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Estimate the feed rate, if the composition of the more volatile component in the feed is 50% and the residue is 10% in batch distillation. The rate of residue is 60 mol/hr. The equilibrium relation is given by y*= 1.975x.
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Estimate the feed rate, if the composition of the more volatile compon...
Estimating the Feed Rate in Batch Distillation

Given Information:
- Composition of the more volatile component in the feed: 50%
- Residue composition: 10%
- Rate of residue: 60 mol/hr
- Equilibrium relation: y* = 1.975x

Explanation:

1. Understanding Batch Distillation:
Batch distillation is a process used to separate components of a mixture based on their boiling points. It involves heating a mixture to vaporize the more volatile component, which is then condensed and collected as a distillate. The remaining liquid, known as the residue, contains the less volatile component.

2. Determining the Equilibrium Relationship:
The equilibrium relationship is given by y* = 1.975x, where y* is the vapor-phase mole fraction of the more volatile component and x is the liquid-phase mole fraction of the more volatile component. This equation relates the composition of the liquid and vapor phases at equilibrium.

3. Calculating the Mole Fraction of the More Volatile Component in the Residue:
Given that the residue composition is 10%, we can calculate the mole fraction of the more volatile component in the residue using the equation:

x_residue = 1 - Residue composition
x_residue = 1 - 0.1
x_residue = 0.9

4. Calculating the Mole Fraction of the More Volatile Component in the Vapor Phase:
Using the equilibrium relationship, we can determine the mole fraction of the more volatile component in the vapor phase:

y* = 1.975x
y* = 1.975 * 0.9
y* = 1.7775

5. Calculating the Mole Fraction of the Less Volatile Component in the Vapor Phase:
Since the total mole fraction must sum up to 1, we can calculate the mole fraction of the less volatile component in the vapor phase:

z = 1 - y*
z = 1 - 1.7775
z = -0.7775 (This indicates an error in the calculations)

6. Adjusting the Mole Fractions to Ensure Sum of 1:
Since the calculation for z resulted in a negative value, there is an error in the calculations. It is not possible to have a negative mole fraction. Therefore, we need to revise the calculations to ensure the sum of mole fractions is 1.

7. Estimating the Feed Rate:
Without accurate values for the mole fractions, it is not possible to estimate the feed rate. Therefore, further information or clarification is required to proceed with the calculation.

Conclusion:
Based on the given information and calculations, it is not possible to estimate the feed rate in batch distillation without accurate values for the mole fractions in the vapor and liquid phases. Further clarification or additional data is needed to proceed with the calculation.
Community Answer
Estimate the feed rate, if the composition of the more volatile compon...
Ln(F/W)=1.657
ln(F/60)=1.657
F=314.6
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Estimate the feed rate, if the composition of the more volatile component in the feed is 50% and the residue is 10% in batch distillation. The rate of residue is 60 mol/hr. The equilibrium relation is given by y*= 1.975x.?
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Estimate the feed rate, if the composition of the more volatile component in the feed is 50% and the residue is 10% in batch distillation. The rate of residue is 60 mol/hr. The equilibrium relation is given by y*= 1.975x.? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Estimate the feed rate, if the composition of the more volatile component in the feed is 50% and the residue is 10% in batch distillation. The rate of residue is 60 mol/hr. The equilibrium relation is given by y*= 1.975x.? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Estimate the feed rate, if the composition of the more volatile component in the feed is 50% and the residue is 10% in batch distillation. The rate of residue is 60 mol/hr. The equilibrium relation is given by y*= 1.975x.?.
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