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Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation?
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Q:A thermocouple of negligible resistance produces an e.m.f.of 40micro...
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Q:A thermocouple of negligible resistance produces an e.m.f.of 40micro...
The smallest value of temperature difference that can be detected by the system can be determined by considering the resolution of the galvanometer and the sensitivity of the thermocouple.
Given:
- e.m.f. produced by the thermocouple = 40 microvolt/C
- Resistance of the galvanometer = 10 ohm
- Sensitivity of the galvanometer = 1 microamp/div
To calculate the smallest value of temperature difference, we need to determine the smallest change in e.m.f. that can be detected by the galvanometer.
1. Sensitivity of the galvanometer:
The sensitivity of the galvanometer is given by the ratio of the change in deflection (in amps) to the change in e.m.f. (in volts).
Sensitivity = Change in deflection / Change in e.m.f.
In this case, the sensitivity is given as 1 microamp/div. Since 1 microampere is equal to 10^-6 amperes, the sensitivity can be written as:
1 microamp/div = 10^-6 A/div
2. Change in e.m.f.:
The change in e.m.f. that can be detected by the galvanometer is given by the product of the sensitivity and the change in deflection.
Change in e.m.f. = Sensitivity * Change in deflection
3. Calculating the change in deflection:
The change in deflection can be calculated by dividing the change in e.m.f. by the resistance of the galvanometer.
Change in deflection = Change in e.m.f. / Galvanometer resistance
Substituting the given values, we have:
Change in deflection = (10^-6 A/div) / 10 ohm
Change in deflection = 10^-7 A
4. Calculating the smallest value of temperature difference:
The smallest value of temperature difference that can be detected by the system is given by the change in deflection per unit change in temperature.
Smallest temperature difference = Change in deflection / Sensitivity of the thermocouple
Substituting the calculated values, we have:
Smallest temperature difference = (10^-7 A) / (40 × 10^-6 V/C)
Smallest temperature difference = 0.25°C
Therefore, the smallest value of temperature difference that can be detected by the system is 0.25°C.
Answer: a) 0.25 degree celsius
Given:
- e.m.f. produced by the thermocouple = 40 microvolt/C
- Resistance of the galvanometer = 10 ohm
- Sensitivity of the galvanometer = 1 microamp/div
To calculate the smallest value of temperature difference, we need to determine the smallest change in e.m.f. that can be detected by the galvanometer.
1. Sensitivity of the galvanometer:
The sensitivity of the galvanometer is given by the ratio of the change in deflection (in amps) to the change in e.m.f. (in volts).
Sensitivity = Change in deflection / Change in e.m.f.
In this case, the sensitivity is given as 1 microamp/div. Since 1 microampere is equal to 10^-6 amperes, the sensitivity can be written as:
1 microamp/div = 10^-6 A/div
2. Change in e.m.f.:
The change in e.m.f. that can be detected by the galvanometer is given by the product of the sensitivity and the change in deflection.
Change in e.m.f. = Sensitivity * Change in deflection
3. Calculating the change in deflection:
The change in deflection can be calculated by dividing the change in e.m.f. by the resistance of the galvanometer.
Change in deflection = Change in e.m.f. / Galvanometer resistance
Substituting the given values, we have:
Change in deflection = (10^-6 A/div) / 10 ohm
Change in deflection = 10^-7 A
4. Calculating the smallest value of temperature difference:
The smallest value of temperature difference that can be detected by the system is given by the change in deflection per unit change in temperature.
Smallest temperature difference = Change in deflection / Sensitivity of the thermocouple
Substituting the calculated values, we have:
Smallest temperature difference = (10^-7 A) / (40 × 10^-6 V/C)
Smallest temperature difference = 0.25°C
Therefore, the smallest value of temperature difference that can be detected by the system is 0.25°C.
Answer: a) 0.25 degree celsius
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Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation?
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Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation?.
Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q:A thermocouple of negligible resistance produces an e.m.f.of 40microvolt/C in the linear range of temperature.A galvanometer of resistance 10ohm whose sensitivity is 1microamp/div,is employed with the thermocouple.The smallest value of temperature difference that can be detected by the system will be? a)0.25degree celsius b)0.5 celsius c)1 celsius d)0.1celsius Give the answer and explanation?.
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