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A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is?
Most Upvoted Answer
A metallic wire of length 2m hooked between 2 points has tension 10N. ...
**Solution:**
To find the fundamental frequency emitted by the wire on vibration, we need to use the formula for the fundamental frequency of a stretched string:
**f = (1/2L) * sqrt(T/µ)**
Where:
- f is the fundamental frequency
- L is the length of the wire
- T is the tension in the wire
- µ is the mass per unit length of the wire
Given:
- Length of the wire (L) = 2m
- Tension in the wire (T) = 10N
- Mass per unit length of the wire (µ) = 0.004 kg/m
Let's substitute these values into the formula to calculate the fundamental frequency.
**Calculations:**
The formula for the fundamental frequency of a stretched string is:
**f = (1/2L) * sqrt(T/µ)**
Substituting the given values:
f = (1/2 * 2) * sqrt(10/0.004)
Simplifying further:
f = 1 * sqrt(10/0.004)
f = sqrt(100/0.004)
f = sqrt(25000)
f ≈ 158.11 Hz
Therefore, the fundamental frequency emitted by the wire on vibration is approximately 158.11 Hz.
To find the fundamental frequency emitted by the wire on vibration, we need to use the formula for the fundamental frequency of a stretched string:
**f = (1/2L) * sqrt(T/µ)**
Where:
- f is the fundamental frequency
- L is the length of the wire
- T is the tension in the wire
- µ is the mass per unit length of the wire
Given:
- Length of the wire (L) = 2m
- Tension in the wire (T) = 10N
- Mass per unit length of the wire (µ) = 0.004 kg/m
Let's substitute these values into the formula to calculate the fundamental frequency.
**Calculations:**
The formula for the fundamental frequency of a stretched string is:
**f = (1/2L) * sqrt(T/µ)**
Substituting the given values:
f = (1/2 * 2) * sqrt(10/0.004)
Simplifying further:
f = 1 * sqrt(10/0.004)
f = sqrt(100/0.004)
f = sqrt(25000)
f ≈ 158.11 Hz
Therefore, the fundamental frequency emitted by the wire on vibration is approximately 158.11 Hz.
Community Answer
A metallic wire of length 2m hooked between 2 points has tension 10N. ...
Vibration iske kal ko pata karenge abhi jao so jao.
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A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is?
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A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is?.
A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metallic wire of length 2m hooked between 2 points has tension 10N. If mass per unit length is 0.004 kg/m, their fundamental frequency emitted by wire on vibration is?.
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