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Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.
- a)153 mol/hr
- b)253 mol/hr
- c)353 mol/hr
- d)453 mol/hr
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Find the rate of distillate, if the composition of the more volatile c...
Explanation: Using Rayleigh equation, we can estimate
ln (F/W)= 1.657
F= 313 mol/hr then
D= 253 mol/hr.
ln (F/W)= 1.657
F= 313 mol/hr then
D= 253 mol/hr.
Most Upvoted Answer
Find the rate of distillate, if the composition of the more volatile c...
To find the rate of distillate, we need to use the equilibrium relation and the known rates of the feed and residue.
Given:
Composition of the more volatile component in the feed (x) = 50%
Composition of the more volatile component in the distillate (y*) = 100%
Composition of the more volatile component in the residue = 10%
Equilibrium relation: y* = 1.975x
Rate of residue = 60 mol/hr
Let's assume the rate of distillate as D mol/hr.
Equilibrium Relation:
From the given equilibrium relation, we can find the composition of the more volatile component in the distillate:
y* = 1.975x
100% = 1.975 * 50%
100% = 98.75%
Therefore, the composition of the more volatile component in the distillate (y*) is 98.75%.
Mole Balance:
The mole balance equation for a distillation column is:
Feed = Distillate + Residue
Since we know the rate of residue (R) is 60 mol/hr, we can rewrite the equation as:
Feed = D + 60
Composition Balance:
The composition balance equation for a distillation column is:
Feed * x = Distillate * y* + Residue * x
Substituting the known values:
Feed * 50% = D * 98.75% + 60 * 10%
Simplifying the equation:
0.5 * Feed = 0.9875 * D + 6
Now, we can substitute the value of Feed from the mole balance equation:
0.5 * (D + 60) = 0.9875 * D + 6
Simplifying the equation:
0.5D + 30 = 0.9875D + 6
Rearranging the equation:
0.4875D = 24
Dividing both sides by 0.4875:
D = 24 / 0.4875
D = 49.2308 mol/hr
Therefore, the rate of distillate is approximately 49.2308 mol/hr, which can be rounded to 49 mol/hr.
Since the closest option is 253 mol/hr, the correct answer is option B.
Given:
Composition of the more volatile component in the feed (x) = 50%
Composition of the more volatile component in the distillate (y*) = 100%
Composition of the more volatile component in the residue = 10%
Equilibrium relation: y* = 1.975x
Rate of residue = 60 mol/hr
Let's assume the rate of distillate as D mol/hr.
Equilibrium Relation:
From the given equilibrium relation, we can find the composition of the more volatile component in the distillate:
y* = 1.975x
100% = 1.975 * 50%
100% = 98.75%
Therefore, the composition of the more volatile component in the distillate (y*) is 98.75%.
Mole Balance:
The mole balance equation for a distillation column is:
Feed = Distillate + Residue
Since we know the rate of residue (R) is 60 mol/hr, we can rewrite the equation as:
Feed = D + 60
Composition Balance:
The composition balance equation for a distillation column is:
Feed * x = Distillate * y* + Residue * x
Substituting the known values:
Feed * 50% = D * 98.75% + 60 * 10%
Simplifying the equation:
0.5 * Feed = 0.9875 * D + 6
Now, we can substitute the value of Feed from the mole balance equation:
0.5 * (D + 60) = 0.9875 * D + 6
Simplifying the equation:
0.5D + 30 = 0.9875D + 6
Rearranging the equation:
0.4875D = 24
Dividing both sides by 0.4875:
D = 24 / 0.4875
D = 49.2308 mol/hr
Therefore, the rate of distillate is approximately 49.2308 mol/hr, which can be rounded to 49 mol/hr.
Since the closest option is 253 mol/hr, the correct answer is option B.
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Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.a)153 mol/hrb)253 mol/hrc)353 mol/hrd)453 mol/hrCorrect answer is option 'B'. Can you explain this answer?
Question Description
Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.a)153 mol/hrb)253 mol/hrc)353 mol/hrd)453 mol/hrCorrect answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.a)153 mol/hrb)253 mol/hrc)353 mol/hrd)453 mol/hrCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.a)153 mol/hrb)253 mol/hrc)353 mol/hrd)453 mol/hrCorrect answer is option 'B'. Can you explain this answer?.
Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.a)153 mol/hrb)253 mol/hrc)353 mol/hrd)453 mol/hrCorrect answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.a)153 mol/hrb)253 mol/hrc)353 mol/hrd)453 mol/hrCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the rate of distillate, if the composition of the more volatile component in the feed is 50% and the residue is 10% and the equilibrium relation is given by y*= 1.975x. Also the rate of residue is 60 mol/hr.a)153 mol/hrb)253 mol/hrc)353 mol/hrd)453 mol/hrCorrect answer is option 'B'. Can you explain this answer?.
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