to ?? 
2?? +2?? ????
????
+2?? ????
????
 =0
?                                                                          
????
????
 =
-?? ?? +?? ??? =
-?? ???? /????
-?? 
Putting this in (ii) 
?? 2
+?? 2
+2(
-?? ???? /????
-?? )?? -[2(
-?? ???? /????
-?? )+2]=0
 ?                      ?? 2
-?? 2
-
2????
???? /????
+
2?? ???? /????
+2?? -2=0
 ?                                                                                      
????
????
=
?? 2
-?? 2
-2?? +2
2?? (1-?? )
 
which is the required differential equation. 
Page 2


Edurev123 
Ordinary Differential Equations 
1. Formulation of Differential Equations 
1.1 Find the differential equations of the family of circles in the ???? -plane passing 
through (-?? ,?? ) and (?? ,?? ) . 
(2009 : 20 Marks) 
Solution: 
Approach : First use conditions to get the general equation of such a circle. Then get the 
differential equations 
General equation of circle in ???? plane is 
?? 2
+?? 2
+2???? +2???? +?? =0 (??) 
It passes through (-1,1) and (1,1) 
 
?                                                           2-2?? +2?? +?? =0?4?? =0
2+2?? +2?? +?? =0??? =-(2?? +2)
 
? General equation of circles passing through (-1,1) and (1,1) is 
?? 2
+?? 2
+2???? -(2?? +2)=0 (???? ) 
where ?? is the single parameter. 
Differentiating (ii) with respect to ?? 
2?? +2?? ????
????
+2?? ????
????
 =0
?                                                                          
????
????
 =
-?? ?? +?? ??? =
-?? ???? /????
-?? 
Putting this in (ii) 
?? 2
+?? 2
+2(
-?? ???? /????
-?? )?? -[2(
-?? ???? /????
-?? )+2]=0
 ?                      ?? 2
-?? 2
-
2????
???? /????
+
2?? ???? /????
+2?? -2=0
 ?                                                                                      
????
????
=
?? 2
-?? 2
-2?? +2
2?? (1-?? )
 
which is the required differential equation. 
 
Alternatively: We can also use equation of circle ?? 2
+(?? -1)
2
+?? (?? -1)=0 and 
proceed. 
1.2 Find the curve for which the part of the tangent cut-off by the axes is bisected 
at the point of tangency.  
(2014 : 10 Marks) 
Solution: 
Let equation of tangent line at point ' ?? ' al 
?? -?? ?? -?? =
????
????
(??) 
Now, its point of intersection with co-ordinate axes are 
?? (0,?? -
?? ????
????
);?? (?? -?? ????
????
,0) 
Given : ' ?? ' is mid point of ???? . 
                                             
So, 
Page 3


Edurev123 
Ordinary Differential Equations 
1. Formulation of Differential Equations 
1.1 Find the differential equations of the family of circles in the ???? -plane passing 
through (-?? ,?? ) and (?? ,?? ) . 
(2009 : 20 Marks) 
Solution: 
Approach : First use conditions to get the general equation of such a circle. Then get the 
differential equations 
General equation of circle in ???? plane is 
?? 2
+?? 2
+2???? +2???? +?? =0 (??) 
It passes through (-1,1) and (1,1) 
 
?                                                           2-2?? +2?? +?? =0?4?? =0
2+2?? +2?? +?? =0??? =-(2?? +2)
 
? General equation of circles passing through (-1,1) and (1,1) is 
?? 2
+?? 2
+2???? -(2?? +2)=0 (???? ) 
where ?? is the single parameter. 
Differentiating (ii) with respect to ?? 
2?? +2?? ????
????
+2?? ????
????
 =0
?                                                                          
????
????
 =
-?? ?? +?? ??? =
-?? ???? /????
-?? 
Putting this in (ii) 
?? 2
+?? 2
+2(
-?? ???? /????
-?? )?? -[2(
-?? ???? /????
-?? )+2]=0
 ?                      ?? 2
-?? 2
-
2????
???? /????
+
2?? ???? /????
+2?? -2=0
 ?                                                                                      
????
????
=
?? 2
-?? 2
-2?? +2
2?? (1-?? )
 
which is the required differential equation. 
 
Alternatively: We can also use equation of circle ?? 2
+(?? -1)
2
+?? (?? -1)=0 and 
proceed. 
1.2 Find the curve for which the part of the tangent cut-off by the axes is bisected 
at the point of tangency.  
(2014 : 10 Marks) 
Solution: 
Let equation of tangent line at point ' ?? ' al 
?? -?? ?? -?? =
????
????
(??) 
Now, its point of intersection with co-ordinate axes are 
?? (0,?? -
?? ????
????
);?? (?? -?? ????
????
,0) 
Given : ' ?? ' is mid point of ???? . 
                                             
So, 
?? -?? ????
????
2
=?? and 
?? -
?? ????
2
=?? 
 
?                                                           ?? =-?? ????
????
 and ?? =-
?? ????
????
 
?                                                       
????
????
=-
?? ??         
?                                                       ?????? +?????? =0         
 
Integrating, we get 
?? 2
+?? 2
=?? which the required curve.  
1.3 Find the differential equation (DE) representing all the circles in the ???? -plane. 
(2017 : 10 Marks) 
Solution: 
Method 1: General equation of circle 
(?? -?? )
2
+(?? -?? )
2
=?? 2
 
Differentiating w.r.t. ?? , 
2(?? -?? )+2(?? -?? )
????
????
 =0
 
??.?? .,                                                            (?? -?? )+(?? -?? )?? 1
=0                                                   (??) 
Differentiating again w.r.t. ?? 
1+(?? -?? )?? 2
+?? 1
2
=0 (???? ) 
Differentiating again w.r.t. ?? 
                                                     (?? -?? )?? 3
+?? 1
?? 2
+2?? 1
?? 2
=0 
i.e., 
(?? -?? )=
-3?? 1
?? 2
?? 3
 
Substituting it in (ii) 
Page 4


Edurev123 
Ordinary Differential Equations 
1. Formulation of Differential Equations 
1.1 Find the differential equations of the family of circles in the ???? -plane passing 
through (-?? ,?? ) and (?? ,?? ) . 
(2009 : 20 Marks) 
Solution: 
Approach : First use conditions to get the general equation of such a circle. Then get the 
differential equations 
General equation of circle in ???? plane is 
?? 2
+?? 2
+2???? +2???? +?? =0 (??) 
It passes through (-1,1) and (1,1) 
 
?                                                           2-2?? +2?? +?? =0?4?? =0
2+2?? +2?? +?? =0??? =-(2?? +2)
 
? General equation of circles passing through (-1,1) and (1,1) is 
?? 2
+?? 2
+2???? -(2?? +2)=0 (???? ) 
where ?? is the single parameter. 
Differentiating (ii) with respect to ?? 
2?? +2?? ????
????
+2?? ????
????
 =0
?                                                                          
????
????
 =
-?? ?? +?? ??? =
-?? ???? /????
-?? 
Putting this in (ii) 
?? 2
+?? 2
+2(
-?? ???? /????
-?? )?? -[2(
-?? ???? /????
-?? )+2]=0
 ?                      ?? 2
-?? 2
-
2????
???? /????
+
2?? ???? /????
+2?? -2=0
 ?                                                                                      
????
????
=
?? 2
-?? 2
-2?? +2
2?? (1-?? )
 
which is the required differential equation. 
 
Alternatively: We can also use equation of circle ?? 2
+(?? -1)
2
+?? (?? -1)=0 and 
proceed. 
1.2 Find the curve for which the part of the tangent cut-off by the axes is bisected 
at the point of tangency.  
(2014 : 10 Marks) 
Solution: 
Let equation of tangent line at point ' ?? ' al 
?? -?? ?? -?? =
????
????
(??) 
Now, its point of intersection with co-ordinate axes are 
?? (0,?? -
?? ????
????
);?? (?? -?? ????
????
,0) 
Given : ' ?? ' is mid point of ???? . 
                                             
So, 
?? -?? ????
????
2
=?? and 
?? -
?? ????
2
=?? 
 
?                                                           ?? =-?? ????
????
 and ?? =-
?? ????
????
 
?                                                       
????
????
=-
?? ??         
?                                                       ?????? +?????? =0         
 
Integrating, we get 
?? 2
+?? 2
=?? which the required curve.  
1.3 Find the differential equation (DE) representing all the circles in the ???? -plane. 
(2017 : 10 Marks) 
Solution: 
Method 1: General equation of circle 
(?? -?? )
2
+(?? -?? )
2
=?? 2
 
Differentiating w.r.t. ?? , 
2(?? -?? )+2(?? -?? )
????
????
 =0
 
??.?? .,                                                            (?? -?? )+(?? -?? )?? 1
=0                                                   (??) 
Differentiating again w.r.t. ?? 
1+(?? -?? )?? 2
+?? 1
2
=0 (???? ) 
Differentiating again w.r.t. ?? 
                                                     (?? -?? )?? 3
+?? 1
?? 2
+2?? 1
?? 2
=0 
i.e., 
(?? -?? )=
-3?? 1
?? 2
?? 3
 
Substituting it in (ii) 
1+(
-3?? 1
?? 2
?? 3
)?? 2
+?? 1
2
 =0
??.?? .,                                 (1+?? 1
2
)?? 3
-3?? 1
?? 2
2
 =0
??.?? .,                                                  (1+?? 1
2
)?? 3
 =3?? 1
?? 2
2
 
Method II : Using curvature-formula (?? ) . 
1.4 Find the orthogonal trajectories of the family of circles passing the points 
(?? ,?? ) and (?? ,-?? ) . 
(2020: 10 marks) 
Solution: 
Let equation of circle through (0,2) and (0,-2) be: 
?? 2
+(?? 2
-4)+???? =0, ?? : Parameter (1) 
Differentiating w.r.t. ?? , we get: 
2?? +2?? (
????
????
)+?? =0 (2) 
From (1) and (2), 
?? 2
+?? 2
-4+[-2?? -2?? (
????
????
)]?? =0
  
 
                                                         ?? 2
-?? 2
-4-2????
????
????
=0                                                               (3) 
Replace 
????
????
 by -
????
????
 in (3), we get 
?? 2
-?? 2
-4+2????
????
????
 =0
(?? 2
-4)????
?? 2
+
2???????? -?? 2
????
?? 2
 =0
? (1-
4
?? 2
)???? +? ?? (
?? 2
?? ) =0
?? +
4
?? +
?? 2
?? =0
?? 2
+?? 2
+4 =???? (required trajectory) 
 
1.5 Find the orthogonal trajectories of the family of confocal conics 
?? ?? ?? ?? +?? +
?? ?? ?? ?? +?? =?? ;?? >?? >?? 
Page 5


Edurev123 
Ordinary Differential Equations 
1. Formulation of Differential Equations 
1.1 Find the differential equations of the family of circles in the ???? -plane passing 
through (-?? ,?? ) and (?? ,?? ) . 
(2009 : 20 Marks) 
Solution: 
Approach : First use conditions to get the general equation of such a circle. Then get the 
differential equations 
General equation of circle in ???? plane is 
?? 2
+?? 2
+2???? +2???? +?? =0 (??) 
It passes through (-1,1) and (1,1) 
 
?                                                           2-2?? +2?? +?? =0?4?? =0
2+2?? +2?? +?? =0??? =-(2?? +2)
 
? General equation of circles passing through (-1,1) and (1,1) is 
?? 2
+?? 2
+2???? -(2?? +2)=0 (???? ) 
where ?? is the single parameter. 
Differentiating (ii) with respect to ?? 
2?? +2?? ????
????
+2?? ????
????
 =0
?                                                                          
????
????
 =
-?? ?? +?? ??? =
-?? ???? /????
-?? 
Putting this in (ii) 
?? 2
+?? 2
+2(
-?? ???? /????
-?? )?? -[2(
-?? ???? /????
-?? )+2]=0
 ?                      ?? 2
-?? 2
-
2????
???? /????
+
2?? ???? /????
+2?? -2=0
 ?                                                                                      
????
????
=
?? 2
-?? 2
-2?? +2
2?? (1-?? )
 
which is the required differential equation. 
 
Alternatively: We can also use equation of circle ?? 2
+(?? -1)
2
+?? (?? -1)=0 and 
proceed. 
1.2 Find the curve for which the part of the tangent cut-off by the axes is bisected 
at the point of tangency.  
(2014 : 10 Marks) 
Solution: 
Let equation of tangent line at point ' ?? ' al 
?? -?? ?? -?? =
????
????
(??) 
Now, its point of intersection with co-ordinate axes are 
?? (0,?? -
?? ????
????
);?? (?? -?? ????
????
,0) 
Given : ' ?? ' is mid point of ???? . 
                                             
So, 
?? -?? ????
????
2
=?? and 
?? -
?? ????
2
=?? 
 
?                                                           ?? =-?? ????
????
 and ?? =-
?? ????
????
 
?                                                       
????
????
=-
?? ??         
?                                                       ?????? +?????? =0         
 
Integrating, we get 
?? 2
+?? 2
=?? which the required curve.  
1.3 Find the differential equation (DE) representing all the circles in the ???? -plane. 
(2017 : 10 Marks) 
Solution: 
Method 1: General equation of circle 
(?? -?? )
2
+(?? -?? )
2
=?? 2
 
Differentiating w.r.t. ?? , 
2(?? -?? )+2(?? -?? )
????
????
 =0
 
??.?? .,                                                            (?? -?? )+(?? -?? )?? 1
=0                                                   (??) 
Differentiating again w.r.t. ?? 
1+(?? -?? )?? 2
+?? 1
2
=0 (???? ) 
Differentiating again w.r.t. ?? 
                                                     (?? -?? )?? 3
+?? 1
?? 2
+2?? 1
?? 2
=0 
i.e., 
(?? -?? )=
-3?? 1
?? 2
?? 3
 
Substituting it in (ii) 
1+(
-3?? 1
?? 2
?? 3
)?? 2
+?? 1
2
 =0
??.?? .,                                 (1+?? 1
2
)?? 3
-3?? 1
?? 2
2
 =0
??.?? .,                                                  (1+?? 1
2
)?? 3
 =3?? 1
?? 2
2
 
Method II : Using curvature-formula (?? ) . 
1.4 Find the orthogonal trajectories of the family of circles passing the points 
(?? ,?? ) and (?? ,-?? ) . 
(2020: 10 marks) 
Solution: 
Let equation of circle through (0,2) and (0,-2) be: 
?? 2
+(?? 2
-4)+???? =0, ?? : Parameter (1) 
Differentiating w.r.t. ?? , we get: 
2?? +2?? (
????
????
)+?? =0 (2) 
From (1) and (2), 
?? 2
+?? 2
-4+[-2?? -2?? (
????
????
)]?? =0
  
 
                                                         ?? 2
-?? 2
-4-2????
????
????
=0                                                               (3) 
Replace 
????
????
 by -
????
????
 in (3), we get 
?? 2
-?? 2
-4+2????
????
????
 =0
(?? 2
-4)????
?? 2
+
2???????? -?? 2
????
?? 2
 =0
? (1-
4
?? 2
)???? +? ?? (
?? 2
?? ) =0
?? +
4
?? +
?? 2
?? =0
?? 2
+?? 2
+4 =???? (required trajectory) 
 
1.5 Find the orthogonal trajectories of the family of confocal conics 
?? ?? ?? ?? +?? +
?? ?? ?? ?? +?? =?? ;?? >?? >?? 
are constants and ?? is a parameter. Show that the given family of curves is self 
orthogonal. 
[2021 : 10 marks] 
Solution: 
(i) 
Given: 
?? 2
?? 2
+?? +
?? 2
?? 2
+?? =1 
Differentiating (i) 
2?? ?? 2
+?? +
2?? ?? 2
+?? ????
????
=0 
or ?? (?? 2
+?? )+?? (?? 2
+?? )
????
????
=0 
or, 
?? (?? +?? ????
????
)=-(?? 2
?? +?? 2
?? ????
????
) 
?                                                                         ?? =-[
?? 2
?? +?? 2
?? (
????
????
)
?? +?? (
????
????
)
] 
 
?                                                            ?? 2
+?? =?? 2
-
?? 2
?? +?? 2
?? (
????
????
)
?? +?? (
????
????
)
=
(?? 2
-?? 2
)?? ?? +?? (
?? ?? ?? ????
)
 
and 
?? 2
+?? =?? 2
-
?? 2
?? +?? 2
?? (
????
????
)
?? +?? (
????
????
)
=
-(?? 2
-?? 2
)?? (
????
????
)
?? +?? (
????
????
)
 
Putting the above values of (?? 2
+?? ) and (?? 2
+?? ) in (i), 
We have, 
?? 2
[?? +?? (
????
????
)]
(?? 2
-?? 2
)?? -
?? 2
[?? +?? (
????
????
)]
(?? 2
-?? 2
)?? (
????
????
)
=1 
or [?? +?? (
????
????
)][?? -?? (
?? ?? ????
)]=?? 2
-?? 
which is the differential equation of the family (i). Replacing ???? /???? by ( -?????????? ) in (ii), 
the differential equation of the required orthogonal trajectories is 
or [?? +?? (-
????
????
)][?? -?? (-
????
????
)]=?? 2
-?? 2
 
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