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Meiosis I is reductional division. Meiosis II is equational division due to
  • a)
    pairing of homologous chromosomes
  • b)
    crossing over
  • c)
    separation of chromatids
  • d)
    disjunction of homologous chromo
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Meiosis I is reductional division. Meiosis II is equational division d...
Explanation:

Meiosis I is the first stage of meiosis, where the homologous chromosomes pair up and exchange genetic material through crossing over. This stage is known as reductional division because it reduces the number of chromosomes in the cell by half. Meiosis II, on the other hand, is equational division because it divides the sister chromatids into two separate cells, resulting in four haploid cells with the same number of chromosomes as the parent cell.

The correct answer is option C, separation of chromatids. During meiosis II, the sister chromatids separate from each other and move towards opposite poles of the cell. This is referred to as chromatid disjunction and results in the formation of four haploid cells.

Option A, pairing of homologous chromosomes, is a characteristic of meiosis I, where homologous chromosomes pair up to form bivalents.

Option B, crossing over, also occurs during meiosis I, where homologous chromosomes exchange genetic material.

Option D, disjunction of homologous chromosomes, occurs during meiosis I, where homologous chromosomes separate from each other and move towards opposite poles of the cell.
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Meiosis I is reductional division. Meiosis II is equational division d...
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