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A student walks from his house at 4km/hr and reaches his school 5 mins too late, if his speed had been 5km/hr he would have reached 10 minutes too early. How far is the school from his house?
  • a)
    64   
  • b)
    5 km     
  • c)
    63   
  • d)
    65     
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A student walks from his house at 4km/hr and reaches his school 5 mins...
 
Diff of time = 15 min
5 m late 10 meals
So 1 ≡ 15m
4 ≡ 60,
So distance ≡ 1 x 5 = 5 km
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Most Upvoted Answer
A student walks from his house at 4km/hr and reaches his school 5 mins...
Given:
Speed of the student from his house to school = 4 km/hr
Speed of the student from his house to school if he had reached 10 minutes early = 5 km/hr

Let's assume the distance between the student's house and the school is 'd' km.

To find:
The value of 'd'

- - -

Distance = Speed × Time

Time taken by the student to reach the school at a speed of 4 km/hr = d/4
Time taken by the student to reach the school at a speed of 5 km/hr = d/5

According to the given information,
The student reached 5 minutes too late at a speed of 4 km/hr, so the time taken was 5 minutes more than the expected time.

Therefore, d/4 + 5/60 = d/5

Simplifying this equation,
(5d + 4)/20 = d/5

Cross-multiplying,
5d + 4 = 4d

Simplifying further,
d = 4

Hence, the distance between the student's house and the school is 4 km.
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A student walks from his house at 4km/hr and reaches his school 5 mins too late, if his speed had been 5km/hr he would have reached 10 minutes too early. How far is the school from his house?a)64b)5 km c)63 d)65 Correct answer is option 'B'. Can you explain this answer?
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