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If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ?
Verified Answer
If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-...
x + 2y + 1 =0 is the required relation.
Step-by-step explanation:
The equation of the line joining the points (x₁,y₁) and (x₂,y₂) is given as
Equation of the line joining (1,-3) and (-4,2) is given by
Y+3=-(X-1) = -X+1
X+Y+2=0
∴ Equation of the line is X+Y+2=0
The point (x+2,2y-3) lies on this line, hence it satisfies the equation.
(x+2) + (2y-3) +2 =0
x + 2 + 2y -3 +2 =0
x + 2y + 1 =0.
Hence x + 2y + 1 =0 is the required relation.
This question is part of UPSC exam. View all Class 10 courses
Most Upvoted Answer
If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-...
And (5,7), we can use the slope formula to find the equation of the line and then substitute the given point to find the values of x and y.
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula:
m = (y2 - y1) / (x2 - x1)
Using the points (1, -3) and (5, 7), we can calculate the slope:
m = (7 - (-3)) / (5 - 1)
= 10 / 4
= 2.5
Now, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
Using the point (1, -3):
y - (-3) = 2.5(x - 1)
y + 3 = 2.5x - 2.5
y = 2.5x - 5.5
Now, we can substitute the given point (x+2, 2y-3) into the equation:
2y - 3 = 2.5(x + 2) - 5.5
Expanding and simplifying:
2y - 3 = 2.5x + 5 - 5.5
2y = 2.5x + 1.5
y = 1.25x + 0.75
So, the point (x+2, 2y-3) lies on the line with equation y = 1.25x + 0.75.
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula:
m = (y2 - y1) / (x2 - x1)
Using the points (1, -3) and (5, 7), we can calculate the slope:
m = (7 - (-3)) / (5 - 1)
= 10 / 4
= 2.5
Now, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope.
Using the point (1, -3):
y - (-3) = 2.5(x - 1)
y + 3 = 2.5x - 2.5
y = 2.5x - 5.5
Now, we can substitute the given point (x+2, 2y-3) into the equation:
2y - 3 = 2.5(x + 2) - 5.5
Expanding and simplifying:
2y - 3 = 2.5x + 5 - 5.5
2y = 2.5x + 1.5
y = 1.25x + 0.75
So, the point (x+2, 2y-3) lies on the line with equation y = 1.25x + 0.75.
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If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ?
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If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ?.
If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the point (x 2,2y-3) lies on the line joining the points (1,-3) &(-4,2) write a linear relation between x and y any one of u plz plz help ?.
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