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A student who gets 36% of marks, fails by 32 marks. Another candidate who gets 45% marks gets 40 marks more than are necessary for passing. Find the maximum marks.
- a)1600
- b)600
- c)400
- d)None
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A student who gets 36% of marks, fails by 32 marks. Another candidate ...
Given:
- A student who gets 36% of marks, fails by 32 marks.
- Another candidate who gets 45% marks gets 40 marks more than are necessary for passing.
To find:
- Maximum marks
Solution:
Let the maximum marks be x.
From the given data,
- The first student gets 36% marks and fails by 32 marks. So,
- Marks obtained by the first student = 36% of x
- Marks required to pass = (100% - 36%) of x = 64% of x
- According to the question, the first student fails by 32 marks. So,
- 36% of x - 64% of x = 32
- -28% of x = 32
- x = 32/(-28%) = 114.28 ≈ 114 (rounded off to the nearest integer)
- The second student gets 45% marks and gets 40 marks more than are necessary for passing. So,
- Marks obtained by the second student = 45% of x
- Marks required to pass = (100% - 45%) of x = 55% of x
- According to the question, the second student gets 40 marks more than are necessary for passing. So,
- 45% of x - 55% of x = 40
- -10% of x = 40
- x = 40/(-10%) = 400
Therefore, the maximum marks are 400.
Hence, option B is the correct answer.
- A student who gets 36% of marks, fails by 32 marks.
- Another candidate who gets 45% marks gets 40 marks more than are necessary for passing.
To find:
- Maximum marks
Solution:
Let the maximum marks be x.
From the given data,
- The first student gets 36% marks and fails by 32 marks. So,
- Marks obtained by the first student = 36% of x
- Marks required to pass = (100% - 36%) of x = 64% of x
- According to the question, the first student fails by 32 marks. So,
- 36% of x - 64% of x = 32
- -28% of x = 32
- x = 32/(-28%) = 114.28 ≈ 114 (rounded off to the nearest integer)
- The second student gets 45% marks and gets 40 marks more than are necessary for passing. So,
- Marks obtained by the second student = 45% of x
- Marks required to pass = (100% - 45%) of x = 55% of x
- According to the question, the second student gets 40 marks more than are necessary for passing. So,
- 45% of x - 55% of x = 40
- -10% of x = 40
- x = 40/(-10%) = 400
Therefore, the maximum marks are 400.
Hence, option B is the correct answer.
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Community Answer
A student who gets 36% of marks, fails by 32 marks. Another candidate ...
Let Passing marks be P
Let total marks be T
36% mark student fails by 32
==> 0.36T = P - 32 ------(1)
45% mark student passes by 40 marks extra
==> 0.45T = P + 40 ------(2)
subtracting equation (1) from (2)
0.45T - 0.36T = P+40 - (P - 32)
0.09T= P + 40 -P + 32 = 72
T=72/0.09 = 800
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A student who gets 36% of marks, fails by 32 marks. Another candidate who gets 45% marks gets 40 marks more than are necessary for passing. Find the maximum marks.a)1600b)600c)400d)Nonee)All of the aboveCorrect answer is option 'B'. Can you explain this answer?
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