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CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆?
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CFSE for metal ion in d7 configuration in presence of strong ligand fi...
The crystal field stabilization energy (CFSE) is a measure of the stability of a metal ion in a complex with ligands. In the presence of a strong ligand field, the d-orbitals of the metal ion split into two sets of energy levels: the lower energy t2g set and the higher energy eg set. The CFSE is the energy difference between these two sets.
To determine the CFSE for a metal ion in a d7 configuration, we need to consider the number of electrons in each set and their respective energy levels. In a d7 configuration, we have 5 electrons in the t2g orbitals and 2 electrons in the eg orbitals.
The CFSE can be calculated using the formula:
CFSE = (n * P) - (m * Q)
where n is the number of electrons in the lower energy set (t2g), m is the number of electrons in the higher energy set (eg), P is the energy difference between the average energy of the t2g orbitals and the average energy of the eg orbitals, and Q is the energy difference between the highest energy t2g orbital and the lowest energy eg orbital.
In the case of a d7 configuration, n = 5, m = 2, P is the energy difference between the average energy of the t2g orbitals and the average energy of the eg orbitals, and Q is the energy difference between the highest energy t2g orbital and the lowest energy eg orbital.
To simplify the calculation, we can assume that P and Q are both equal to ∆, which represents the energy difference between the two sets of orbitals.
Substituting the values into the formula, we get:
CFSE = (5 * ∆) - (2 * ∆) = 3∆
Therefore, the CFSE for a metal ion in a d7 configuration in the presence of a strong ligand field is 3∆.
However, none of the given options (A) -0.6∆, (B) -0.8∆, (C) -1.6∆, or (D) -1.8∆ match the calculated value of 3∆. It is possible that there is an error in the options provided or in the calculation of the CFSE.
To determine the CFSE for a metal ion in a d7 configuration, we need to consider the number of electrons in each set and their respective energy levels. In a d7 configuration, we have 5 electrons in the t2g orbitals and 2 electrons in the eg orbitals.
The CFSE can be calculated using the formula:
CFSE = (n * P) - (m * Q)
where n is the number of electrons in the lower energy set (t2g), m is the number of electrons in the higher energy set (eg), P is the energy difference between the average energy of the t2g orbitals and the average energy of the eg orbitals, and Q is the energy difference between the highest energy t2g orbital and the lowest energy eg orbital.
In the case of a d7 configuration, n = 5, m = 2, P is the energy difference between the average energy of the t2g orbitals and the average energy of the eg orbitals, and Q is the energy difference between the highest energy t2g orbital and the lowest energy eg orbital.
To simplify the calculation, we can assume that P and Q are both equal to ∆, which represents the energy difference between the two sets of orbitals.
Substituting the values into the formula, we get:
CFSE = (5 * ∆) - (2 * ∆) = 3∆
Therefore, the CFSE for a metal ion in a d7 configuration in the presence of a strong ligand field is 3∆.
However, none of the given options (A) -0.6∆, (B) -0.8∆, (C) -1.6∆, or (D) -1.8∆ match the calculated value of 3∆. It is possible that there is an error in the options provided or in the calculation of the CFSE.
Community Answer
CFSE for metal ion in d7 configuration in presence of strong ligand fi...
In presence of strong field legend pairing of electron occur hence
-0.4*6+0.6*1=-2.4+0.6 =-1.8
-0.4*6+0.6*1=-2.4+0.6 =-1.8
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CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆?
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CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆?.
CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CFSE for metal ion in d7 configuration in presence of strong ligand field is A) -0.6∆ B) -0.8∆ C) -1.6∆ D) -1.8∆?.
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