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ABC is an isosceles triangle right angled at C.Prove that (AB)^2=2(AC)^2?
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ABC is an isosceles triangle right angled at C.Prove that (AB)^2=2(AC)...
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ABC is an isosceles triangle right angled at C.Prove that (AB)^2=2(AC)...
Understanding the Isosceles Right Triangle
An isosceles triangle has two sides of equal length. In triangle ABC, where angle C is a right angle, we have AC = BC.
Labeling the Triangle
- Let AC = BC = x (the lengths of the equal sides).
- Since triangle ABC is right-angled at C, AB is the hypotenuse.
Applying the Pythagorean Theorem
In any right triangle, the Pythagorean theorem states:
AB² = AC² + BC²
- Substituting the lengths:
- AB² = x² + x²
Simplifying the Equation
- This simplifies to:
- AB² = 2x²
Final Result
Thus, we conclude:
(AB)² = 2(AC)²
Conclusion
This proof demonstrates that in an isosceles triangle right-angled at C, the square of the length of the hypotenuse (AB) is twice the square of the length of either leg (AC).
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ABC is an isosceles triangle right angled at C.Prove that (AB)^2=2(AC)^2?
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