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The force constant of a weightless spring is 16 N/m. A body of mass 1.0 Kg suspended from it is pulled down through 5 cm and then released. The maximum kinetic energy of the system will be
  • a)
    2 x 10⁻2 J
  • b)
    4 x 10⁻2 J
  • c)
    8 x 10⁻2 J
  • d)
    16 x 10⁻2 J
Correct answer is option 'A'. Can you explain this answer?
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The force constant of a weightless spring is 16 N/m. A body of mass 1....
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The force constant of a weightless spring is 16 N/m. A body of mass 1....
Given:
Force constant, k = 16 N/m
Mass, m = 1.0 kg
Displacement, x = 5 cm = 0.05 m
Maximum kinetic energy = ?

Formula used:
The maximum kinetic energy of the system is given by the formula:
Kmax = (1/2) kx²

Calculation:
Substituting the given values in the formula, we get:
Kmax = (1/2) × 16 N/m × (0.05 m)²
Kmax = 2 J
Therefore, the maximum kinetic energy of the system is 2 J, which is option (a).

Conclusion:
When a weightless spring is stretched or compressed by a certain distance, it stores potential energy. When the spring is released, this potential energy is converted into kinetic energy. The maximum kinetic energy of the system can be calculated using the formula Kmax = (1/2) kx², where k is the force constant of the spring and x is the displacement of the mass from its equilibrium position. In this case, the maximum kinetic energy of the system is found to be 2 J.
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