The emf per turn of a single phase 2200/220v 50 Hz transformer is appr...
A. Calculation of primary and secondary turns:
Given, emf per turn = 12V
Primary voltage (Vp) = 2200V
Secondary voltage (Vs) = 220V
Frequency (f) = 50Hz
We know that, emf per turn = 4.44fΦN
where,
Φ = maximum flux density of the core (we will calculate it in part B)
N = number of turns
For primary winding,
emf per turn = 12V
Vp = 2200V
f = 50Hz
Therefore, 12 = 4.44 x 50 x Φ x Np
Np = Vp / (4.44fΦ)
Np = 2200 / (4.44 x 50 x Φ)
For secondary winding,
emf per turn = 12V
Vs = 220V
f = 50Hz
Therefore, 12 = 4.44 x 50 x Φ x Ns
Ns = Vs / (4.44fΦ)
Ns = 220 / (4.44 x 50 x Φ)
Answer:
Number of primary turns (Np) = 141
Number of secondary turns (Ns) = 14
B. Calculation of net cross-sectional area of the core:
We know that, emf per turn = 4.44fΦN
Φ = emf per turn / (4.44fN)
Φ = 12 / (4.44 x 50 x 141) [taking primary winding values]
Φ = 0.0053 Wb
Maximum flux density of the core (Bmax) = 1.5T
Net cross-sectional area of the core (A) = Φ / Bmax
Answer:
Net cross-sectional area of the core (A) = 0.0035 m^2 or 35 cm^2
Explanation:
The given problem is solved using the formula for emf per turn and the relation between emf per turn, flux, and number of turns. In part A of the problem, the number of turns for the primary and secondary winding is calculated using the given emf per turn, voltage, and frequency. In part B of the problem, the maximum flux density of the core is calculated using the emf per turn and the number of turns calculated for the primary winding. Finally, the net cross-sectional area of the core is calculated using the maximum flux density of the core and the calculated flux.