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CN⁻ is a strong field ligand. It is due to the fact
  • a)
     It can accept electrons from metal species
  • b)
    It is a pseudohalide ion
  • c)
    It carries a -ve charge
  • d)
    It forms high spin complexes with metal species
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
CN is a strong field ligand. It is due to the facta)It can accept elec...
Explanation:
CN- is a strong field ligand due to the following reasons:

1. CN- is a pi-acceptor ligand: CN- has a vacant π* orbital which can accept electrons from the d-orbitals of the metal ion. This reduces the energy gap between the t2g and eg orbitals, leading to the formation of low spin complexes.

2. High electronegativity of nitrogen: Nitrogen has a high electronegativity which results in the polarization of the CN- bond towards the nitrogen atom. This creates a partial negative charge on the nitrogen atom, which further enhances the pi-accepting ability of the ligand.

3. Small size of CN-: CN- is a small ligand which can approach the metal ion closely. This increases the extent of overlap between the metal d-orbitals and the ligand orbitals, leading to stronger bonding.

4. Low-lying LUMO: CN- has a low-lying LUMO (π* orbital) which can interact strongly with the metal d-orbitals, leading to stronger bonding.

Overall, the pi-accepting ability of CN-, combined with its small size and high electronegativity, make it a strong field ligand. This results in the formation of low spin complexes with metal ions.
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Community Answer
CN is a strong field ligand. It is due to the facta)It can accept elec...
Cyanide ion is strong field ligand because it is a pseudohalide ion. Pseudohalide ions are stronger coordinating ligand & they have the ability to form sigma bond (from the pseudohalide to the metal) and π bond (from the metal to pseudohalide). So, option a is correct.
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CN is a strong field ligand. It is due to the facta)It can accept electrons from metal speciesb)It is a pseudohalide ionc)It carries a -ve charged)It forms high spin complexes with metal speciesCorrect answer is option 'A'. Can you explain this answer?
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