10 identical cells connected in series are needed to heat a wire of le...
Answer is option A 20..!
use (10E)^2 ÷ R=m×s× delT
and (ne)^2÷2R=m×s× delT
combine this two equation..
from that u find n^2
n^2=4×100
n=20...!!😊
10 identical cells connected in series are needed to heat a wire of le...
Calculating the Number of Cells Required
- In the given scenario, 10 identical cells connected in series are needed to heat a wire of length 1 m and radius r by 10 degrees Celsius in time t.
- We can calculate the number of cells required using the formula:
\[Q = \frac{m \cdot c \cdot \Delta T}{t}\]
- Where Q is the heat required, m is the mass of the wire, c is the specific heat capacity of the material of the wire, ΔT is the temperature change, and t is the time taken.
- As the length and radius of the wire are doubled in the second scenario, the mass of the wire will also double.
- Therefore, the heat required to heat a wire of length 2 meters and the same radius by 10 degrees Celsius in time t will be double that of the first scenario.
- Since the heat generated by each cell remains the same, the number of cells required will also double.
Calculating the Number of Cells Required for the 2-meter Wire
- Therefore, for a wire of length 2 meters and the same radius, 20 identical cells connected in series will be required to heat the wire by 10 degrees Celsius in time t.
- Hence, the correct answer is option (a) 20 cells.
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